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This is an experiment from Discovering Design With Chemistry.
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Table 1: Masses
Mass of hydrogen peroxide: 78.3g Balloon circumference: 33.02cm Vapor pressure of water in that temperature: 0.026atm Temperature in Kelvin: 295.15K Atmospheric pressure: 29.7inHg Atmospheric pressure in Atm: 0.922atm Vapor pressure in Atm: 0.026atm Pressure of oxygen: 0.922atm โ 0.026atm = 0.896atm Radius of balloon: radius = circumference/2pie 33.02cm/2pie = 5.257cm Volume of balloon: 4/3 X 3.14 X 5.257 = 66mL 0.896atm x 66/0.0821 x 295.15K = 2.44 moles 2.44moles O 2 /1 X 2 H 2 O 2 /1 = 4.88 moles 4.88 moles H 2 O 2 /1 X 34.02g H 2 O 2 /1 = 166.
Heading (10) _______ Purpose (10) ________ Hypothesis (10) ________ Procedure (10) _______ Data (20) ________ Calculations (20) _______ Conclusion (20) ______