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The solution to quiz 3 question in math 252, which asks to find the volume of a solid obtained by rotating a washer around the y-axis. The washer's cross-section is a circle with inner radius x+1 and outer radius 2x+1. The document calculates the area of the cross-section and integrates it from x=0 to x=1 to find the volume.
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Math 252 Quiz 3 Solution
A cross section perpendicular to the x-axis at position x (0 ≤ x ≤ 1) is a washer with inner radius x + 1 and outer radius 2x + 1 (see the picture above). Hence the area of that cross section is
A(x) = π(2x + 1)^2 − π(x + 1)^2 = π(4x^2 + 4x + 1 − (x^2 + 2x + 1)) = π(3x^2 + 2x)
Therefore the volume of the solid is ∫ (^1)
0
A(x)dx = π
0
(3x^2 + 2x)dx = π[x^3 + x^2 ]^10 = π(1 + 1 − 0 − 0) = 2π.