2
n
2
V is wind velocity with a pdf f(v) = 1/10; 0 v 10. The pressure at point is
given by = 0.003 v . Find the expected value of pressure.
Sol : 1
f(v) = ; 0 v 10; = 0.003 v
10
E( ) =
≤≤ ω
ω
≤≤ ω
ω
2
2
?
E( ) = g( )d , given = 0.003 v or d = 0.006 vdv
1
given, f(v) = & = 0.003 v g( )will be monotonically increasing function.
10
dv 1 0.0274
Therefore, g( ) = f(v) d 10
=
+α
−α
ω ω ωω ω ω
ω ∴ω
ω=×
ωω
∫
12
2
0.00274( ) as = 0.003 v
−
ωω
Module 7
Example Problem
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