Understanding Couples and Force Couple Systems: Moments and Equivalent Systems - Prof. Ahm, Study notes of Statistics

A lesson from engr210 - spring 2005 course taught by ahmed abdel-rahim. It explains the concept of couples, which are two parallel forces with the same magnitude but opposite directions separated by a perpendicular distance. The moment of a couple, the effect of moving a force, and finding an equivalent force-couple system. It also includes an example of finding the equivalent resultant force and couple moment acting at a point.

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Pre 2010

Uploaded on 08/19/2009

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Engr210 – Spring 2005 Instructor: Ahmed Abdel-Rahim
Lesson # 11: Couples/Force Couple Systems Page 1 of 2
Today’s Objectives:
1. Define a couple and determine
the moment of a couple
2. Determine the effect of moving a
force.
3. Find an equivalent force-couple
system for a system of forces
and couples.
Concept
A couple is two parallel forces with the same
magnitude but opposite in direction separated
by a perpendicular distance d.
MO = F d (using a scalar analysis)
MO = r x F (using a vector analysis).
Here r is any position vector from the line of
action of –F to the line of action of F.
The net external effect of a couple is that the
net force equals zero and the magnitude of
the net moment equals F d
Since the moment of a couple depends only
on the distance between the forces, the
moment of a couple is a free vector. It can be
moved anywhere on the body and have the
same external effect on the body.
Moments due to couples can be added using
the same rules as adding any vectors.
AN EQUIVALENT SYSTEM
Two force and couple systems are called
equivalent systems if they have the same
external effect on the body.
MOVING A FORCE ON ITS LINE OF
ACTION
Moving a force from A to O, when both
points are on the vectors’ line of action,
does not change the external effect.
Hence, a force vector is called a sliding
vector.
MOVING A FORCE OFF ITS LINE OF
ACTION
Moving a force from point A to O (as shown
above) requires creating an additional
couple moment.
Since this new couple moment is a “free”
vector, it can be applied at any point P on
the body.
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Engr210 – Spring 2005 Instructor: Ahmed Abdel-Rahim Lesson # 11: Couples/Force Couple Systems Page 1 of 2

Today’s Objectives:

1. Define a couple and determine **the moment of a couple

  1. Determine the effect of moving a** **force.
  2. Find an equivalent force-couple** system for a system of forces and couples.

Concept

A couple is two parallel forces with the same magnitude but opposite in direction separated by a perpendicular distance d.

M O = F d (using a scalar analysis) M O = r x F (using a vector analysis).

Here r is any position vector from the line of action of –F to the line of action of F.

The net external effect of a couple is that the net force equals zero and the magnitude of the net moment equals F d

Since the moment of a couple depends only on the distance between the forces, the moment of a couple is a free vector. It can be moved anywhere on the body and have the same external effect on the body.

Moments due to couples can be added using the same rules as adding any vectors.

AN EQUIVALENT SYSTEM

Two force and couple systems are called equivalent systems if they have the same external effect on the body.

MOVING A FORCE ON ITS LINE OF

ACTION

Moving a force from A to O, when both points are on the vectors’ line of action, does not change the external effect. Hence, a force vector is called a sliding vector.

MOVING A FORCE OFF ITS LINE OF

ACTION

Moving a force from point A to O (as shown above) requires creating an additional couple moment. Since this new couple moment is a “free” vector, it can be applied at any point P on the body.

Engr210 – Spring 2005 Instructor: Ahmed Abdel-Rahim Lesson # 11: Couples/Force Couple Systems Page 2 of 2

Finding the resultant of a force and couple system

Reducing a force-moment to a single force

If FR and MRO are perpendicular to each other, then the system can be further reduced to a single force, FR , by simply moving FR from O to P.

Example

Find: The equivalent resultant force and couple moment acting at A.

Solution Plan

  1. Sum all the x and y components of the forces to find FRA.
  2. Find and sum all the moments resulting from moving each force to A and add them to the 500 lb - ft free moment to find the resultant MRA.
  • → ΣFx = (4/5) 150 lb + 50 lb sin 30° = 145 lb

  • ↑ ΣFy = (3/5) 150 lb + 50 lb cos 30° = 133.3 lb

FRA = (145 2 + 133.3 2)1/2 = 197 lb and θ = tan-1 (133.3/145) = 42.6 °

  • MRA = { (4/5)(150)(2) – 50 cos30° (3) + 50 sin30° (6) + 500 } = 760 lb·ft