EVALUATING LOGARITHMIC FUNCTIONS, Quizzes of Algebra

Solutions to nine logarithmic function problems. Each problem involves transforming the logarithmic equation to exponential form and solving for the variable. The problems vary in difficulty and involve different bases. The solutions are presented step-by-step and rounded to three decimal places. The document can be useful for students studying logarithmic functions and exponential equations.

Typology: Quizzes

2021/2022

Available from 01/03/2023

LesterDave
LesterDave ๐Ÿ‡ต๐Ÿ‡ญ

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EVALUATING LOGARITHMIC FUNCTIONS
1. log711๐‘ฅ=43
Solution:
743 =11๐‘ฅ Transform to exponential form
log743 = log11๐‘ฅ Apply log to both sides
43log7
log11 =๐‘ฅlog11
log11 Property of log function
๐Ÿ‘๐Ÿ’.๐Ÿ–๐Ÿ—๐Ÿ“ = ๐’™ Final answer (Rounded to three decimal places)
2. 7log12๐‘ฅ=21
Solution:
7log12๐‘ฅ
7=21
7 Simplify
log12๐‘ฅ= 3
103=12๐‘ฅ Transform to exponential form
log103= log12๐‘ฅ Apply log.
3log10
log12 =๐‘ฅlog12
log12 Property of log
๐Ÿ. ๐Ÿ•๐Ÿ–๐ŸŽ = ๐’™ Final answer (Rounded to three decimal places)
3. log716807
Solution:
log716807 = ๐‘ฅ Add variable x
7๐‘ฅ= 16807 Transform to exponential form
7๐‘ฅ= 75 16807 = (7)(7)(7)(7)(7)= 75
๐’™ = ๐Ÿ“ Final Answer
4. log51
625 = ๐‘ฅ
Solution:
5๐‘ฅ=1
625 Exponential Form
5๐‘ฅ=1
54 625 =(5)(5)(5)(5)= 54
5๐‘ฅ= 5โˆ’4
๐’™ = โˆ’๐Ÿ’ Final Answer
5. log4(2)(8)(1024)= ๐‘ฅ
Solution:
4๐‘ฅ=16(1024) Exponential form
4๐‘ฅ= 42(45) Rewrite as base 4
4๐‘ฅ= 42+5 Simplify
4๐‘ฅ= 47 Simplify
๐’™ = ๐Ÿ• Final Answer
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EVALUATING LOGARITHMIC FUNCTIONS

  1. log 7

๐‘ฅ

Solution:

43

๐‘ฅ

Transform to exponential form

log 7

43

= log 11

๐‘ฅ

Apply log to both sides

43 log 7

log 11

๐‘ฅ log 11

log 11

Property of log function

๐Ÿ‘๐Ÿ’. ๐Ÿ–๐Ÿ—๐Ÿ“ = ๐’™ Final answer (Rounded to three decimal places)

  1. 7 log 12

๐‘ฅ

Solution:

7 log 12

๐‘ฅ

7

21

7

Simplify

log 12

๐‘ฅ

3

๐‘ฅ

Transform to exponential form

log 10

3

= log 12

๐‘ฅ

Apply log.

3 log 10

log 12

๐‘ฅ log 12

log 12

Property of log

๐Ÿ. ๐Ÿ•๐Ÿ–๐ŸŽ = ๐’™ Final answer (Rounded to three decimal places)

  1. log 7

Solution:

log

7

16807 = ๐‘ฅ Add variable x

๐‘ฅ

= 16807 Transform to exponential form

๐‘ฅ

5

5

๐’™ = ๐Ÿ“ Final Answer

  1. log 5

1

625

Solution:

๐‘ฅ

1

625

Exponential Form

๐‘ฅ

1

5

4

4

๐‘ฅ

โˆ’ 4

๐’™ = โˆ’๐Ÿ’ Final Answer

  1. log 4

Solution:

๐‘ฅ

= 16 ( 1024 ) Exponential form

๐‘ฅ

2

5

) Rewrite as base 4

๐‘ฅ

2 + 5

Simplify

๐‘ฅ

7

Simplify

๐’™ = ๐Ÿ• Final Answer

  1. log( 1000 โˆš

3

Solution:

๐‘ฅ

3

Exponential Form

๐‘ฅ

3

1

3 ) Write as base 10

๐‘ฅ

3 +

1

3 Simplify

๐‘ฅ

10

3 Simplify

๐Ÿ๐ŸŽ

๐Ÿ‘

Final Answer

  1. log 3

4

7

Solution:

๐‘ฅ

4

7

Exponential Form

๐‘ฅ

7

4 Simplify

๐‘ฅ

3 (

7

4

)

Write as Base 3

๐‘ฅ

21

4 Simplify

๐Ÿ๐Ÿ

๐Ÿ’

Final Answer

  1. log ๐‘ฅ

1

๐‘ฅ

10

Solution:

๐‘ฅ

1

๐‘ฅ

10

Exponential Form

๐‘ฅ

โˆ’ 10

Simplify

๐’™ = โˆ’๐Ÿ๐ŸŽ Final Answer

  1. log 2

( 2 )( 4

3

)( 8

5

)

( 32 )( 16

2

)

Solution:

๐‘ฅ

( 2 )( 4

3

)( 8

5

)

( 32 )( 16

2

)

Exponential Form

๐‘ฅ

2

1

( 2

6

)( 2

15

)

2

5

( 2

8

)

Write as base 2

๐‘ฅ

2

( 1 + 6 + 15 )

2

( 5 + 8 )

Simplify

๐‘ฅ

2

22

2

13

Simplify

๐‘ฅ

9

Simplify

๐’™ = ๐Ÿ— Final Answer