Docsity
Docsity
Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity

Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan

Guidelines and tips
Guidelines and tips
Sell on Docsity
Sell on Docsity
Docsity AI
Docsity AI
Log inSign up

Prepare for your exams

Study with the several resources on Docsity

Find documents

Prepare for your exams with the study notes shared by other students like you on Docsity

Search for your university

Find the specific documents for your university's exams

Docsity AINEW

Summarize your documents, ask them questions, convert them into quizzes and concept maps

Explore questions

Clear up your doubts by reading the answers to questions asked by your fellow students

Earn points to download

Earn points by helping other students or get them with a premium plan

Share documents
download point icon20 Points

For each uploaded document

Answer questions
download point icon5 Points

For each given answer (max 1 per day)

All the ways to get free points
Get points immediately

Choose a premium plan with all the points you need

Study Opportunities

Choose your next study program

Get in touch with the best universities in the world. Search through thousands of universities and official partners

Community

Ask the community

Ask the community for help and clear up your study doubts

Free resources

Our save-the-student-ebooks!

Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors

Electrical & Computer Engineering: Homework 10 Solutions |, Assignments of Computer Science

Kent State University (KSU) - Ashtabula CampusComputer Science

Typology: Assignments

2019/2020

Uploaded on 06/15/2020

ubimaiorminorcessat
ubimaiorminorcessat 🇺🇸

4.4

(17)

225 documents

1 / 5

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
University of Florida EEL 3701 Dr. Eric M. Schwartz
Department of Electrical & Computer Engineering
Page 1/1 Homework 10 Solutions
1. Here is a short program that shows all addressing modes:
We are given a table of student's test scores where there are three scores in a semester per student.
Unfortunately, the person who entered the grades put them in the wrong order. They presently are in the
following order. Student #1 test #2/test #3/test #1, Student #2 test #2/test #3/test #1… Student #200 test
#2/test #3/test #1. We would like them to be in the following order. Student #1 test #1/test #2/test #3,
Student #2 test #1/test #2/test #3… Student #200 test #1/test #2/test #3. Assume all scores start at
1000H (SRAM).
N EQU 200
TABLE EQU $1000
NEG1 EQU %11111111 ; $FF
ORG $1800 ; temporary data area
TEMP DS.B 1
COUNT DS.B 1
ORG $0
LDAA #N
STAA COUNT
LDX #TABLE ; ptr to top of table (immediate addressing)
Loop_pt LDAB 0,X ; get test #2 score (indexed addressing)
LDAA 1,X ; get test #3 score (indexed addressing)
STAA TEMP ; save test #3 score in temp area (extended)
LDAA 2,X ; get test #1 score (indexed)
Re_order_data
STAA 0,X ; store test #1 score (indexed)
STAB 1,X ; store test #2 score (indexed)
LDAA TEMP ; get test #3 score (extended)
STAA 2,X ; store test #3 score (indexed)
Check_counter
LDAA COUNT ; retrieve count (extended)
LDAB #NEG1 ; decrement counter (immediate)
SUM_BA ; count = count -1 (inherent)
* ABA ; equivalent to SUM_BA on 68HC11/12
BEQ END ; if count = 0 then end (branch addressing)
STAA COUNT ; save count (extended)
INX ; inc ptr (inherent)
INX ; inc ptr (inherent)
INX ; inc ptr (inherent)
BNE Loop_pt ; if count != 0 then loop (branch addressing)
END BEQ END ; something to do (branch addressing)
pf3
pf4
pf5

Partial preview of the text

Download Electrical & Computer Engineering: Homework 10 Solutions | and more Assignments Computer Science in PDF only on Docsity!

Department of Electrical & Computer Engineering

Page 1/1 Homework 10 Solutions

  1. Here is a short program that shows all addressing modes:

We are given a table of student's test scores where there are three scores in a semester per student. Unfortunately, the person who entered the grades put them in the wrong order. They presently are in the following order. Student #1 test #2/test #3/test #1, Student #2 test #2/test #3/test #1… Student #200 test #2/test #3/test #1. We would like them to be in the following order. Student #1 test #1/test #2/test #3, Student #2 test #1/test #2/test #3… Student #200 test #1/test #2/test #3. Assume all scores start at 1000H (SRAM).

N EQU 200 TABLE EQU $ NEG1 EQU %11111111 ; $FF

ORG $1800 ; temporary data area TEMP DS.B 1 COUNT DS.B 1

ORG $ LDAA #N STAA COUNT LDX #TABLE ; ptr to top of table (immediate addressing) Loop_pt LDAB 0,X ; get test #2 score (indexed addressing) LDAA 1,X ; get test #3 score (indexed addressing) STAA TEMP ; save test #3 score in temp area (extended) LDAA 2,X ; get test #1 score (indexed) Re_order_data STAA 0,X ; store test #1 score (indexed) STAB 1,X ; store test #2 score (indexed) LDAA TEMP ; get test #3 score (extended) STAA 2,X ; store test #3 score (indexed) Check_counter LDAA COUNT ; retrieve count (extended) LDAB #NEG1 ; decrement counter (immediate) SUM_BA ; count = count -1 (inherent)

  • ABA ; equivalent to SUM_BA on 68HC11/ BEQ END ; if count = 0 then end (branch addressing) STAA COUNT ; save count (extended) INX ; inc ptr (inherent) INX ; inc ptr (inherent) INX ; inc ptr (inherent) BNE Loop_pt ; if count != 0 then loop (branch addressing) END BEQ END ; something to do (branch addressing)

Department of Electrical & Computer Engineering

Page 2/1 Homework 10 Solutions

  1. a) Here is the hand assembly (shown in two different formats)

This code grabs a number from Table #1 @ $1100 and a number from Table #2 @ $1110 and then computes an average value which is then stored in a Table #3, starting at $1120.

b) This process is repeated 16 ($10) decimal times. c) We must save the count in a temporary memory location because the A register is corrupted inside the loop that retrieves the data and computes the average value.

Address (Hex)

Data (Hex) Instructions 0 08 LDX^ #$ 1 00 2 11 3 02 LDAA^ #$ 4 10 5 06 STAA^ $ 6 00 7 12 8 0C LOOP:^ LDAA 0,X 9 00 A 0E LDAB^ $10,X B 10 C 15 SUM_AB D 1F SHFB_R E 12 STAB $20,X F 20 10 30 INX 11 03 LDAB^ #$FF 12 FF 13 04 LDAA^ $ 14 00 15 12 16 14 SUM_BA 17 20 BEQ^ DONE 18 1E 19 06 STAA^ $ 1A 00 1B 12 1C 21 BNE LOOP 1D 08 1E 20 DONE:^ BEQ^ DONE 1F 1E

Address (Hex)

Data (Hex) Instructions 0 08 00 11^ LDX^ #$ 3 02 10^ LDAA^ #$ 5 06 00 12^ STAA^ $ 8 0C 00^ LOOP:^ LDAA^ 0,X A 0E 10^ LDAB^ $10,X C 15 SUM_AB D 1F SHFB_R E 12 20^ STAB^ $20,X 10 30 INX 11 03 FF LDAB #$FF 13 04 00 12^ LDAA^ $ 16 14 SUM_BA 17 20 1E^ BEQ^ DONE 19 06 00 12^ STAA^ $ 1C 21 08^ BNE^ LOOP 1E 20 1E^ DONE:^ BEQ^ DONE

Department of Electrical & Computer Engineering

Page 4/1 Homework 10 Solutions

  1. Here is the program that corresponds to the machine code listed in problem #3:

ORG $ STAA $1400 ; temporarily store the A reg value COMA ; /A AND_BA ; /AB STAA $1401 ; save /AB for future use LDAA $1400 ; restore original A reg value COMB ; /B AND_BA ; A /B TAB LDAA $1401 ; retrieve /AB OR_BA ; (A/B) + (/AB)

This code performs the exclusive or of registers A and B (A xor B = A/B + /AB) and then returns this value in register A. Two temporary locations are required, 1400H and 1401H.

  1. Code to count the number of (decimal) 37’s in memory from $1000-$107F:
  • The final result is in Num37s and is also passed to the A register. If this result is zero (i.e. no 37s found),
  • the program will crash. Why?

NUM EQU $7F+1 ; = $ Neg1 EQU $FF Neg37 EQU $DB ; -37 = -$25 = -(%0010 0101) Table EQU $

  • ; -(%0010 0101) => %1101 1010 + %1 = %1101 1011 = $DB ORG $1100 ; The below program uses these temporary locations that are reserved in memory Num37s DS.B 1 ; Keep track of the number of 37s found LoopCnt DS.B 1 ; Loop counter
  • Neg37 DS.B 1 ; Holds -37 value used to test if the current data is 37 ORG $ LDAA # STAA Num37s ; Initialize the count of 37’s found to zero LDAA #NUM ; Initialize the loop counter (how many times the loop is executed) STAA LoopCnt ; ... LDX #Table ; Initialize table pointer to point to the beginning of the table TOP LDAA 0,X ; Get first table value LDAB #Neg37 ; Get - SUM_BA ; Add table value to –37. If result is zero, table value was 37. BNE SKIP_INC ; If result is not zero, the table value was not 37, so don’t increment. LDAA Num37s ; increment the number of $37s count value LDAB # SUM_AB STAB Num37s SKIP_INC LDAA LoopCnt LDAB #Neg1 ; Decrement loop counter SUM_BA ; ... BEQ DONE STAA LoopCnt INX ; Increment the data pointer BNE TOP DONE LDAA Num37s WAIT BNE WAIT BEQ WAIT

Department of Electrical & Computer Engineering

Page 5/1 Homework 10 Solutions

  1. BRA $addr

Q5:0 IR5:0 Z N D5:0 MSA MSB MSC IR_LD RW PMXY SEL PC_LD M_LD X_LD Y_LD XD YD 000001 110010 - - 110100 01 10 0000 0 1 1000 00 00 00 00 00 0 0 110100 ------ - - 000000 01 10 0000 0 1 0000 00 10 00 00 00 0 0

IR_LD

IR_5:

$addr => PCL

INC_PC