Uniformly Accelerated Motion: Horizontal and Vertical Dimensions, Slides of Earth science

The concept of uniformly accelerated motion in two dimensions: horizontal and vertical. It includes definitions, examples, and equations to help understand this physics concept. solutions to two problems involving uniformly accelerated motion in the horizontal and vertical dimensions.

Typology: Slides

2021/2022

Uploaded on 05/24/2022

anguluan-ma-jessica-s
anguluan-ma-jessica-s 🇵🇭

5

(1)

4 documents

1 / 11

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Uniformly Accelerated Motion:
Horizontal and Vertical
Dimension
Next
pf3
pf4
pf5
pf8
pf9
pfa

Partial preview of the text

Download Uniformly Accelerated Motion: Horizontal and Vertical Dimensions and more Slides Earth science in PDF only on Docsity!

Uniformly Accelerated Motion:

Horizontal and Vertical

Dimension

Next

definition If an object is under constant acceleration and moves on the x-axis plane, it is known as a uniformly accelerated motion on the horizontal plane or dimension. Similarly, if the movement is along the y- axis, it would be known as a vertical uniformly accelerated motion.

Points Speed the distance traveled by an object in a given amount of time Displacement is a vector quantity that refers to “how far out of place an object is” Velocity Speed in a given direction Acceleration Change of velocity over a period of time

Conclusion Constant acceleration means the velocity of the body changes by the same amount each second. Uniformly accelerated motion is a motion of an object with constant acceleration.

Uniformly Accelerated Motion: Horizontal Dimension If an object is under constant acceleration and moves on the x-axis plane, it is known as a uniformly accelerated motion on the horizontal plane or dimension.

Equations of Uniformly Accelerated Motion: Horizontal Dimension A jeepney from rest accelerates uniformly over a time of 3.25 seconds and covers 15 meters. Determine the acceleration of the jeepney. Solution: Given: vi = 0 m/sGiven: vi = 0 m/s d = 15 md = 15 m t = 3.25 st = 3.25 s Unknown: a = _____ Equation: d = vit + ½ at Substitution: 15 m = (0 m/s)(3.25 s ) + ½ a(3.25 s) 15 m = (5 28 s2)a a = (15 m)/(5.28 s2) Final Answer: a = 2.84 m/s

Equations of Uniformly Accelerated Motion: Vertical Dimension Zed is playing with a ball on the top of a building but the ball falls and hits the ground after 2.6 seconds. What is the final velocity of the ball just before it hits the ground and how high is the building? Solution: Given: vi = 0Given: vi = 0 g = - 9.8 m/s2 g = - 9.8 m/s t = 2.6 s t = 2.6 s Unknown: vf = _____ Equation: vf = vi + gt Substitution: vf = 0 + (- 9.8 m/s2)(2.6 s) Final Answer: vf = - 25.48 m/s

Thank You

Any Questions?