Algorithm for Projectile Motion: Calculating Velocity, Position, and Acceleration, Exams of Vector Analysis

The steps to calculate the velocity, position, and acceleration of a projectile using the initial conditions and integration techniques. It covers the calculation of range, maximum height, and impact speed, as well as the tangential and normal components of acceleration and curvature. The document also includes notes on units and dimensions.

Typology: Exams

Pre 2010

Uploaded on 02/13/2009

koofers-user-75d
koofers-user-75d 🇺🇸

9 documents

1 / 1

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Algorithm for Projectile Problems:
Always start with
a
ØHtL= < 0, -g>
, where
g=32 ft
ÅÅÅÅÅÅÅÅÅÅÅ
sec2
or
9.8 m
ÅÅÅÅÅÅÅÅÅÅÅ
sec2
(or g(t) if gravity is not constant, e.g. on planet Z)
1. Write down the "Initial Conditions" for
v
ØHtL
and
r
ØHtL
, (i.e
v
ØH0L= < vo cosq,vo sinq >
where q is in rad and
r
ØH0L= < 0, height off the ground >
)
2. Integrate
to find
v
ØHtL
using the initial condition
v
ØH0L= < vo cosq,vo sinq >
3. Integrate
v
ØHtL
to get
r
ØHtL
using the initial condition
r
ØH0L= < 0, height off the ground >
4. Answer the actual question, frequently solving for t first
Note:
To find range,
xHtL
: set the height,
y
component of
r
ØHtL
, equal to zero, solve for t and insert it in the x component of
r
ØHtL
To find maximum height: set
vyHtL
, the
y
component of
v
ØHtL
, equal to zero, solve for t and insert it in the y component of
r
ØHtL
To find its speed at impact: set the height
yHtL
equal to zero to find the time of impact, insert this t in both components of
v
ØHtL
, and compute
»»v
ØHtL»»
Note: Check meters vs. feet. Check radians vs. degrees
Arc Length:
Arc Length =
Ÿt1
t2»»v
ØHtL»»t
Tangental and Normal Components of Acceleration:
aTHtL=d»»v
ØHtL»»
ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ
dt
aNHtL= k I»»v
ØHtL»»M2
or
aNHtL=
»»v
ØHtL x a
ØHtL»»
ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ
»»v
ØHtL»»
or
aNHtL
=
$%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
I»»a
ØHtL»»M2-aT2
Curvature:
k =
aN
ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ
I»»v
ØHtL»»M2
or
k =
»»v
ØHtL x a
ØHtL»»
ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ
I»»v
ØHtL»»M3
k = 0 Ø straight line
k = const. Ø k =
1
ÅÅÅÅÅ
R
(
acircular =v2
ÅÅÅÅÅÅÅ
R
)
Think about:
a
Ø=aTT
`+aN N
`
=d»»v
ØHtL»»
ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ
dt T
`+ k I»»v
ØHtL»»M2 N
`
T
`
= const.
v
Ø
so
N
`
in perpendicular to
v
Ø
Exam III Formula Sheet.nb 1

Partial preview of the text

Download Algorithm for Projectile Motion: Calculating Velocity, Position, and Acceleration and more Exams Vector Analysis in PDF only on Docsity!

Algorithm for Projectile Problems:

Always start with a

Ø

H t L = < 0, - g > , where g = 32

ft

ÅÅÅÅÅÅÅÅÅÅÅ sec

2 or^ 9.^

m

ÅÅÅÅÅÅÅÅÅÅÅ sec

2 (or g(t)^ if^ gravity^ is^ not constant,^ e.g.^ on^ planet^ Z)

  1. Write down the "Initial Conditions" for v

Ø

H t L and r

Ø

H t L, (i.e v

Ø

H 0 L = < v o

cosq, v o

sinq > where q is in rad and

r

Ø

H 0 L = < 0 , height off the ground >)

  1. Integrate a

Ø

H t L to find v

Ø

H t L using the initial condition v

Ø

H 0 L = < vo cosq, vo sinq >

  1. Integrate v

Ø

H t L to get r

Ø

H t L using the initial condition r

Ø

H 0 L = < 0, height off the ground >

  1. Answer the actual question, frequently solving for t first

Note:

To find range , x H t L: set the height, y component of r

Ø

H t L, equal to zero, solve for t and insert it in the x component of r

Ø

H t L

To find maximum height : set v y

H t L, the y component of v

Ø

H t L, equal to zero, solve for t and insert it in the y component of r

Ø

H t L

To find its speed at impact : set the height y H t L equal to zero to find the time of impact, insert this t in both components of

v

Ø

H t L, and compute »» v

Ø

H t L »»

Note: Check meters vs. feet. Check radians vs. degrees

Arc Length:

Arc Length = Ÿ t 1

t 2

»» v

Ø

H t L »» „ t

Tangental and Normal Components of Acceleration:

aT H t L =

d »» v

Ø

H t L»»

ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ

dt

a N

H t L = k I »» v

Ø

H t L »»M

2

or a N

H t L =

»» v

Ø

H t L x a

Ø

H t L»»

ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ

»» v

Ø

H t L»»

or a N

H t L=

I »» a

Ø

H t L »»M

2

  • a T

2

Curvature:

k =

a

N

ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ

I»» v

Ø

H t L»»M

2

or k =

»» v

Ø

H t L x a

Ø

H t L»»

ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ

I»» v

Ø

H t L»»M

3

k = 0 Ø straight line

k = const. Ø k =

ÅÅÅÅÅ

R

( a circular

v

2

ÅÅÅÅÅÅÅ

R

Think about:

a

Ø

= a T

T

`

  • a N

N

`

d »» v

Ø

H t L»»

ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ

dt

T

`

  • k I »» v

Ø

H t L »»M

2

N

`

T

`

= const. v

Ø

so N

`

in perpendicular to v

Ø

Exam III Formula Sheet.nb 1