Exponentials and Logarithms Worksheet Solutions: Analyzing Quantities and Finding Values -, Assignments of Pre-Calculus

Solutions to a set of problems related to exponentials and logarithms. Topics covered include finding the value of logarithms, determining the domain and range of functions, and solving equations. The problems involve various calculations using logarithms and exponents.

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Pre 2010

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MA 107 Exponentials and Logarithms Worksheet
Solutions
1. Express the following quantity as a single logarithm
22222
22 2 2
2ln( ) ln( 1) ln( 1) ln( ) ln( 1) ln( 1) ln[ ( 1)] ln( 1)
(1) (1)(1)
ln ln ln ( 1)
11
xx x x x x xx x
xx xx x xx
xx
+−+= +−+= +
⎡⎤
−+
⎡⎤
== =
⎢⎥
⎣⎦
++
⎣⎦
2. Find the domain and range of
log( 3)yx=−
3 0 3 So the damain is (3, )xx x−> >
And the range is .
y∈ℜ
3.Find the exact value (no decimal answers) of
33
log(4)log(5)
3+
33 3 3
log (4) log (5) log (4 5) log (20 )
333
===20
Solve for x in problems 4-6
4.
33
log ( 1) log ( 4) 2xx−− + =
2
33 3
11
log ( 1) log ( 4) log 2 3 9
44
37
19( 4)9 36 8 37 8
xx
xx xx
xx x x x
−−
⎛⎞
−− + = = = =
⎜⎟
++
⎝⎠
−= + = + = =
Note that the domain of the original equation requires
10 1
40 4
xx 1
x
xx
−> > ⇒>
+> >
.
Obviously, 37
8
x=− is not in the domain, i.e., it is an extraneous solution. Hence the solution does not
exist for this equation.
5.
1
36
xx+=
12
ln3
3 6 ( 1)ln 3 ln 6 (ln 6 ln3) ln 3 ln(2) ln 3 log 3
ln 2
xx xxx x x
+=⇒+ = = = ==
6.
.09
4(3) 15 0
x−=
.09 .09 .09 33
15 15 1 15
4(3) 15 0 4(3) 15 (3) 0.09 log log
4 4 0.09 4
xxx
xx
⎛⎞ ⎛⎞
−= = = = =
⎜⎟ ⎜⎟
⎝⎠ ⎝⎠
7. a. If $3000 is invested into a money market fund at an interest rate of 5.6% compounded quarterly,
how long will it take for the investment to triple?
Compounded quarterly, so =1
nt
r
AP n
⎛⎞
+
⎜⎟
⎝⎠
, where 5.6% 0.056, 4, 3 , rnAPtunkown
=
====
So
()
44
4
0.056 0.056
3 = 1+ 3 1+ 1.014 ln(3) 4 ln 1.014
44
ln(3) 1.0986
19.76
4ln(1.014) 0.0556
tt
t
PP t
t
⎛⎞ ⎛⎞
⇒= = =
⎜⎟ ⎜⎟
⎝⎠ ⎝⎠
⇒=
pf2

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MA 107 Exponentials and Logarithms Worksheet

Solutions

  1. Express the following quantity as a single logarithm

2 2 2 2 2

2 2 2 2

2 ln( ) ln( 1) ln( 1) ln( ) ln( 1) ln( 1) ln[ ( 1)] ln( 1)

ln ln ln ( 1) 1 1

x x x x x x x x x

x x x x x x x x x

= = = ⎡^ − ⎤

⎣ +^ ⎦ ⎣ + ⎦

  1. Find the domain and range of y = log( x −3)

x − 3 > 0 ⇒ x > 3 So the damain is x ∈ (3, ∞)

And the range is y ∈ ℜ.

3.Find the exact value (no decimal answers) of

log (4) 3 log (5) 3 3

log (4) 3 log (5) 3 log (4 5) 3 log (20) 3

  • ×

Solve for x in problems 4-

  1. log ( 3 x − 1) − log ( 3 x + 4) = 2

2 3 3 3

log ( 1) log ( 4) log 2 3 9 4 4

x x x x x x

x x x x x

⎛ −^ ⎞ −

⎝ +^ ⎠ +

Note that the domain of the original equation requires

x x x 1 x x

⎬ ⇒^ >

Obviously,

x = − is not in the domain, i.e., it is an extraneous solution. Hence the solution does not

exist for this equation.

1 3 6

x + x

1 2

ln 3 3 6 ( 1) ln 3 ln 6 (ln 6 ln 3) ln 3 ln(2) ln 3 log 3 ln 2

x x x x x x x

= ⇒ + = ⇒ − = ⇒ = ⇒ = =

. 4(3) 15 0

x − =

.09 .09. 3 3

4(3) 15 0 4(3) 15 (3) 0.09 log log 4 4 0.09 4

x x x x x

  1. a. If $3000 is invested into a money market fund at an interest rate of 5.6% compounded quarterly,

how long will it take for the investment to triple?

Compounded quarterly, so = 1

nt r A P n

, where r = 5.6% = 0.056, n = 4, A = 3 P , t = unkown

So

4 4 0.056 0.056 4 3 = 1+ 3 1+ 1.014 ln(3) 4 ln 1. 4 4

ln(3) 1.

4ln(1.014) 0.

t t t P P t

t

b. How long will it take if the interest is compounded continuously?

Compounded continuously, so , where 5.6% 0.056, 3

rt A = Pe r = = A = P

0.056 0.056 ln 3^ 1. 3 3 ln 3 0.056 19. 0.056 0.

t tP = Pe = e ⇒ = tt = ≈ ≈

  1. At a nearby high school, someone overhears the principal say that school will be closed a day early

this week. The number of people, N, who hear this rumor in t minutes is given by the formula,

0.15 t N N (^) f N ef

− = − , where f

N is the fixed population of the school. If the school has 1800 students and

staff members, how many minutes will it take for ¾ of the school to hear the rumor?

t t t t N (^) f N (^) f N ef N (^) f e e e

− − − − = − = − ⇒ = − ⇒ = − = =

ln(0.25) 1. 0.15 ln(0.25) 9. 0.15 0.

t t

  1. HALF-LIFE is defined as the time required for one-half of a radioactive substance to decay. The

half-life of Strontium-90 is 29 years. If 500 grams is present now, how much will be present in 50

years? (Hint: you need to use the formula , and you need to find first from the given

information)

kt p t = p e k

(29) 29 0 0

ln(0.5) 0. 0.5 0.5 29 ln(0.5) 0. 29 29

k k p p e e k k

0.0239(50) 1. p (50) 500 e 500 e 500(0.303) 151.

− − = = ≈ =

  1. The energy E (in ergs) released during an earthquake of magnitude R (from the Richter scale)

may be approximated by the formula log( E ) = 11.4 + (1.5) R. Find the energy that was released during

one of the biggest earthquakes in history which took place in 1933 in Japan and had a magnitude of 8.9.

log( E ) = 11.4 + (1.5) R = 11.4 + 1.5 × 8.9 = 11.4 + 13.35 = 24.75 ⇒ E = 10 ≈5.6E