Precedence Diagram and Resource Allocation Solution, Lab Reports of Engineering

A solution to a project management problem involving the determination of a precedence diagram, cycle time, minimum number of workstations, task assignments, and resource utilization. The problem includes task dependencies, task times, and workstation capacities.

Typology: Lab Reports

2020/2021

Uploaded on 05/13/2022

amer-mohia
amer-mohia 🇾🇪

1 document

1 / 3

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
ab
c
d
e
f
g
h
1.4 0.5
0.6
0.7
0.8
0.5
1.0
0.5
Assignment (Solution)
Name:
Task Immediate Predecessor Task time (min)
a - 1.4
b a 0.5
c b 0.6
d b 0.7
e b 0.8
f c 0.5
g e, d 1.0
h f, g 0.5
(1) Draw a precedence diagram.
Solution
(2) Assume an 8hour workday, compute cycle time to obtain an output rate of 266
units a day.
Solution
CycleTime=Work time per da y
Output per day =8×(60 min)
266 units
CycleTime=1.8045 minutes
(3) Determine the minimum number of workstations.
pf3

Partial preview of the text

Download Precedence Diagram and Resource Allocation Solution and more Lab Reports Engineering in PDF only on Docsity!

a (^) b c d e f g h 1.4 (^) **0.

0.**

Assignment (Solution)

Name:

Task Immediate Predecessor Task time (min) a - 1. b a 0. c b 0. d b 0. e b 0. f c 0. g e, d 1. h f, g 0.

(1) Draw a precedence diagram.

Solution

(2) Assume an 8hour workday, compute cycle time to obtain an output rate of 266

units a day.

Solution

CycleTime = Work time per da y Output per day

8 × ( 60 min ) 266 units CycleTime =1.8045 minutes

(3) Determine the minimum number of workstations.

Solution

N =

∑ task^ time

cycletime N =

∴ Minimum Number of Workstations =3.325 4

(4) Assign tasks to workstations using this rule: Assign tasks in order of the most

following tasks. In case of a tie, use a tiebreaker which is assigning tasks in

order of the greatest positional weight.

Solution

Table 1 : Terms of Greatest Positional Weight Task Task Time in minutes Number of Following Tasks Positional Weight (Highest to Lowest)

a 1.4 4 1.4+0.5+0.8+1+0.5=4.

b 0.5 3 0.5+0.8+1+0.5=2.

e 0.8 2 0.8+1+0.5=2.

d 0.7 2 0.7+1+0.5=2.

c 0.6 2 0.6+0.5+0.5=1.

g 1.0 1 1+0.5=1.

f 0.5 1 0.5+0.5=

h 0.5 0 0.