Material Strength and Failure: Load, Yield, Ultimate Strength, Ductility, Shear Stress, an, Lecture notes of Machine Design

An in-depth analysis of material strength and failure, focusing on static load, yield and ultimate strength, ductility, maximum shear stress and distortion energy theories. It covers the concepts of static load, failure, material strength, ductility, brittle materials, and elastic and distortion energy. The document also includes equations and design equations for calculating yield and ultimate strengths, as well as safety factors and failure envelopes.

Typology: Lecture notes

2020/2021

Uploaded on 06/29/2021

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Static load – a stationary load that is gradually applied having an unchanging
magnitude and direction
Failure – A part is permanently distorted and will not function properly.
A part has been separated into two or more pieces.
Material Strength
Sy = Yield strength in tension, Syt = Syc
Sys = Yield strength in shear
Su = Ultimate strength in tension, Sut
Suc = Ultimate strength in compression
Sus = Ultimate strength in shear = .67 Su
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Static load – a stationary load that is gradually applied having an unchanging

magnitude and direction

Failure – A part is permanently distorted and will not function properly.

A part has been separated into two or more pieces.

Material Strength

Sy = Yield strength in tension, Syt = Syc

Sys = Yield strength in shear

Su = Ultimate strength in tension, Sut

Suc = Ultimate strength in compression

Sus = Ultimate strength in shear = .67 Su

A ductile material deforms significantly before fracturing. Ductility is measured by % elongation at the fracture point. Materials with 5% or more elongation are considered ductile. Brittle material yields very little before fracturing, the yield strength is approximately the same as the ultimate strength in tension. The ultimate strength in compression is much larger than the ultimate strength in tension.

  • (^) Distortion energy theory (von Mises-Hencky) Hydrostatic state of stress → (S y ) h σ h σ h σ h σ t σ t Simple tension test → (S y ) t (S y ) t (S y ) h >> Distortion contributes to failure much more than change in volume. (total strain energy) – (strain energy due to hydrostatic stress) = strain energy

due to angular distortion > strain energy obtained from a tension test at the

yield point → failure

The area under the curve in the elastic region is called the Elastic Strain Energy. Strain energy

U = ½ σε

3D case

UT = ½ σ 1 ε 1 + ½ σ 2 ε 2 + ½ σ 3 ε 3

E

E

E

v v

E

E

E

v v

E

E

v v

Stress-strain relationship E

UT = (σ 1

2

2

2

) - 2 v (σ 1 σ 2 + σ 1 σ 3 + σ 2 σ 3 )

2 E

Strain energy from a tension test at the yield point σ 1 = S y and σ 2 = σ 3 = 0 (^) Substitute in equation (2)

3 E

1 + v

(Sy)

2 Utest = To avoid failure, Ud < Utest (σ 1 – σ 2 ) 2

  • (σ 1 – σ 3 ) 2
  • (σ 2 –^ σ 3 ) 2

< S y

U d = U T – U h =

6 E

1 + v (σ 1 – σ 2 ) 2

  • (σ 1 – σ 3 ) 2
  • (σ 2 –^ σ 3 ) 2 (2)

2D case, σ 3 = 0

2

2

) < S

y

Where σ′ is von Mises stress

S

y

n

Design equation

2

2

+ (σ 2 –^ σ 3 )

2

< S

y

S

y

n

τmax =

S

y

2 n

Distortion energy theory Maximum shear stress theory

• Select material: consider environment, density, availability → S

y

, S

u

  • (^) Choose a safety factor The selection of an appropriate safety factor should be based on the following:  (^) Degree of uncertainty about loading (type, magnitude and direction)  (^) Degree of uncertainty about material strength  (^) Type of manufacturing process  (^) Uncertainties related to stress analysis  (^) Consequence of failure; human safety and economics  (^) Codes and standards

n Size Weight Cost

 Use n = 1.2 to 1.5 for reliable materials subjected to

loads that can be determined with certainty.

 Use n = 1.5 to 2.5 for average materials subjected to

loads that can be determined. Also, human safety and

economics are not an issue.

 Use n = 3.0 to 4.0 for well known materials subjected to

uncertain loads.

One of the characteristics of a brittle material is that the ultimate strength in compression is much larger than ultimate strength in tension.

S

uc >> S ut

Mohr’s circles for compression and tension tests. Compression test S uc Failure envelope The component is safe if the state of stress falls inside the failure envelope.

σ 1 > σ 3 and σ 2 = 0

Tension test

σ 3 Stress σ 1 S ut state

σ 1 S ut S uc S ut S uc Safe Safe Safe Safe -S ut Cast iron data

Modified Coulomb-Mohr theory

σ 1 σ 3 or σ 2 S ut S ut S uc -S ut

I

II

III

Three design zones σ 3 or σ 2