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Main points of this exam paper are: Evaluate, Fourth Order, Linear Equation, General Solution, DeNite Integral, Laplace Transform, Function, Expressions, Linear Equation, Second Order
Typology: Exams
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Examination II
November 13, 2012
FORM A
Name: Student Number: Section:
This exam has 12 questions for a total of 100 points. In order to obtain full credit for partial credit problems, all work must be shown. For other problems, points might be deducted, at the sole discretion of the instructor, for an answer not supported by a reasonable amount of work. The point value for each question is in parentheses to the right of the question number. A table of Laplace transforms is attached as the last page of the exam.
Please turn off and put away your cell phone.
You may not use a calculator on this exam.
through 8:
9:
10:
11:
12:
Total:
Do not write in this box.
y(4)^ − 2 y(3)^ + y′′^ = 0.
What is its general solution?
(a) y(t) = C 1 + C 2 t + C 3 et^ + C 4 tet
(b) y(t) = C 1 et^ + C 2 e−t^ + C 3 cos t + C 4 sin t
(c) y(t) = C 1 + C 2 t + C 3 cos t + C 4 sin t
(d) y(t) = C 1 + C 2 t + C 3 e−t^ + C 4 te−t
0
e−(s+4)tt^2 dt.
(a)
(s − 4)^3
(b) e−s^
(s − 4)^3
(c) e−s^
(s + 4)^3
(d)
(s + 4)^3
(a)
x′ 1 = x 2 x′ 2 = − 7 x 1 + 4x 2 + 10t^3
(b)
x′ 1 = x 2 x′ 2 = 7 x 1 − 4 x 2 + 10t^3
(c)
x′ 1 = x 2 x′ 2 = − 4 x 1 + 7x 2 + 10t^3
(d)
x′ 1 = x 2 x′ 2 = 4 x 1 − 7 x 2 + 10t^3
− 2 − 5 i 4
. What is the system’s real-valued general solution?
(a) x(t) = C 1 e^3 t
−2 cos t − 5 sin t 4 cos t
5 cos t − 2 sin t 4 sin t
(b) x(t) = C 1 e^3 t
−2 cos t + 5 sin t 4 cos t
−5 cos t − 2 sin t 4 sin t
(c) x(t) = C 1 e^3 t
−2 cos t + 5 sin t 4 sin t
−5 cos t − 2 sin t −4 cos t
(d) x(t) = C 1 e^3 t
−2 cos t − 5 sin t 4 sin t
5 cos t − 2 sin t −4 cos t
2 β 5 − 5 β^2
x.
(a) 0
(b) 2
(c) − 2 , 2
(d) 0, − 2
x′^ = xy + 2y y′^ = xy − 4 x
Linearize this system about (− 2 , 4) to determine the critical point as a(n)
(a) unstable saddle point.
(b) asymptotically stable spiral point.
(c) unstable node.
(d) asymptotically stable proper node.
(a) (7 points) F (s) =
2 s + 5 s^2 (s − 2)
(b) (8 points) F (s) = e−^4 s^
s s^2 + 8s + 20 − 4 e−^7 s
(a) (16 points) Use the Laplace transform to solve the following initial value problem.
y′′^ + 3y′^ + 2y = u 6 (t) − 2 δ(t − 1), y(0) = 0, y′(0) = 2.
(b) (2 points) Evaluate y(ln 2).