Advanced Probability Theory: Martingales, Brownian Motion, and Poisson Random Measures, Exams of Statistics

The fourth attempt of a m.phil. Exam in advanced probability theory. The exam covers various topics including martingales, brownian motion, and poisson random measures. The questions involve proving theorems, showing convergence, and calculating probabilities. The document also includes instructions for the exam, such as the number of questions to attempt and the stationery requirements.

Typology: Exams

2012/2013

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M. PHIL. IN STATISTICAL SCIENCE
Monday 6 June, 2005 9 to 12
ADVANCED PROBABILITY
Attempt FOUR questions.
There are SIX questions in total.
The questions carry equal weight.
STATIONERY REQUIREMENTS SPECIAL REQUIREMENTS
Cover sheet None
Treasury Tag
Script paper
You may not start to read the questions
printed on the subsequent pages until
instructed to do so by the Invigilator.
pf3
pf4
pf5

Partial preview of the text

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M. PHIL. IN STATISTICAL SCIENCE

Monday 6 June, 2005 9 to 12

ADVANCED PROBABILITY

Attempt FOUR questions. There are SIX questions in total.

The questions carry equal weight.

STATIONERY REQUIREMENTS SPECIAL REQUIREMENTS

Cover sheet None Treasury Tag Script paper

You may not start to read the questions

printed on the subsequent pages until

instructed to do so by the Invigilator.

1 (a) Let M = (Mn)n≥ 0 be a discrete-time random process, which is integrable, and adapted to a filtration (Fn)n≥ 0. Show that the following are equivalent:

(i) M is a martingale,

(ii) E(MT ) = E(M 0 ) for all bounded stopping times T. (b) Assume that M is a martingale and that Mn → M∞ a.s. as n → ∞. State an additional condition, expressible in terms of the laws μn(dx) = P(Mn ∈ dx), which would allow us to conclude that E(MT ) = E(M 0 ) for all, possibly infinite, stopping times T.

(c) Let (Zn)n≥ 1 be a sequence of independent N(0, 1) random variables and let (an)n≥ 1 be a sequence of real numbers. Set M 0 = 0 and define

Mn =

∑^ n

k=

akZk, n ≥ 1.

By consideration of characteristic functions, or otherwise, show that Mn converges a.s. only if

k=1 a

2 k <^ ∞. (d) Under what additional conditions if any on the sequence (an)n≥ 1 can we conclude that E(MT ) = 0 for T = inf{n ≥ 0 : Mn ≥ 1 }?

2 (a) State the almost-sure martingale convergence theorem.

(b) Let f : [0, 1] → R be a Lipschitz function and define for n ∈ N, k ∈ { 0 , 1 ,... , 2 n^ − 1 } and ω ∈ [k 2 −n, (k + 1)2−n),

Xn(ω) = 2n{f ((k + 1)2−n) − f (k 2 −n)}.

Show that, for a suitable probability space (Ω, F, P) and a suitable filtration (Fn)n≥ 0 , the sequence (Xn)n∈N may be considered as a martingale.

(c) Deduce that there exists a bounded measurable function f˙ : [0, 1] → R such that, for all a, b ∈ [0, 1] with a ≤ b, we have

∫ (^) b

a

f^ ˙ (x)dx = f (b) − f (a).

ADVANCED PROBABILITY

4 (a) Let B = (Bt)t≥ 0 be a Brownian motion in Rd, d ≥ 3, starting from x. Fix ε > 0 and set T = inf{t ≥ 0 : |Bt| ≤ ε}.

Assume that |x| > ε. Show that

Px(T < ∞) = (ε/|x|)d−^2.

(b) For t > 0 and x, y ∈ Rd, set

p(t, x, y) = (2πt)−d/^2 e−|x−y|

(^2) / 2 t .

By evaluating the integral

I =

0

Rd

p(t, x, y)p(s, 0 , y)dyds

in two different ways, establish the identity

Rd

p(t, x, y)|y|^2 −ddy = cd

t

p(s, 0 , x)ds,

where cd is given by

cd =

0

(2πs)−d/^2 e−^1 /^2 sds.

(c) Show that, for x 6 = 0, as ε → 0, we have

ε^2 −dPx(T ≤ t) → cd

∫ (^) t

0

p(s, 0 , x)ds.

5 (a) Let W be a Brownian motion in Rn, n ≥ 1, starting from 0, and let U be a random variable in Rn^ which is uniformly distributed on the unit ball {|x| ≤ 1 } and is independent of W. Set T = inf{t ≥ 0 : |Wt| = |U |}. Show that WT has the same distribution as U.

(b) Suppose now that W starts from a general point x in some connected open set D in Rn. Set gD (x) = Ex(TD ), x ∈ D,

where TD = inf{t ≥ 0 : Wt 6 ∈ D}. Show that if gD (x) < ∞ for some x ∈ D then gD (y) < ∞ for all y ∈ D.

(c) For n = 1, 2 , 3 and for D = Dn = (0, ∞)n, determine whether gD is finite.

ADVANCED PROBABILITY

6 (a) Let μ be a Poisson random measure on R × (0, ∞) with intensity

ν(dy, dt) = K(dy)dt = c|y|−^2 dydt,

where c ∈ (0, ∞) is determined by

2 c

0

(1 − cos z) z^2

dz = 1.

Set

Xt =

(0,t]×{|y|≤ 1 }

y(μ − ν)(dy, ds) +

(0,t]×{|y|> 1 }

yμ(dy, ds).

Explain why these integrals are well-defined in spite of the fact that

{|y|≤ 1 }

yK(dy) =

{|y|> 1 }

yK(dy) = ∞.

(b) Write down the characteristic function of X 1 and hence obtain the density function of X 1.

(c) Fix α ∈ (0, ∞) and set X t( α)= αXαt. Show that the processes X(α)^ and X have the same distribution.

END OF PAPER

ADVANCED PROBABILITY