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Electronics Power Supplies, Thesis of Basic Electronics

Tshwane University of TechnologyBasic Electronics

Principle of Power Supplies, flowchart of how to connect diodes,rectifiers...... correctly

Typology: Thesis

2017/2018

Uploaded on 04/19/2018

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Module 2: Power Supplies
Engineering and the Built Environment / Electrical Engineering
Overview: Chapter 27 –Sec 27-1 to 27-7 Grobs
•Complete block diagram - Components
•Transformer –V/I/N, Rating [Part 1]
•Diode
Semiconductor Theory
Applications
Special Purpose diodes [Part 2]
Rectification
•Half-Wave [Part 3]
•Full-Wave [Part 4]
•Filtering [Part 5]
•Regulation [Part 6]
•Power Supply Design [Part 6]
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Module 2: Power Supplies

Overview: Chapter 27 – Sec 27-1 to 27- 7 Grobs

  • Complete block diagram - Components
  • Transformer – V/I/N, Rating [Part 1]
  • Diode  Semiconductor Theory  Applications  Special Purpose diodes [Part 2]  Rectification - Half-Wave [Part 3] - Full-Wave [Part 4]
  • Filtering [Part 5]
  • Regulation [Part 6]
  • Power Supply Design [Part 6]

Part 1

The Process

Part 1 Overview of the process The basic function of a DC power supply is to convert an AC voltage to a smooth DC voltage.

Part 1 The Transformer Application of mutual inductance.  Transfer of power from primary to secondary.  Primary is coupled to secondary by magnetic link, not electrically.  PP = PS ( Assuming loss free)  Turn ratio = primary turns to secondary turns (N (^) P:N (^) S)  Voltage ratio is proportional to turn ratio (VS/VP = N (^) S/N (^) P)  Step-down – Secondary has less turns than Primary IP referred to as Line Current IS referred to as Load current

Part 1 The Transformer Examples: Solutions

  1. A power transformer has 900 turns for Np and 600 turns Ns. Find: a) turn ratio. [1,5:1] b) Vs if Vp is 120 V. [80 V]
  2. A transformer has these specification: Np = 100, Ns = 5. Same as Question 1 [20:1] [6 V]
  3. A 1:6 transformer has 720 V across a 7200Ω in the secondary. Find Is and Ip. [0, 1 A; 0, 6 V]
  4. Spec: Vp = 120V; Vs = 25 V, VA(power rating = 125 VA). Explain what this spec mean. [Max Is=5 A; Max Ip=1,04 A]

Important Dates –

Refer to semester course plan