Engineering Circuit Analysis: Chapter 1 Solved Problems, Study Guides, Projects, Research of Engineering

11th chapter 1 engineering circuit analysis

Typology: Study Guides, Projects, Research

2018/2019

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Irwin, Basic Engineering Circuit Analysis, 11/E 1
Chapter 01: Basic Concepts Problem 1.1
SOLUTION:
1.1 If the current in an electric conductor is 2.4 A, how many coulombs of charge pass any point in a 30-second interval?
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Download Engineering Circuit Analysis: Chapter 1 Solved Problems and more Study Guides, Projects, Research Engineering in PDF only on Docsity!

SOLUTION:

1.1 If the current in an electric conductor is 2.4 A, how many coulombs of charge pass any point in a 30-second interval?

SOLUTION:

1.2 Determine the time interval required for a 12-A battery charger to deliver 4800 C.

SOLUTION:

1.4 If a 12-V battery delivers 100 J in 5 s, find (a) the amount of charge delivered and (b) the current produced.

SOLUTION:

1.5 The current in a conductor is 1.5 A. How many coulombs of charge pass any point in a time interval of 1.5 minutes?

SOLUTION:

1.7 Determine the number of coulombs of charge produced by a 12-A battery charger in an hour.

SOLUTION:

1.8 Five coulombs of charge pass through the element in Fig. P1.8 from point A to point B. If the energy absorbed by the element is 120 J, determine the voltage across the element.

B

A

Ȃ

V 1

Figure P1.

SOLUTION:

1.10 The charge entering the positive terminal of an element is q ( t ) = − 30 e −^4 t^ mC. If the voltage across the element

is 120 e −^2 t^ V, determine the energy delivered to the element in the time interval 0 < t < 50 ms.

SOLUTION:

1.11 The charge entering the positive terminal of an element is given by the expression q ( t ) = − 12 e −^2 t^ mC. The

power delivered to the element is p ( t ) = 2.4 e −^3 t^ W. Compute the current in the element, the voltage across the

element, and the energy delivered to the element in the time interval 0 < t < 100 ms.

SOLUTION:

1.13 The power absorbed by the BOX in Fig. P1.13 is 2 e −^2 t^ W. Calculate the amount of charge that enters the BOX

between 0.1 and 0.4 seconds.

4 e Ȃ t^ V Ȃ BOX

Figure P1.

SOLUTION:

1.14 The power absorbed by the BOX in Fig. P1.14 is 0.1 e −^4 t^ W. Calculate the energy absorbed by the BOX during

this same time interval.

10 e Ȃ^2 t^ V Ȃ BOX

Figure P1.

Problem 1.15 Chapter 01: Basic Concepts

SOLUTION:

1.16 The charge that enters the BOX in Fig. P1.16 is shown in the graph below. Calculate and sketch the current flowing into and the power absorbed by the BOX between 0 and 10 milliseconds.

12 V Ȃ BOX

i ( t ) (^) q ( t ) (mC)

t (ms)

1

2

3

Ȃ 2

Ȃ 3

Ȃ 1

1 2 3 4

5 6 7 8 9 10

Figure P1.

SOLUTION:

1.17 The energy absorbed by the BOX in Fig. P1.17 is given below. Calculate and sketch the current flowing into the BOX. Also calculate the charge which enters the BOX between 0 and 12 seconds.

10 V Ȃ BOX

i ( t ) (^) w ( t ) (J)

t (s)

5

Ȃ2.

1 2 3 4 5

6 7 8 9

10 11

12

Figure P1.