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Maxwell observed that Ampere’s circuital law cannot
be applied between the plates of the capacitor.
When the circuit is closed, conduction current flows
from the plate P of the capacitor to the other plate
through the conducting wires. Maxwell suggested that
due to time varying electric field between the plates,
an electric current, called displacement current ( I D
also flows across the space between the plates of the
capacitor.
Maxwell pointed out that in Ampere’s circuital law, the
current I should be treated as total current i.e., the sum
of the conduction current I C and displacement current
D
and modified the law as B dl. = m 0 ( IC + ID ) ∫
It is called the Ampere-Maxwell’s circuital law.
The displacement current is defined as
0
E D
d I dt
φ = ε
( )
0 . D E
t
ε = φ =
0
dt d
= ε =
t d
ε 0 = =
Gauss’s law of magnetism: It states that the net
magnetic flux crossing any closed surface is always
zero.
Mathematically, (^) ∫ B .dS^^ =^0
1. (^) ∫ E^ dA^ =^ Q /ε 0
(Gauss’s Law for electricity)
2. B^ dA^ =^0 ∫
(Gauss’s Law for magnetism)
B d E d dt
∫
(Faraday’s Law)
E c
d B d i dt
= m + m ε ∫
(Ampere - Maxwell Law)
Lorentz force: The vector sum of electric force and
magnetic force on any charged particle is called the
Lorentz force.
( v )
F q E B
The above five equations give a complete description of
all electromagnetic interactions.
Neither stationary charges nor charges in uniform motion
(steady currents) can be sources of electromagnetic waves.
The former produces only electrostatic field, while the latter
produces magnetic field that, however, do not vary with time.
It is an important result of Maxwell’s theory that accelerated
charges radiate electromagnetic waves.
The frequency of electromagnetic wave naturally
equals the frequency of oscillation of the charge. The
energy associated with the propagating wave comes at
the expense of the energy of the source-the accelerated
charge.
ELECTROMAGNETIC WAVES
Chapter
NCERT CRUX
Electromagnetic W aves^2
Electromagnetic waves travel through vacuum with the
speed of light, where
8
0 0
= = 3 ×10 m/s m ε
c
The velocity of electromagnetic wave in a medium
v = m ∈ r r
where m r = relative permeability
r = relative permitivity
The electric and magnetic fields of an electromagnetic
wave are perpendicular to each other and also
perpendicular to the direction of wave propagation.
Hence, these are transverse waves.
The instantaneous magnitudes of E
and B
in an
electromagnetic wave are related by the expression
c B
= (velocity of light)
The total instantaneous energy density u is equal to the
sum of the energy densities associated with the electric
and magnetic fields.
2 2 0 0
= + = ε + m
E B
u u u E
The components of the electric and magnetic fields of a
plane electromagnetic wave are given by:
max.
cos ( kx – w t )
max.
. cos ( kx – w t )
First we consider that the electromagnetic wave strikes the
surface at normal incidence and transports a total energy U to
the surface in a time ‘ t ’, if the surface absorbs all the incident
energy, the total momentum ‘ p ’ transported to the surface has
a magnitude
p c
= (complete absorption) ...(1)
If the surface is a perfect reflector and incidence is normal
then the momentum transported to the surface is twice that
given by Eq.(1). Therefore,
p c
= (complete reflection) ...(2)
Intensity of electromagnetic wave is given by
2 4
av
r
π
av -average power)
Type Wavelength Range
( λ )
Frequency Range
(Hz)
1. Radiowaves 0.3 to 6 × 10 2 m 10 9 - 5 × 10 5 Hz 2. Microwaves 10 - to 0.3 m 3 × 10 11 - 1 × 10 9 Hz 3. Infrared 8 × 10 - to 10 - m 4 × 10 14 - 3 × 10 11 Hz 4. Visible light 4 × 10 - to 8 × 10 - m 8 × 10 14 - 4 × 10 14 Hz 5. Ultra violet 6 × 10 - to 4 × 10 - m 5 × 10 17 - 8 × 10 14 Hz 6. X-rays 10 - to 3 × 10 - m 3 × 10 21 - 1 × 10 16 Hz 7. γ-rays 0.6 × 10 - to 10 - m 5 × 10 22 - 3 × 10 18 Hz
A P P L E T O N L A Y E R
KENNELLY HEAVISIDE
LAYER
THERMOSPHERE
MESO SPHERE
STRATO SPHERE
TROPO SPHERE
Earth Surface
OZONE LAYER
IONOSPHERE
400km80km 50km 12km