Engineering course on microcontrollers, Exercises of Electrical and Electronics Engineering

Engineering course on microcontrollers

Typology: Exercises

2024/2025

Uploaded on 02/13/2025

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ECE-205 : Dynamical Systems
Homework #6
Due : Friday October 22 at noon
1) In this problem we will derive some useful properties of Laplace transforms starting from the basic
relationship
0
( ) ( ) st
X s x t e dt
a) Let’s assume
()xt
is a causal signal (it is zero for
0t
). We can then write
( ) ( ) ( )x t x t u t
to emphasize the
fact that
()xt
is zero before time zero. If there is a delay in the signal and it starts at time
0
t
, then we can write
the signal as
0 0 0
) ( ) )( (x t tx t t u t t
to emphasize the fact that the signal is zero before time
0
t
.
Using the definition of the Laplace transform and a simple change of variable in the integral, show that
0
00
( ) ( )) ( st
x t t u t t X s e
b) Using the results from part a, determine the inverse Laplace transform of
3
( 2)( 4
() )
s
e
ss
Xs

Answer:
c) Starting from the definition of the Laplace transform, show that
()
() dX s
tx t ds

.
d) Using the result from part c, and the transform pair
1
( ) ( )() atutt X sa
e sx

, and some simple
calculus, show that
2 3
342
1
( ) , ( ) , ( )
( ) (
26
) ( )
at at at
te u t t e u t t e u t
s a s a s a
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ECE-205 : Dynamical Systems

Homework #

Due : Friday October 22 at noon

1) In this problem we will derive some useful properties of Laplace transforms starting from the basic

relationship

0

st X s x t e dt

  

a) Let’s assume x t( )is a causal signal (it is zero for t  0 ). We can then write x t( ) x t u t( ) ( )to emphasize the

fact that x t( )is zero before time zero. If there is a delay in the signal and it starts at time t 0 , then we can write

the signal as x t( t 0 )  x t(  t 0 ) u t( t 0 )to emphasize the fact that the signal is zero before time t 0.

Using the definition of the Laplace transform and a simple change of variable in the integral, show that

0 ( 0 ) ( 0 ) ( )

st x t t u t t X s e

   

b) Using the results from part a , determine the inverse Laplace transform of

3

s e

s s

X s

Answer:

2( 3) 4( 3) (

t t x t e e ut

         

c) Starting from the definition of the Laplace transform, show that  

dX s tx t ds

d) Using the result from part c, and the transform pair

at t u t X s a

x e s

    

, and some simple

calculus, show that

2 3 2 3 4

at at at te u t t e u t t e u t s a s a s a

        

2) For the following circuits, determine the transfer function and the corresponding impulse responses.

Scrambled Answers:

2 / 1 / (^1) /^1 ( ) ( ) ( ), ( ) ( ) ( ), () ( ), ( ) [ ( ) ] ( )

a b b a a b

R R t b tR^ L^ t R C^ t RaC CR R b a a a

R

t e u t t e u t h t e u t h t t e L R C R C R C

h t R  h t   u t

    (^)        

3) For the following impulse responses and inputs, compute the system output using transfer functions.

a) ( ) ( ), () ( )

t h t e u t x t ut

   b)

2 ( ) ( ), ( ) ()

t

h t e u t x t  t

   c)

2( 1) 2 ( ) ( 1), ( ) ()

t t h t e u t x t e u t

     

d) ( ) ( ), ( ) ( 1) ( 1)

t h t e u t x t t u t

     e)

2 ( ) ( ), ( ) ( ) ( 1)

t h t e u t x t ut ut

    

f)

2( 1) 3 ( ) ( 1), ( ) ( )

t t h t e u t x t te u t

     

Scrambled Answers :

2 2( 1) 2( 1)

2 ( 1)

2( 1) 3( 1) 3( 1)

( ) ( ), ( ) [ 1 ( 1) ] ( 1),

( ) [ ( 1) ] ( 1)

t t t t

t t

t t t

y t e u t e u t y t e u t y t t e u t

y t e u t y t t e u t

y t e e t e u t

     

  

     