

Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Material Type: Exam; Class: STATISTICAL METHODS I; Subject: Statistics; University: University of South Carolina - Columbia; Term: Fall 2001;
Typology: Exams
1 / 2
This page cannot be seen from the preview
Don't miss anything!


STAT 515 ā Fall 2001 - Final Exam - Solutions
Part I: Answer three of the following four questions. If you answer more than three I will grade only the first three. Five points each.
Define what is meant by the p-value (or observed significance level) of a test. The p-value is the probability of observing a statistic as extreme as the one observed, or more extreme, if the null hypothesis is true. -or- The p- value is the smallest αααα -level at which the null hypothesis would be rejected.
The histogram at the right is skewed left We would expect that its mean would be smaller than its median.
A fair coin (probability of a head on one flip = 0.5) is flipped 10 times. What is the probability of observing exactly
5 heads? 252 ( 0. 000976562 ) 0. 2461
np p
X np Z
We need to subtract the 0.5 for the continuity correction. The answer we want is P(Z>0.73) = 0.5 - 0.2673=0.
Part II: Answer every part of the next three problems. Read each problem carefully, and show your work for full credit. Twenty points each.
1A) State the appropriate null and alternate hypothesis to test if a high score on the exam seems to indicate mild to moderate traumatic brain injury. Identify any parameters you use in stating the hypotheses. H (^) 0: μμμμ =40 vs. H (^) A : μμμμ >40 where μμμμ is the average test score of all patients with mild to moderate traumatic brain injuries
B) Test the hypothesis in part a. Report your conclusion at α=0.05 (e.g. Do we accept or reject H0? Is a high test score associated with traumatic brain injury, or not?)
compare this to 1.717 and reject H 0. The injured do seem to score higher.
C) Construct a 95% confidence interval for the mean test score of patients who suffered mild to moderate traumatic brain injury.
n
s
D) What assumptions need to be satisfied in order to trust the results you obtained in parts B and C?
The patients need to be a random sample and their test scores need to follow a normal distribution.
n
s
x tdf n
2A) Note that four values have been deleted from the ANOVA table. What values should they have?
DF for total _____________ MS for Error __________ MS for model _____________ F Statistic __________
B) Assuming the assumptions for predicting this linear regression are met, perform the test of hypotheses for testing
whether batting average predicts wins. What is the p-value, and what is your conclusion α=0.05?
The p-value is 0.0014. We reject the null hypothesis and conclude that batting average does predict wins.
C) Assuming the assumptions for this simple linear regression are met, identify which of the following statements are
true or false.
F 58.8% of a teamās wins are explained by batting average.
T 58.8% of the variation in the number of wins a team has is explained by the batting average.
F The correlation coefficient for this regression is 0.588.
T The coefficient of determination for this regressions is 0.588.
D) Assuming the assumptions for this simple linear regression are met, give the estimated range that the model says
95% of the teams batting 0.300 should have win totals between. From the prediction interval, 85.9738 to 136.8921.
E) Why canāt we trust the interval in D? A 0.300 batting average is out of the range of our data (we would be
extrapolating.)
Could Not Identify Product 55 109 164 150 150 300
A) Would this data be analyzed by using a test of independence, a test of homogeneity , or a goodness of fit test?
B) Write out the tables of expected values for conducting this test.
Male Viewer Female Viewer Identified Product (136)(150)/300=68 (136)(150)/300=
Could Not Identify Product (150)(164)/300=82 (150)(164)/300=
C) Give the formula for X 2 for this problem (plugging the values in, but not needing to simplify).
D) What is the rejection region (critical region) for conducting this test at α=0.05? df=1, so Reject if X 2 ā„3.84146.
E) Why is, or why isn't, the sample size of this experiment large enough for performing this hypothesis test?
It is large enough because all of the expected values are at least 5.
Summary of Fit Mean of Response 81. Root MSE 8.
R-Square 0. Adj R-Sq 0.
Analysis of Variance Source Model Error C Total
DF 1 12 13
Sum of Squares
Mean Square 1322. 77.
F Stat 17.
Pr > F