Exam 1 Solution - System Dynamics | ME 3017, Exams of Dynamics

Material Type: Exam; Professor: Sadegh; Class: System Dynamics; Subject: Mechanical Engineering; University: Georgia Institute of Technology-Main Campus; Term: Spring 2012;

Typology: Exams

2013/2014

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George W. Woodruff School of Mechanical Engineering
Georgia Institute of Technology
ME3015 Test I Solutions
Spring 2012
NAME__________ Key____________
________________________________________________________________________
Total Score:_____________/50
Please read this first:
1. The test is closed-book and closed notes. A Laplace Transform table and some useful
formulas are given on the last page.
2. There are ten (10) questions/problems on this test. Read all of the problems carefully and
start from the one that is easiest for you.
3. Budget your time -- total exam time is 75 minutes.
4. Make sure you have a clear presentation for the solutions. No answer without justification
is accepted.
5. Sign the pledge of honor below -- any act of academic dishonesty may result in your
failing the course.
6. Do not forget to write down your NAME.
I pledge on my honor that the work presented in this test is entirely my own; I have
neither given nor received any inappropriate aid in preparation of this test.
Signature ________________________________
STOP HERE
Do not turn the page until further instructions
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Download Exam 1 Solution - System Dynamics | ME 3017 and more Exams Dynamics in PDF only on Docsity!

George W. Woodruff School of Mechanical Engineering Georgia Institute of Technology ME3015 Test I Solutions Spring 2012

NAME__________ Key ____________


Total Score:_____________/

Please read this first:

  1. The test is closed-book and closed notes. A Laplace Transform table and some useful

formulas are given on the last page.

  1. There are ten (10) questions/problems on this test. Read all of the problems carefully and

start from the one that is easiest for you.

  1. Budget your time -- total exam time is 75 minutes.
  2. Make sure you have a clear presentation for the solutions. No answer without justification

is accepted.

  1. Sign the pledge of honor below -- any act of academic dishonesty may result in your

failing the course.

  1. Do not forget to write down your NAME.

I pledge on my honor that the work presented in this test is entirely my own; I have

neither given nor received any inappropriate aid in preparation of this test.

Signature ________________________________

STOP HERE

Do not turn the page until further instructions

M


1) In

an

a) y=

c) y =

2) Id

Input

x, Tw

Ts ,Ti,

3) W

f

f(t)=

F(s)=(

0

t

L

5) F

a) F

b) F

c) F

6) F

b ,

2

2

s

sY s

1 5 Test I Solu


ndicate wheth nd linear (L) =u 2 S_ ___

= τ τ

t u d 0

( ) _

dentify 3 inpu

Outpu

wi , Q (^) i , Q (^) f

Qw T (^) wo, Ω

T (^) s (can

What is the is

t

t t f t

(t)t-1(t-1)(t- (1-e -s )/s 2

The Laplac

τ

F

f dt

ind the invers

s

s F s ( 1

s

s F s

s

s F s ( 2

ind Y(s)=L (

, and c are co

as bY s

s sy y

utions


her the follow or nonlinear N__

D_ ___

uts and 3 outp

ut

f , Qe

Ωs n also be an outp

the Laplace t

? (3 pts.)

ce transform

2

s s

e

s

F s

s

se Laplace tra

s s

s 2

1 )( 2 )

s s +

s

2 2 ( 2 )

(y(t)) given th

nstant coeffic

s

c s a

y asY

N


wing input-out (N): (4 pts) b) y 

L_ d) y 

puts of the ho

ut )

transform of

of function f (

s

[

− 2 e f

t

L

ansform of ea

s 2

2 2

s

f s

2 2

hat y ( t ) satisfi

cients. (5 pts.)

2

s

s as c

s y b

NAME_____ _


tput relationsh

y  + 3 y + 5 y =

y  + sin y = u

ot water furna

( t ) is given by

f ( t ) ] = F ( s + 2

ach of the foll

t f ( t ) 2 e

− ⇒ =

2 2 s

f ( t )=( 1 − 2 t

es  y  + ay + b

)

2

s

Y s

s

bYs

______ Key __


hips are Dyna

= u D_

_D_____ __

ace system sho

y ( ) 2

s

e Fs

2

( 2

− +

s

e

s

owing functio

t t e

− 2 −

f ( t ) e

t ⇒ =

t t e

2 )

by = c , y ( 0 )=

2

2

s as b

s as c



amic (D) or S

L_

N__

own below: (

s

. Determin

)

f ( t )= 1 (

ons: (6 pts)

(cos 3 t +sin

= 1 , y ( 0 )= 0



tatic (S)

3 pts)

ne (3 pts)

( t − 1 )sin( t

3 t )

, where a ,

M3015 Test I Solutions NAME_____ ______ Key ___________________


10) The differential equation of motion for the rack and roller system shown in the figure may be

expressed as (^) meff x  (^) + kx = f. Assuming that each roller has radius r and moment of inertia J ,

and rolls without slipping about its fixed center, find m (^) eff in terms of m , J , and r. (6 pts)

The equations of motion of mass m and pinion J are given by

θ= − θ

J Fr kr

mx F F

p

p

 

Where F (^) p is the contact force between each pinion gear and mass m. Using that x=rθ

yields

x kx F r

J

m

meff

⎟ +^ =

2

x

m

f k

J

J

r

r