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An experiment designed to determine the values of Faraday's constant and Avogadro's number by studying the electrolysis of a potassium iodide solution. The experiment involves passing an electric current through the solution using a DPDT switch, a digital ammeter, and other materials. The number of moles of hydrogen gas and iodine produced are measured to calculate the number of moles of electrons that passed through the cell, which in turn is used to determine Faraday's constant and Avogadro's number.
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FV 04/20/
MATERIALS: DPDT (double pole/double throw) switch, digital ammeter, J-shaped platinum electrode and holder, Hubbell plug with attached leads, carbon electrode, electrical lead, 10 mL graduated cylinder, 100 mL beaker, 400 mL beaker, buret, thermometer, starch-KI paper, starch solution, 0.20 M KI, 1 M H (^) 2SO (^) 4, 0.0200 M Na (^) 2S2O (^) 3.
PURPOSE: The purpose of this experiment is to determine values for the Faraday constant and Avogadro’s number.
LEARNING OBJECTIVES: By the end of this experiment, the student should be able to demonstrate the following proficiencies:
DISCUSSION:
Forcing an electrical current through an electrolytic cell can cause a nonspontaneous chemical reaction to occur. For example, when direct current is passed through a solution of aqueous potassium iodide, KI, the following reactions occur at the electrodes:
anode: 2 I−^ (aq) → I 2 (aq) + 2 e−^ (oxidation)
cathode: 2 H (^) 2O (l) + 2 e−^ → H 2 (g) + 2 OH−^ (aq) (reduction)
overall redox: 2 I−^ (aq) + 2 H (^) 2O (l) → I 2 (aq) + H 2 (g) + 2 OH−^ (aq)
Electrons can be treated stoichiometrically like the other chemical species in these reactions. Thus, the number of moles of products formed is related to the number of moles of electrons that pass through the cell during the electrolysis. Iodine is formed at the anode in this electrolysis and dissolves in the solution upon stirring.^1 Hydrogen gas is formed at the cathode and will be collected in an inverted graduated cylinder by displacement of water. In this reaction, because the same number of electrons must pass through each electrode, the number of moles of iodide ion oxidized at the anode must equal the number of moles of water reduced at the cathode (i.e., in redox equations, electrons gained = electrons lost). Thus, equimolar quantities of hydrogen gas (H (^) 2) and molecular iodine (I (^) 2) will be produced by the electrolysis.
(^1) Iodine reacts with water according to the equilibrium below.
I 2 (aq) + H (^) 2O (l) ↔ HIO (aq) + H +^ (aq) + I−^ (aq)
For this reason, the pH of the solution must be adjusted to insure that I 2 is the predominant species in solution. For a more detailed explanation see: a) I. M. Kolthoff and R. Belcher, Volumetric Analysis, New York, Interscience (1957), Vol. 3, pp 214-215 and b) W. C. Bray and E. L. Connolly, J. Am. Chem. Soc. 33 (1911), 1485.
The current, or rate of flow of electricity, is measured in amperes, A. The ampere is the SI unit of current and corresponds to 1 coulomb of charge flowing for 1 second. Therefore, the total charge passing through the circuit, in coulombs, is equal to the product of the current in amperes and the time of current flow in seconds.
C = A × t (in sec)
In this experiment the following quantities will be obtained: (1) the total charge that has passed through the cell obtained from the average current and the elapsed time; (2) the number of moles of H 2 determined from the volume of gas collected; and (3) the number of moles of I 2 found by titration of the iodine with sodium thiosulfate (Na (^) 2S2O (^) 3). The number of moles of electrons that have passed through the cell can be obtained from the moles of hydrogen or the moles of iodine using stoichiometry. The total charge in coulombs that has passed through the cell can be obtained from the average current data. The value of the Faraday constant (F) can then be calculated from the total charge used in the electrolysis and the number of moles of electrons. Remember that 1 F is the electric charge, in coulombs, on 1 mole of electrons. Avogadro’s number can also be determined using the following procedure. The value of Avogadro’s number is the number of units in one mole. For the electrolysis, the required quantities for this calculation are: (1) the number of electrons and (2) the moles of electrons flowing through the electrolytic cell. As before, the moles of electrons can be determined stoichiometrically. The number of electrons can be determined from the total charge used, knowing that the charge on a single electron is 1.60 x 10 -19^ coulombs.
Part B. Moles of H 2 formed.
Part C. Moles of I 2 formed.
Clean-up:
Name Section
Partner Date
DATA SECTION Experiment 21A
Report all data with the proper number of significant figures and units.
Part A. Electrolysis and Quantity of Electrical Charge Used.
Trial 1
Initial Time _____________
Final Time _____________
Current
Average current (A) = ______________________
Total elapsed time (s) = _____________________
Observations of reaction: ________________________________________________________________________
Trial 2
Initial Time _____________
Final Time _____________
Current
Average current (A) = ______________________
Total elapsed time (s) = _____________________
Experiment 21A
Show your work for all calculations. Include the proper number of significant figures and units in your final answers. Try to complete these calculations before you leave lab.
Part A. Electrolysis and Quantity of Electrical Charge Used.
(A.1) Using the average current and the total elapsed time for the electrolysis, calculate the total electrical charge ( i.e ., number of coulombs) that passed through the cell during the electrolysis.
Trial 1: ___________________________ Trial 2: ___________________________
Part B. Moles of H 2 formed.
(B.1) From the volume of H 2 gas collected and the pressure of the dry H (^) 2, use the Ideal Gas Law to calculate the number of moles of hydrogen gas formed during the electrolysis.
Trial 1: ___________________________ Trial 2: ___________________________
Part C. Moles of I 2 formed.
(C.1) From your Na 2 S 2 O 3 titration data and the reaction stoichiometry, calculate the number of moles of iodine formed during the electrolysis.
titration reaction: I 2 (aq) + 2 Na (^) 2S2O 3 (aq) → 2 NaI (aq) + Na (^) 2S 4 O 6 (aq) ↑ ↑ electrolysis titrant product
Trial 1: ___________________________ Trial 2: ___________________________
Part D. Calculating the Value of the Faraday.
(D.1) From the moles of hydrogen gas formed at the cathode and the appropriate reaction stoichiometry on page E21A-1, calculate the moles of electrons that passed through the cell during the electrolysis.
Trial 1: ___________________________ Trial 2: ___________________________
(D.2) From the moles of iodine formed at the anode and the appropriate reaction stoichiometry on page E21A-1, calculate the moles of electrons that passed through the cell during the electrolysis.
Trial 1: ___________________________ Trial 2: ___________________________
(D.3) Using the values from (D.1) and (D.2), calculate the average number of moles of electrons that passed through the cell.
Trial 1: ___________________________ Trial 2: ___________________________
(D.4) Use the average moles of electrons that passed through the cell and the total charge that passed through the cell to calculate the Faraday, i.e., the number of coulombs per mole of electrons.
Trial 1: ___________________________ Trial 2: ___________________________
(D.5) Calculate the percent error between the value of the Faraday determined in this experiment and the accepted value. (The source for the accepted value must be properly referenced.)
Trial 1: ___________________________ Trial 2: ___________________________
Reference: ___________________________________
Experiment 21A
Name ___________________________________________________ Section _________ Date ___________
Pre-Lab Exercise Experiment 21A
a. Using Table 18.1 in the textbook, determine the standard cell potential for this reaction.
b. Is this reaction spontaneous as written (under standard conditions)? YES NO
c. If the electrolysis process was carried out for 10 minutes at 120 mA, what was the total charge (in C) that passed through the cell?