Download Docsity.com: A Comprehensive Collection of Academic Resources and more Exercises Dynamics in PDF only on Docsity! 6/49 is = O24Am
Fe
M=IZ Nem ka = 615 m
SN ma = Zo kg
Taz % Fm
N = 6,
N heme
FE
Ma =Iakg: I2- F(24)= 20(0.15)7 x 0)
G DMs =Te%q: Fo) = Ia(ou)? eX (2)
Tangential acceltrotions match + Va%at tga
&
224 %q = O18 %
Solution of Ey. Q-@i(F= Ieee nN
Xp V1 vedis*(cw)
Xg = 25.5 radjs*(cew)
(3)
it
ib
Ml
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6/50 } the awgular acceleration of the welded
unit depends Yeon Ty and te Momunit Cdve
+o tre wbegnts ) Soout 0. Neither quantity
depends upon the acientuton 8 of tne sbb.
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6/53 | % 24,2 nF", 272 prrr 2a"
ree . FT T= prtw*
i 4
T Tr
rae Le=mrw', 276i 2 = prdé (ra)
Ado ar « pride
T=prw*
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AGBIN 6
8 mma T_g= ¥A)(0350)~
= 0.1633 key m™
Iq = $28)"
+ Le 4 O.ss)t+ 4 (0.774 0.n5*) |
o[54 |? S08 AA
o
Ma = @.2\ kgm
DEMaz= Tar! Ma —25(9.81)(0.350 cas 48°)
-442))Co. 700 +9.115) ms 48° = 6214)
Ma = 107.8 Nem
FE Mp = Tae |
Mg — 4(9.81) (07S ong45*)= 0.1633 (4)
Mg = 5.51 New
ALBIN
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6/55 Zhe Lx | mgr cos @ = 2mr®a
re. at 2 cose
er
a) 8
OMDE AGE, Ly dev = 2 feos de
o er
2 o .
ws 9, sin@
Vie ,
mg é , , 7 628 e G3 g
Q* - B? cose
-, @ .
EAE rte G,~ 1g 9108 svar (8 sir)
G2 2mg sin @
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6/68 =|
YAO
iL 300
From ~Vable DA, ram 1 “
. 125
_ 1
Lez mrs tami’ o @)——em
= a4 * - yd
# loo (ozs +03) le 100 (4.81) N
= LIAL gsm? :
Ly = Lgt rad® = LI + too (ozo 0150) 8.43 ky
TLMo = Look : Gai (0.120 + O50) = B43 0
A = Bis rod fst
ZL Fe=mG,: F-98) = 100 (-0.27)(31.4)
Fe is20.N
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ZLMo= Lows mypcas 6 = Fanti
= Zt eos
(udu = fade
a 8 ag
foda= fFtewe ae ) w= Sy sms
° 0
Zaye mans On- mgsin ® =mbu>
39.
On = mMaSmOB4+ mb ZF sind = Zregsin @
ER, = ma, i mg oso - O% = mb HF case
O+ = F my cos 8
OF | On + Oo. = amg C0870 + loosin70
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6fo0 ov Ry
b= tan 'S2 24.2° sh
~ ~
|O.9m
o~.
zy =i, em? 4 B
= 6 a00)#)+300 (240.97) 2" gle
= /643 kg+m* / 300(4.8/) N
2
zm, =L,u: JOOS 1)(2) = 1843 ef, of 3.19 rad/s*
LE, = mPa: 3000481) cos 24,2°~ Ry = 300 M2*20,F*) 3.14,
Rpt Fh2N
ZF, am Fo": R, -300(9.81) sin 24,2°=300(0), B= /208 N
R2f5 027+ /ZOP* =/3H4IN
eee
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_ 2 2 2) /F =
6/63 Lge + (amt + md’) FB a0.5)
3
- Agim
&, EM a= La 3
2 ous 0.25 |10.25 o 8 17 2
a mom | 8981)(C, 50 40,25) =F (BOS)
O
n eo =4 Veoh ee = 20.8 rad/s?
Le .
| 82.87) LF = imia,
£ nN é t
ZONG.BI)-R = 8(0.25)(Z0.8)
+6&(0,50)(20.8)
&,? 523 N
24,= Zima, , Rae 8(0.25)4 ey $(0.50)4 = F.OA
B= 5E5 "+ FEB" = 70).3.)
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6/64. -mFawt A= 2
/ w= 20 rads EE mra, Ans /0(0.500)( 27)
n é =/°74
ti a -S0mm 2M,= mad; o/ooT= 197.4(0.500)
“ aA T fooOmm T= FIN
Ab a * we Eke mioe 20; A= 987M
500 mm S —_ *
An As Vi/97.4)?+(987)%= 1007 NW
or Az/,.007 AN
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(@) w:=0, f= f= mhafe
) A=VA, eae er HA = om
(¢) F20 tohen Yew or we c/s
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6/68 |_ m= 3000 kg Am
= \jG*+2% = 632m \
<
\
E = TZ Boos) 474 127) \n [°™
= 40 000 Kegrmm = LEK em _
Az ° ae N\A Eo
@= ton = BAS yg #\elGm
Emr @
| a)n (Fa),
la a B
fF EMeg = Lah + mar :
ATa = 40 000« + 3000 (6,a2«) (6.32)
x= 6.05 red|s*
BoP, = man = 0: (Fen ~ 2000 cos 18,43° =o
(Fa\n = [897 N
ZRL= may: Zoe sin 18,43°+ Fe \e > 3000 (¢.32)(0.05)
(Fae = Sle N
Fg = {189774 3 = (1924 N
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6/69 2M = Lok | mgd sin a = gmb7a
- 39 .-
ott
sin 6
te eo
[ fwdw=fKde w*: 28(-cos6)
é o oO ’ &z o
w= H(/-cos 6)
mg £454, | WG 6080 ~As mS"
a
LF = ing ces ~m$ $1-cos a)
‘a . = rng [cos 0 ~ $(- cos 0))] = 29/5056 -3)
CF2Mma, mg sind -f= mS 44.) = :
é 6, NG SINE ~F2 ms 5g 179, Fs Pesine
(@)snps at O=30° Me blrngs PI 8AIOF 0/98
29(5 cos 30°-3)
(3) Ne slp: N20 when tos8= 9/5 os 537°
3 docsity.com
‘ef70| ae
T=t+ mr %
tp 50(3\*+ 50(0.5)*
50 Kem =
i]
Ht
TM, =zL, x! S0(4.81\(0.5 cose) = 50 x
dw o 6
x= 4405 cos8 = 8 Ge Jada = [4.965 cos6u8
° Q
wo = 4.8 sine
ee mB, + 50 (ai) ces @- N = 50(0.5)4.105 ens)
SL F,= may: Fo 50(48i) sine = 500.5) (4.8) sin 6)
SVipgeng otcury when F=O.30N /
2 ey: O.3N= 75(4.si)sind j Divide
1 ey: N= BR (4.31) Cos6 obtain @=8.53°
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ZFY= ma, | aso .
Ay = Wy | Pe may yay? w
‘| GAMg= Iu: Pe = tinvta
Gy as a
A
b .
P
4 Zon
= 24 + Ose = Zt KkLole + YK Mx Cae)
- mi+ tee Ris Si]
= Es -i|
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docsity.com 6/75 LM,= Lo; Fr= mk, a =f,
wh
Ae
“re \o de emey ; —Fsm(-%)
42Flm
ze ~-y St %t om
A Aap) s rey (a, FONG
, (Bap ) = of, (Cag) = -re dep ad
4 ied
ea
=. ff’. :
vo 2,2 - ohh -(E-w)
& docsity.com
6/78 + / J mg = $b, Te dbmr*
Se Bs = O15, y= 9-18
~x Le =3s°
et
N yng = 8 ib
- : s
RF = may! -F + 8sin3e= ary a 0)
ER, = 9 + N= Flog So =O @
= & g /6\2
EMg= Ea: F(R) =o daa) (3)
Assume rolling with ne slip : = Bx 4)
Solutin of (-@): F2i333 b a= i073
N= 6.93 Ib «=ans fed
sect
Finax= Wg N* 9.15(6-93) = L037 1b <F =D Slips
Fe AN = 0, 10(6.93) = 0,693 Ib a
From Regs. (4 @): GEIS Ped, X= INS Sect
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6/79 100,91) N
ZF = 0: N- 98.1 cos 60° =O gn
¥ .
N=49.0 Ni Jka =
F = ty N= 0,30(49.0) = 14.72 N 2-13 m
ZF, = ma: 1004, 2/)sin 60°-/4,72= 104, , ew
ay = 7.02 mfs* fsa?
eae /
é
x
2M, =L,0: 14.72 (0.2) = 1010.18 *)d,
a= 9.08 rad/s*
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680 Ae
Eq : - .
2M,= Lo tmad: mgrsine = mh ok + med)
ols BESO | F.8110.2)sinb0°
kp tre 0.180*+ 0.27
= 23.4 rad/s? aay
pF le=8e
ZF ema, ! ngsinO-F2mra, x m=lO kg
F = 981 sin b60°-/0(0.2)23.4) mg 2 10(0,81)296.1 M
= BRON r2 Om, k= O10 m
Zh, =O: N-mgcos b= 0,
N= 96.1 tos 60°= 49.0 N
E = .
Ms 257 7 9.775 =(As) rnin
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6/83
25 (4.81) N k= O15 m
wan 4 Bg = Oly Py = 0.08
30N is
i
—
+ U}-—-%
F N .
ZR, =0 & N= 25(9.8) = 245 N
Eye ma, 2 30°F = 250 0)
Mg = Te: 30(0.015)- F (0.2) = 25 (0.175) "x (2)
Assome rolling blrth fe Ship | @a-re (3)
Seiution oF E5s. Q)-8) ‘(a= 0.425 mIs*
A= - RAZ wad |s®
F= 1238 N
Fina PgN= 01 (245) = REEN OF (assumption 0X)
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G|84- | 25 (4.81) N k= 011s m
oz m 50N
F N .
ZAy=o! N-2Z5(1.B1)+ 50 sin Be? =o
N= 220 N
ZFy = WO, + 50 cos3- F = 25a Q)
ZMg = Te: 50(0.018)- F(s.2) = 25(0.15)"& @
Assume elling with no slip + 85 -ra (3)
Solution oF Q) -B) :(@= 0.556 mis" a =-2.78 rad)s>
FRR2UAN
Fray? MsN= 0.1 (220)= 22.0 N< Fé Slips FEA NE (TORN
From Eqs. (I)¢ @): a= hOZ7 mjs™ = 0.295 radfs®
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6/85 2N [= 0075 m
25(781) N
wage {alm bs Oy fe= 298
\3
+L. |
N ZAFY=O+ N-25(1.8I) + Bo sin T=
N= 217.N
ZAR Ma, 30 cos To°- F = 25a D
Mg = Tm + 90(0.098)~ F (4.2) © 25(0078)"x @)
Assure falling WK ne Shp F QE TK (3)
Sotwkion of Eq. W-@): (a= —o.02z24 mst
& = O.NZ) ved fs?
Foe los2n
Fina” HsN= 0.1 (ai7) = 2\.7>F Cassumption ox)
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79% = mba tmaltm
3
Solve get AFG, 055
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6/89 Jy aye Vp >
——_ t 27 athe
co = =e;
6: 4 FOSS ape
L/2 “/2
a mg A
ha
7?
Se
La 2 zp
“= —). eet az
iM, La tna, Ad -mgh a7 7b wk +s e
a
as Bye
z
r
_ +t aut
Az ng (3 3H)
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6/90
Ay
S—> A
% wee MP = 5 (0.4)27= ROM
0.4m
cht. = —_alls
= OR IDT e174, = Sl4)=20 N
t %
; pe “> Fy 2h Sfo.8)%= 0,
00M nary || Toes ph Slot 0.2670
= 5(0.4) ot
= 20k
IM,=LAd + FmAd, 0 =0.2670 + 2.00 (0.4)- 200. 4)
X= 750 rad/s?
‘Apt 20- 2.01750) = FN
ZRema,) A,~ S12 B)= 8, AY SRIN
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Pac = Yag = 2k rads
Age = KAgetk reys’
49.81) N
Gg. = %&* Cra, A Lag, = 4Kx [6740.17 5)e0s 45%
+ CoT= 0078) sin45%y [- 2* [OT r0.r7S)eas4ses
+ (0.1- 0.178 sin 45%j T= 3.9L + 0.990; mst
SMe = Ta + Emad: Mg- 407.81) (0.195 sin 4s*)=
“2 4) (0.38) “AY 4 400.999) (0.175 cas 45°)
— 4(3.46) (175 sia45?) » Me=3.55 Nem Cow
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6/94
he -6
“a
2M, = La + Emad
O= mks rmtak -ma, 4
2 tg GCOSO
—-""@ . ~
“ A R= mb,
Al mosin@=m(a,-2a0 6088
AN Tu 7 m(5 )
oi oar Eliminate & & get
<7 |t mg :
mg ma, ||, 2% ax 298 _
“2 1-2 cos*6
2
N Alternativesole Hon !
\ Pr C may 6 used @3 @ moment
LC
Center fhus eliminating reference
fo Ayan given ome epuea hon
in &
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6/95 tyg20; (25), + (Ge) =(4a),,* (an), + (ay),
(y),,= 127) 2 0.4 ofs® (25),° 28". yt foray”
— flog, z
(@q) =0.114) = 0,4 m/s* a lw
‘ (2g) = 4 ra/s*
4 (Ag, \=O.2
y Meo?
“{dg) = 0,2 m/s?
0.89.81) WM a 7
a aa * et 23 20.667
IM, Lx + Peg, A s
(0.38 ~0.8[4.810.05)K = fo.s(o. ay (- 24) -
4 (0.156) x 0.8(0.4j 40.94)
O38 = 4177 - 0.0/6 + 0.048
B= BC#4,03 VW (tension)
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