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Electrostatic Activity, Exercises of Physics

Polytechnic University of the Philippines (PUP)Physics

Lesson 10: Electrostatics Assessment Instruction; Show your complete and neat solution. Identify your final answer in the solution.

Typology: Exercises

2020/2021

Uploaded on 06/15/2021

NABC03
NABC03 ๐Ÿ‡ต๐Ÿ‡ญ

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bg1
F=๐‘˜๐‘„1๐‘„2
๐‘Ÿ2
F = 1 ๐‘‘๐‘ฆ๐‘›๐‘’ ๐‘๐‘š2
๐‘ ๐‘ก๐‘Ž๐‘ก๐ถ2
(3x10โˆ’9)(12x10โˆ’9)
3๐‘๐‘š2= 4x10โˆ’18 ๐‘‘๐‘ฆ๐‘›๐‘’๐‘ 
๐‘„ = ๐‘„1+ ๐‘„2
2= 7.5x10โˆ’9 ๐‘ ๐‘ก๐‘Ž๐‘ก๐ถ
F = ๐‘˜๐‘„1๐‘„2
๐‘Ÿ2โ‡’ 1 ๐‘‘๐‘ฆ๐‘›๐‘’ ๐‘๐‘š2
๐‘ ๐‘ก๐‘Ž๐‘ก๐ถ2
(7.5x10โˆ’9)(7.5x10โˆ’9)
3๐‘๐‘š2= 6.25x10โˆ’18 ๐‘‘๐‘ฆ๐‘›๐‘’๐‘ 
F2 ๐‘ก๐‘œ โˆ’8 =๐‘˜๐‘„1๐‘„2
๐‘Ÿ2โ‡’(9x109)(2x10โˆ’6)(โˆ’8x10โˆ’6)
(10x10โˆ’2)2= โˆ’14.4 ๐‘
F2 ๐‘ก๐‘œ โˆ’8๐‘ฅ = โˆ’14.4 ๐‘ cos 60 = โˆ’7.2๐‘ฅ
F2 ๐‘ก๐‘œ โˆ’8๐‘ฆ = โˆ’14.4 ๐‘ sin 60 = โˆ’12.5๐‘ฆ
F3 ๐‘ก๐‘œ โˆ’8 =๐‘˜๐‘„1๐‘„2
๐‘Ÿ2โ‡’(9x109)(3x10โˆ’6)(โˆ’8x10โˆ’6)
(10x10โˆ’2)2= โˆ’21.6 ๐‘
F3 ๐‘ก๐‘œ โˆ’8๐‘ฅ = โˆ’21.6 ๐‘ cos 120 =10.8๐‘ฅ
F3 ๐‘ก๐‘œ โˆ’8๐‘ฆ = โˆ’21.6 ๐‘ sin 120 = โˆ’18.7๐‘ฆ
๐น = F2 ๐‘ก๐‘œ โˆ’8 + F3 ๐‘ก๐‘œ โˆ’8
๐น = โˆ’7.2๐‘ฅ โˆ’ 12.5๐‘ฆ + 10.8๐‘ฅ โˆ’ 18.7๐‘ฆ = 3.6๐‘ฅ โˆ’ 31.2๐‘ฆ
๐น = โˆš3.62+(โˆ’31.2)2= 31.4 ๐‘
pf2

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F =

1

2

2

F = 1

2

2

3 x 10

โˆ’ 9

12 x 10

โˆ’ 9

2

= 4 x 10

โˆ’ 18

1

2

= 7. 5 x 10

โˆ’ 9

F =

1

2

2

2

2

  1. 5 x 10

โˆ’ 9

  1. 5 x 10

โˆ’ 9

2

= 6. 25 x 10

โˆ’ 18

F

2 ๐‘ก๐‘œ โˆ’ 8

1

2

2

9 x 10

9

2 x 10

โˆ’ 6

โˆ’ 8 x 10

โˆ’ 6

( 10 x 10

โˆ’ 2

2

F

2 ๐‘ก๐‘œ โˆ’ 8

๐‘ฅ = โˆ’ 14. 4 ๐‘ cos 60 = โˆ’ 7. 2 ๐‘ฅ

F

2 ๐‘ก๐‘œ โˆ’ 8

๐‘ฆ = โˆ’ 14. 4 ๐‘ sin 60 = โˆ’ 12. 5 ๐‘ฆ

F

3 ๐‘ก๐‘œ โˆ’ 8

1

2

2

( 9 x 10

9

)( 3 x 10

โˆ’ 6

)(โˆ’ 8 x 10

โˆ’ 6

10 x 10

โˆ’ 2

2

F

3 ๐‘ก๐‘œ โˆ’ 8

๐‘ฅ = โˆ’ 21. 6 ๐‘ cos 120 = 10. 8 ๐‘ฅ

F

3 ๐‘ก๐‘œ โˆ’ 8

๐‘ฆ = โˆ’ 21. 6 ๐‘ sin 120 = โˆ’ 18. 7 ๐‘ฆ

๐น = F

2 ๐‘ก๐‘œ โˆ’ 8

+ F

3 ๐‘ก๐‘œ โˆ’ 8

2

2

F

1

1

2

2

9 x 10

9

โˆ’ 6

โˆ’ 8

2

F

2

1

2

2

( 9 x 10

9

โˆ’ 6

โˆ’ 8

2

F = F

1

+ F

2

F

๐‘Ž

F

1

1

2

2

9 x 10

9

โˆ’ 6

โˆ’ 8

2

F

2

1

2

2

9 x 10

9

โˆ’ 6

โˆ’ 8

2

F = F

1

+ F

2

F

๐‘

F = ๐‘š๐‘”

F =

1

2

2

1

2

2

2

2

1

2

2

1

2

2

2

2

= 0. 49 statC