CS 0 Theory of Computation Final Examination, Exams of Computer Science

The instructions and problems for a theory of computation final examination. The exam is closed notes and lasts for two hours. It includes questions about proving the existence of a total, computable function and determining the recursiveness of certain sets.

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Name: CS590 Final: Page 1
CS590: Theory of Computation
Final Examination
10 May 1994 (On Campus)/Lecture Number 45 (O Campus)
1 Instructions
You may bring a single 8.5x11 inch (or A4) sheet of paper with anything you wanton
it. Other than this, the exam is closed notes. There are 100 points possible (with an
additional 10 points for an extra credit problem). This is a two hour examination, though
you may feel free to use less time if you see t to do so!
Bear in mind that incomplete answers may still receive partial credit.
2 The Problems
Problem 1
(10 points) Prove that there is a total, computable function
m
(
x
)
such that,
for all
x
W
m
(
x
)
=
f
y
: gcd(
x; y
)=1
g
where
gcd(
x; y
)
is the greatest common divisor of
x
and
y
.
Answer:
By the s-m-n theorem, dene a total, computable function
m
(
x
)
such that
m
(
x
)
=
(
1
if
gcd(
x; y
)=1
"
otherwise
By construction,
W
m
(
x
)
is the desired set.
Problem 2
(5 points) Is the set
C
=
f
e
:
e
(
e
)
"g
recursive? Is it recursively enumerable?
Justify your answer.
Answer:
C
is a set of indexes which contains an index for the function which diverges
everywhere. By the Rice-like theorem, this makes it productive, and hence neither recursive nor
r.e.
pf3
pf4

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CS590: Theory of Computation

Final Examination

10 May 1994 (On Campus)/Lecture Numb er 45 (O Campus)

1 Instructions

You may bring a single 8.5x11 inch (or A4) sheet of pap er with anything you want on it. Other than this, the exam is closed notes. There are 100 p oints p ossible (with an additional 10 p oints for an extra credit problem). This is a two hour examination, though you may feel free to use less time if you see t to do so! Bear in mind that incomplete answers may still receive partial credit.

2 The Problems

Problem 1 (10 points) Prove that there is a total, computable function m(x) such that, for al l x Wm(x) = fy : gcd(x; y ) = 1 g

where gcd(x; y ) is the greatest common divisor of x and y.

Answer: By the s-m-n theorem, de ne a total, computable function m(x) such that

m(x) =

1 if gcd(x; y ) = 1 " otherwise

By construction, Wm(x) is the desired set.

Problem 2 (5 points) Is the set C = fe : e (e) "g recursive? Is it recursively enumerable? Justify your answer.

Answer: C is a set of indexes which contains an index for the function which diverges everywhere. By the Rice-like theorem, this makes it pro ductive, and hence neither recursive nor r.e.

Problem 3 (10 points) Prove that the set F in = fe : We is nite g is not recursive.

Answer: This is an index set, since if e = f and e 2 F in then We = Wf and so Wf is nite, so f 2 F in. Hence F in is non-recursive by Rice's theorem.

Problem 4 (10 points) Give an example of an oracle O (other than SAT) such that SAT is decidable in polynomial time relative to O (i.e. S AT 2 P (O )). (Hint: SAT is N P complete.)

Answer: Let O b e any N P complete set (other than SAT). Since O pm S AT and S AT 2 P (S AT ), it follows that S AT 2 P (O ).

Problem 5 (5 points) Arrange the fol lowing complexity classes according to which is a subset of which: P ; LO G; N P S P AC E ; E X P =

S

c D^ T^ I^ M^ E^ (2n

c ); N P ; P S P AC E.

Answer: LO G  P  N P  P S P AC E = N P S P AC E  E X P

Problem 6 (10 points) List the inclusions in Problem 5 which are known to be proper (there are at least 4).

Answer: LO G  P S P AC E , LO G  N P S P AC E , P  E X P , and LO G  E X P ,

Problem 7 (10 points) I have a proof which shows that P 6 = N P by diagonalizing over al l sets in P. Unfortunately, it's too smal l to put on this examination. Do you believe me? Why or why not?

Answer: Not a bit. The Baker-Gill-Solovay theorem shows that there are oracles relative to which P = N P , and pro ofs by diagonalizatio n relativize. In other words, my pro of would imply that P (A) 6 = N P (A) for all A, even though Baker-Gill-Solovay showed a B such that P (B ) 6 = N P (B ). This contradicts my claim.

Problem 8 (10 points) Let A  B = fx 0 : x 2 Ag [ fx 1 : x 2 B g. Prove that A pm A  B for any sets A and B.

Answer: Consider the function f (x) = x 0 (or f (x) = 2 x under the usual enco ding of binary numb ers). Clearly, x 2 A if and only if f (x) 2 A  B , for any sets A and B. Since f is computable in p olynomial (indeed, in linear) time, A pm A  B via f as required.

Problem 9 (5 points) For which complexity classes are the fol lowing problems complete (with respect to pm reductions)?

Satis ability: Given a boolean formula, is there some assignment of truth values to its variables which makes the formula true?

3 Extra Credit

Problem 13 (10 points) How would you modify the URM model in such as way as to de ne the class P? How would you de ne P using this modi ed URM?

Answer: Have xed width registers (a single bit is enough). Now de ne P as the class of problems recognizable in O (nc^ ) steps on this machine, where n is the numb er of registers which contain the input, and c is some constant. Other answers are p ossible, though harder to do correctly.