Entropy and Thermodynamics Tutorial, Schemes and Mind Maps of Chemistry

A tutorial on entropy and thermodynamics, covering topics such as the relationship between entropy and spontaneity of reactions, calculating entropy changes for various chemical reactions, and determining equilibrium constants using gibbs free energy. The tutorial includes several practice problems and solutions, allowing students to apply the concepts learned. It is a valuable resource for students studying thermodynamics, physical chemistry, or related fields, as it reinforces key principles and provides opportunities for problem-solving and understanding the fundamental aspects of entropy and its role in chemical processes.

Typology: Schemes and Mind Maps

2021/2022

Uploaded on 07/09/2022

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Entropy Tutorial
1. Which one of the following reactions would you expect to have the lowest S?
A.CH4(g) + 2O2(g) CO2(g) + 2H2O(g)
B.C2H2(g) + 5/2O2(g) 2CO2(g) + H2O(g)
C.C2H4(g) + O2(g) 2CO2(g) + 2H2O(g)
D.C2H6(g) + 7/2O2(g) 2CO2(g) + 3H2O(g)
Lower s means product must have lower mole compare to reactants
2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk
metal from further corrosion.
4Al(s) + 3O2(g) 2Al2O3(s)
Using the thermodynamic data provided below, calculate S for this reaction.
A.182.3 J/K·mol
B.131.5 J/K·mol
C.–182.3 J/K·mol
D.–626.2 J/K·mol
3. Sulfur can be separated from lead in the mineral galena, PbS(s), by "roasting" the ore in the
presence of oxygen as shown in the following reaction:
2PbS(s) + 3O2(g) 2PbO(s) + 2SO2(g)
Calculate S for this reaction using the thermodynamic data provided below.
A.–410 J/K·mol
B.–161.5 J/K·mol
C.–47.7 J/K·mol
D.21.8 J/K·mol
4. With respect to the system only, a reaction with H < 0 and S > 0 is predicted to be:
A.Spontaneous at all temperatures
B.Spontaneous at high temperatures only
C.Spontaneous at low temperatures only
D.Nonspontaneous at all temperatures
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Entropy Tutorial

  1. Which one of the following reactions would you expect to have the lowest S? A. CH 4 ( g ) + 2O 2 ( g )  CO 2 ( g ) + 2H 2 O( g ) B. C 2 H 2 ( g ) + 5 / 2 O 2 ( g )  2CO 2 ( g ) + H 2 O( g ) C. C 2 H 4 ( g ) + O 2 ( g )  2CO 2 ( g ) + 2H 2 O( g ) D. C 2 H 6 ( g ) + 7 / 2 O 2 ( g )  2CO 2 ( g ) + 3H 2 O( g ) Lower s means product must have lower mole compare to reactants
  2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion. 4Al( s ) + 3O 2 ( g )  2Al 2 O 3 ( s ) Using the thermodynamic data provided below, calculate S for this reaction. A. 182.3 J/K·mol B. 131.5 J/K·mol C. –182.3 J/K·mol D. –626.2 J/K·mol
  3. Sulfur can be separated from lead in the mineral galena, PbS( s ), by "roasting" the ore in the presence of oxygen as shown in the following reaction: 2PbS( s ) + 3O 2 ( g )  2PbO( s ) + 2SO 2 ( g ) Calculate S for this reaction using the thermodynamic data provided below. A. –410 J/K·mol B. –161.5 J/K·mol C. –47.7 J/K·mol D. 21.8 J/K·mol
  4. With respect to the system only, a reaction with H < 0 and S > 0 is predicted to be: A. Spontaneous at all temperatures B. Spontaneous at high temperatures only C. Spontaneous at low temperatures only D. Nonspontaneous at all temperatures
  1. Calculate G for the reaction 3NO 2 (g) + H 2 O(l)  2HNO 3 (l) + NO(g). A. 8.7 kJ/mol B. 192 kJ/mol C. –414 kJ/mol D. –192 kJ/mol
  2. Ozone (O 3 ) in the atmosphere can react with nitric oxide (NO): O 3 (g) + NO(g)  NO 2 (g) + O 2 (g). Calculate the G for this reaction at 25C. (H = –199 kJ/mol, S = –4.1 J/K·mol) A. 1020 kJ/mol B. –1.22  103 kJ/mol C. 2.00  103 kJ/mol D. –198 kJ/mol
  3. Hydrogen peroxide (H 2 O 2 ) decomposes according to the equation H 2 O 2 (l)  H 2 O(l) + 1 / 2 O 2 (g). Calculate Kp for this reaction at 25C. (H = –98.2 kJ/mol, S = 70.1 J/K·mol) A. 1.3  10 – B. 20. C. 3.46  1017 D. 7.5  1020
  4. Determine the equilibrium constant (Kp) at 25C for the reaction CO(g) + H 2 O(g) CO 2 (g) + H 2 (g). G = –28.5 kJ/mol A. 2.9  10 – B. 1.0  10 – C. 1. D. 1.0  105 1b2d3b4a5a6d7d8d