Element Nodal Displacement - Advanced Mechanics of Solids - Lecture Notes, Study notes of Applied Solid Mechanics

The main points in these lecture notes are:Element Nodal Displacement, Finite Element Method, Element Level, Element Interpolation Function, Element Displacement Field, Element Strain Field, Element Stress Field, Element Strain Energy, Element Nodal Force

Typology: Study notes

2012/2013

Uploaded on 05/07/2013

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EN0175 11 / 30/ 06
Finite element method (continued)
Summary of essential concepts:
FEM analysis begins with calculations on the element level.
Element
1#2#
3#
Element nodal displacement:
=
3#
2
3#
1
2#
2
2#
1
1#
2
1#
1
u
u
u
u
u
u
uel
Element interpolation function:
()
21
1,xxN ,
(
)
21
2,xxN ,
(
)
21
3,xxN
Element displacement field:
el
u
NNN
NNN
u
u
=
321
321
2
1
000
000
Element strain field:
1
Docsity.com
pf3
pf4
pf5
pf8
pf9

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Finite element method (continued)

Summary of essential concepts:

FEM analysis begins with calculations on the element level.

Element

Element nodal displacement:

3

2

3

1

2

2

2

1

1

2

1

1

u

u

u

u

u

u

u (^) el

Element interpolation function:

1

N x , x , ( 1 2 )

2

N x , x , ( 1 2 )

3 N x , x

Element displacement field:

u el N N N

N N N

u

u ⎥ ⎦

1 2 3

1 2 3

2

1

0 0 0

Element strain field:

1

uel Bu el

x

N

x

N

x

N

x

N

x

N

x

N

x

N

x

N

x

N

x

N

x

N

x

N

=

=

=

1

3

2

3

1

2

2

2

1

1

2

1

2

3

2

2

2

1

1

3

1

2

1

1

12

22

11

0 0 0

0 0 0

2 ε

ε

ε

ε

Element stress field:

D DBu el

E = =

− −

=

= ε

ε

ε

ε

ν

ν

ν

ν σ

σ

σ

σ

12

22

11

2

12

22

11

2 2

1 0 0

1 0

1 0

1

Element strain energy:

el el

T U (^) el (^) V ij ij V uelK u el (^) 2

1 d 2

1 = (^) ∫ σε =

K A B D B

T el = el

Element nodal force:

V f^ i^ ui V A tiui S Felu^ el el el

∫ ∫

d d

After the element quantities are calculated, the next step is to assemble the global stiffness matrix.

Global strain energy:

U U u K u u K u

T

elements

el el

T el elements

el 2

1

2

1

61

3

2

3

1

2

2

2

1

1

2

1

1

×

u

u

u

u

u

u

u (^) el Æ

( )

( )

( )

( )

( )

( )

2 1

3 2

3 1

2 2

2 1

1 2

1 1

×

n

u

u

u

u

u

u

u

M

( K el ) 6 × 6 Æ K 2 n × 2 n

Element connectivity

( # 1 ,# 2 ,# 3 ) ⇒( a , b , c )

α^ ( 1 , 2 , 3 , 4 , 5 , 6 )^ ⇒ z α(^2 a − 1 , 2 a , 2 b − 1 , 2 b , 2 c − 1 , 2 c )

2

( )

( )

( )

( )

( )

( )

( )

( )

( )

( )

( ) 2 2 , (^231)

1 2 1 , 2

42

2 2

32

2 1

12

1 1

2

1

2 2

2 1

1 2

1 1

2 , 1 2 , 3 2 , 2

31 33 3 , 2

11 13 1 , 2

×

− ⎥

n n

n

n

n

n

n

n n n n

n

n

F K
F K
F K
F K
F K

u

u

u

u

u

u

K K K
K K K
K K K
M^ M
L L L
M M M M M M M
M M M M M M M
M M M M M M
L L L
L L
L L L

The modified K then remains symmetric, as shown above.

Post-processing

Extract nodal displacement using element connectivity: uuel

ε= Bu el

σ= DBu el

Isoparametric elements:

The actual nodal coordinates can be mapped to a normalized domain ξ ⊂ [− 1 , 1 ], which is

particularly convenient because displacements and positions for different elements can be

interpolated using the same shape functions.

1 # 2

x

− 1 0 1

ξ

1 1 # 2 2

u x = u N + u N

1 1 # 2 2

x = x N + x N

1 1 ,^1

N ξ , ( )

2 0 ,^1
N ξ

Interpolation functions:

N = , ( )

N =

4

2D linear triangular element:

a b

c

ξ 1

ξ 2

3 1 2

2 1 2

1

u u N ξ ,ξ u N ξ,ξ u N ξ, ξ

v v a v b v c = + +

3 1 2

2 1 2

1

x x N ξ ,ξ x N ξ,ξ x N ξ, ξ

v v a v b v c = + +

Interpolation functions:

1

N ξ = ξ, ( ) 2

2

N ξ = ξ , ( ) 12

3

N ξ = 1 −ξ − ξ

2D quadratic triangular element:

ξ 1

3

Interpolation functions:

1

N = 2 ξ − 1 ξ

2

N = 2 ξ − 1 ξ

3

N = 21 −ξ −ξ − 1 1 −ξ − ξ

1 2

4

N = 4 ξ ξ

2 (^12 )

5

N = 4 ξ 1 −ξ − ξ

5

Interpolation functions:

1 1 1 1 8

N = −ξ −ξ − ξ ), ( 1 )( 2 )( 3

2 1 1 1 8

N = +ξ −ξ − ξ)

3 1 1 1 8

N = +ξ +ξ − ξ), ( 1 )( 2 )( 3

4 1 1 1 8

N = −ξ +ξ − ξ )

5 1 1 1 8

N = −ξ −ξ + ξ), ( 1 )( 2 )( 3

6 1 1 1 8

N = +ξ −ξ + ξ )

7 1 1 1 8

N = +ξ +ξ + ξ ) , ( 1 )( 2 )( 3

8 1 1 1 8

N = −ξ +ξ + ξ)

Element stiffness matrix:

1 2 3

1

1

1

1

1

1

d ξ^1 ,ξ^2 ,ξ^3 ξ^1 ,ξ^2 ,ξ^3 J dξdξd ξ x

N

x

N
V C

x

N

x

N
K C

l

b

j

a

V ijkl l

b

j

a

ijkl

el aibk ∫ (^) el ∫ ∫ ∫− − − (^) ∂

j

J xi

det is the Jacobian associated with the mapping, which can be computed by

( ( ) )

a i j

a a i

a

j j

i x

N

N x

x

ξ

ξ ξ ξ ∂

− 1

l

j

l

a

j

l

l

a

j

a (^) x N

x

N

x

N

ξ ξ

ξ

ξ

Calculate: (^) jl

l

j A

x

Then:

− 1

jl j

l A x

ξ

Integration scheme for isoparametric elements:

Gaussian integration:

∫− ∑

1

1 1

d

NI

I

f ξ ξ WI f ξ I

ξ I : Gaussian integration points

7

W I : weighting coefficients

Gaussian integration ensures that polynomials of order of ( 2 N I − 1 )are exactly integrated.

For N I = 1 , ξ 1 = 0 , W 1 = 2.

f ( ξ )

1

1

f ξd ξ 2 f 0

Check:

f ( ) ξ = C 0 + C 1 ξ

1

1 0 1 0

C C ξ d ξ 2 C 2 f ( ) 0

For N (^) I = 2 , 3

ξ 2 = , W 1 = W 2 = 1.

d

1

1

f ξ ξ f f

Check:

3 3

2

f ξ = C 0 + C 1 ξ+ C 2 ξ + C ξ

d d 2

1

1 0 2

1

1

2

f ξ ξ C 0 C 2 ξ ξ C C f f
For N I = 3 , ξ 1 =− 0. 775 , ξ 2 = 0 , ξ 3 = 0. 775 , W 1 = W 3 = 0. 556 , W 2 = 0. 889.

( )d 0. 556 ( 0. 775 ) 0. 889 ( ) 0 0. 556 ( 0. 775 )

1

1

∫ f^ = f − + f + f

ξ ξ

8