Experiment: Thermodynamics, Lab Reports of Chemistry

Second Law, a home based experiment, By John Wang, Arizona State University, New College of Interdisciplinary Arts and Sciences

Typology: Lab Reports

2020/2021

Uploaded on 05/12/2021

ryangosling
ryangosling 🇺🇸

4.8

(24)

249 documents

1 / 8

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Experiment: Thermodynamics Second Law, a homebased experiment
By John Wang, Arizona State University, New College of Interdisciplinary Arts and Sciences.
Purpose:
In this lab, we will exam the cooling processes of hot water and validate the second law of thermodynamics.
Introduction:
Entropy is a measure of the numbers of ways the energy can be distributed in a system of particles (molecules,
atoms, or ions). Particles in a system at equilibrium have the same average energy. However, at a given instant
of time, particle most likely have different amount of energy. One particle may have certain amount of energy at
one instant, and at next, it could have more or less. Depends on the energy the particle has, it will able to access
different energy levels. The total amount of energy will determine what energy levels are accessible to particles.
Mathematically Ludwig Boltzmann expressed entropy S, as:
S = k ln(W)
Where k is the Boltzmann constant = 1.38 x 10-23 J/K. W is the numbers of ways the energy can be distributed in
a system of particles
The Second Law of Thermodynamics states that entropy, or the amount of disorder in the universe, increases each
time energy is transferred or transformed. Each energy transfer results in a certain amount of energy that is lost
usually in the form of heat This heat energy can temporarily increase the speed of molecules it encounters. As
such, the more energy that a system loses to its surroundings, the less ordered and the more random the
surroundings becomes.
Entropy and the Second Law of Thermodynamics describe a wide range of occurrences in nature and engineering.
A refrigerator is essentially a heat pump and removes heat from one location at a lower temperature, the heat
source, and transfers it to another location, the heat sink, at a higher temperature. According to the second law,
heat cannot spontaneously flow from a colder location to a hotter one. Thus, work, or energy, is required for
refrigeration. A campfire is another example of entropy change in real life. The solid wood used as fuel burns and
turns into a disordered pile of ash. In addition, water molecules and carbon dioxide gas are released. The atoms
in the vapors spread out in an expanding cloud, with infinite disordered arrangements. Thus, the entropy changes
from burning wood is always positive. The released heat from the burning woods heats up the surrounding and
makes the entropy of the surroundings increase, therefore, the entropy of the universe increases. That is why
burning wood is a spontaneous Process.
Thermodynamic second law can also be demonstrated in a classic food web. Herbivores harvest chemical energy
from plants and release heat and carbon dioxide into the environment. Carnivores harvest the chemical energy
produced by herbivoreswith only a fraction of it representing the original radiant energy from the sunand
also release heat energy with carbon dioxide into their surroundings. As a result, the heat energy and other
metabolic by-products released at each stage of the food web have increased its entropy.
Think about gas trapped in a container with known volume, pressure and temperature as the system. The gas
molecules can have an enormous number of possible configurations. If the container is opened, the gas molecules
escape, and the number of configurations increases dramatically, essentially approaching infinity. If in the gas
expansion process, there is no energy exchange between the gas molecules and its surrounding, the system become
the universe. Thus, ΔS, or the change in entropy for the universe is greater than zero. Thus, the gas expansion
process is spontaneous.
pf3
pf4
pf5
pf8

Partial preview of the text

Download Experiment: Thermodynamics and more Lab Reports Chemistry in PDF only on Docsity!

Experiment: Thermodynamics – Second Law, a homebased experiment

By John Wang, Arizona State University, New College of Interdisciplinary Arts and Sciences.

Purpose :

In this lab, we will exam the cooling processes of hot water and validate the second law of thermodynamics.

Introduction :

Entropy is a measure of the numbers of ways the energy can be distributed in a system of particles (molecules,

atoms, or ions). Particles in a system at equilibrium have the same average energy. However, at a given instant

of time, particle most likely have different amount of energy. One particle may have certain amount of energy at

one instant, and at next, it could have more or less. Depends on the energy the particle has, it will able to access

different energy levels. The total amount of energy will determine what energy levels are accessible to particles.

Mathematically Ludwig Boltzmann expressed entropy S, as:

S = k ln( W )

Where k is the Boltzmann constant = 1.38 x 10

  • 23

J/K. W is the numbers of ways the energy can be distributed in

a system of particles

The Second Law of Thermodynamics states that entropy, or the amount of disorder in the universe, increases each

time energy is transferred or transformed. Each energy transfer results in a certain amount of energy that is lost—

usually in the form of heat— This heat energy can temporarily increase the speed of molecules it encounters. As

such, the more energy that a system loses to its surroundings, the less ordered and the more random the

surroundings becomes.

Entropy and the Second Law of Thermodynamics describe a wide range of occurrences in nature and engineering.

A refrigerator is essentially a heat pump and removes heat from one location at a lower temperature, the heat

source, and transfers it to another location, the heat sink, at a higher temperature. According to the second law,

heat cannot spontaneously flow from a colder location to a hotter one. Thus, work, or energy, is required for

refrigeration. A campfire is another example of entropy change in real life. The solid wood used as fuel burns and

turns into a disordered pile of ash. In addition, water molecules and carbon dioxide gas are released. The atoms

in the vapors spread out in an expanding cloud, with infinite disordered arrangements. Thus, the entropy changes

from burning wood is always positive. The released heat from the burning woods heats up the surrounding and

makes the entropy of the surroundings increase, therefore, the entropy of the universe increases. That is why

burning wood is a spontaneous Process.

Thermodynamic second law can also be demonstrated in a classic food web. Herbivores harvest chemical energy

from plants and release heat and carbon dioxide into the environment. Carnivores harvest the chemical energy

produced by herbivores—with only a fraction of it representing the original radiant energy from the sun—and

also release heat energy with carbon dioxide into their surroundings. As a result, the heat energy and other

metabolic by-products released at each stage of the food web have increased its entropy.

Think about gas trapped in a container with known volume, pressure and temperature as the system. The gas

molecules can have an enormous number of possible configurations. If the container is opened, the gas molecules

escape, and the number of configurations increases dramatically, essentially approaching infinity. If in the gas

expansion process, there is no energy exchange between the gas molecules and its surrounding, the system become

the universe. Thus, ΔS, or the change in entropy for the universe is greater than zero. Thus, the gas expansion

process is spontaneous.

Similarly, entropy also increases when hot water is left at room temperature and allowed to cool down. In this

experiment, we will explore how to measure the change in entropy of the universe during a cooling experiment.

And calculate the free energy change for the water in the cooling process.

Before learning how to do the experiment and gather data, let's learn some laws and equations that allow us to

calculate temperature change and increase in entropy during cooling experiments. Newton's Law of Cooling states

that the rate of temperature change of an object is proportional to the difference between its own temperature and

the temperature of the surroundings.

𝑠

Where T is the temperature of the object, T s

is the temperature of the surroundings. Using calculus, this

relationship can be converted into this equation,

𝑠

0

𝑠

−𝑘𝑡

where lower case t represents time, T s

denotes temperature of the surroundings, T 0

is the initial temperature of

the object, T(t) is the temperature of the object at time t, and k is a constant that depends on the characteristics of

the object and its surroundings.

Using this equation, one can calculate the temperature of a cooling system at any time if all the other variables

are known. This equation also shows that temperature is an exponential function of time. Thus, when a hot object,

like a glass of hot water, is placed in a cooler environment, its temperature will decrease at an exponential rate

until it reaches the temperature of the surroundings.

Entropy is a "state property," which is a quantity that depends only upon the current state of the system. Quantities

that are state properties do not depend on the path by which the system arrived at its present state. Therefore, the

most useful way to quantify a state property is to measure its change.

Now, let's see how to calculate the change in entropy, or ΔS. When talking about entropy, we must first define

the system. In this experiment, the system is the water, the surroundings are the air in the room. So the change in

entropy of the universe, or ΔS universe

is a sum of the change in entropies of these individual components, assuming

there is only energy exchange between water and air.

ΔS

universe

= ΔS

water

+ ΔS

air

Mathematically, the change in entropy is defined as heat gained or lost, denoted by q, divided by the temperature,

T, in Kelvin.

This equation can be applied to both the water and the air. When using this equation for water, then q is the heat

lost by water and T is the temperature of water in Kelvin. When using this equation for air, then q is the heat

gained by air and T is the temperature of air in Kelvin. We know that the hot water will cool spontaneously to the

surrounding temperature. Heat leaves water, or q has a negative sigh for water, thus ΔS water

is negative. Entropy

of water decreases. On the contrary, the surrounding air gains heat or q has a positive sign for air. Therefore, ΔS air

is positive. Entropy of the air increases. From the second law of the thermodynamics, we know that the change

in entropy of the universe must be positive for a spontaneous process. We will calculate the ΔS universe

at various

recorded temperatures.

Data table 1:

Air Temperature ________________

o

C, _______________________ Kelvins.

Volume of water used. ________________ mL

Mass of water used. Assuming density of water is 1.0 g/mL. ________________ grams

Time

Measured

Temp. of

Water

(

o

C)

Measured

Temp

Change of

Water

(

o

C)

q of

water

(J)

q of

air (J)

S

water

(J/K)

S

air

(J/K)

S

univ.

(J/K)

G

water

(kJ)

𝑙𝑛 (

𝑇(𝑡) − 𝑇

𝑠

𝑇

0

− 𝑇

𝑠

)

Calculated

Temp. of

Water (

o

C)

0’00’’

1’00’’

2’00’’

3’00’’

4’00’’

5’00’’

6’00’’

7’00’’

8’00’’

9’00’’

10’00’’

11’00’’

12’00’’

13’00’’

14’00’’

15’00’’

16’00’’

17’00’’

18’00’’

19’00’’

20’00’’

25’00’’

30’00’’

35’00’’

40’00’’

50’00’’

60’00’’

70’00’’

80’00’’

90’00’’

100’00’’

110’00’’

120’00’’

130’00’’

number of ways to distribute b identical objects into d distinguishable containers, using the combination

And in general, (

𝑛!

𝑘!

( 𝑛−𝑘

) !

, where factorial of n is n! = n ( n – 1)( n – 2) … 1. (1 point)

  1. The Haber process to produce ammonia involves the equilibrium

N 2 ( g ) + 3 H 2 ( g ) → 2 NH 3 ( g )

For this reaction, Δ H ° = – 92.38 kJ and Δ S ° = – 198.3 J/K. Assume that Δ H ° and Δ S ° for this reaction do

not change with temperature. (a) Predict the direction in which Δ G for the reaction changes with increasing

temperature. (b) Calculate Δ G at 25 °C and at 500 °C. ( 2 points)

Reference:

  1. JOVE.com/Science-Education
  2. Teaching and Learning Laboratory (TLL), and Singapore University of Technology and Design (SUTD) . RES.TLL- 004 STEM Concept Videos. Fall 2013. Massachusetts Institute of Technology: MIT

OpenCourseWare, https://ocw.mit.edu. License: Creative Commons BY-NC-SA.

  1. https://math.berkeley.edu/~rhzhao/10BSpring19/Worksheets/Discussion%205%20Solutions.pdf