Foundation maths predicte dpaper markscheme, Exams of Mathematics

Predicted foundation maths paper

Typology: Exams

2024/2025

Uploaded on 03/26/2025

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AQA Year 11 Foundation Non-Calculator Paper 1 Mark Scheme Spring 2018
For multiple choice questions, accept any clear indication circled underlined etc.
Question
Answer
Marks
Notes and guidance
1
36 mm
1
2
10
15
1
3
Chord
1
4
38 + 16 ÷ 2
1
5a
19
1
5b
31
2
Award 1 mark for continuing sequence to find
5th and 6th term seen or implied
5c
e.g.
the number of tiles in a pattern should be three
more than a multiple of 4
The number of tiles needed is always odd
1
Accept any correct explanation
6
2, 1, 0, 1, 2, 3
2
Award 1 mark for listing all correct integers
with one omission or one error included
7
CLA, CLB, CLN, CWA, CWB, CWN, COA, COB,
CON
2
Award mark for 1 mark for at least 4 correct
additional combinations seen or implied.
8a
e.g. 40 ×9= £360
2
Award 1 mark for at least one value rounded
to one significant figure use for an estimation
Award 2nd mark for 360 seen
Award 0 marks for an exact value of £383.03
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For multiple choice questions, accept any clear indication – circled underlined etc.

Question Answer Marks Notes and guidance

36 mm

10

15

Chord 1

38 + 16 ÷ 2

5a

5b

Award 1 mark for continuing sequence to find

th

and 6

th

term seen or implied

5c

e.g.

  • the number of tiles in a pattern should be three

more than a multiple of 4

  • The number of tiles needed is always odd

Accept any correct explanation

Award 1 mark for listing all correct integers

with one omission or one error included

CLA, CLB, CLN, CWA, CWB, CWN, COA, COB,

CON

Award mark for 1 mark for at least 4 correct

additional combinations seen or implied.

8a

e.g. 40 × 9 = £

Award 1 mark for at least one value rounded

to one significant figure use for an estimation

Award 2

nd

mark for 360 seen

Award 0 marks for an exact value of £383.

8b

e.g. Underestimate as both values have been

rounded down 1

Allow ft from their part a

Award 0 marks for “underestimate” stated

without correct justification

9a

Award 1 mark for 25 × 60 seen or implied

9b

20 months

Award 1 mark for 600 ÷ 30 seen or implied

10 D 1

13a

e.g.

Accept – 4 – 7

13b

Award 1 mark for a correct first step to solve

seen or implied i.e. 4 𝑛 = 10

Accept equivalent answers e.g. 𝑛 =

5

2

15 a 2

Award 1 mark for method to find

P(G or B or Y) seen or implied e.g. 1 − 0.

15b

Award 1 mark for 500 × 0.24 seen or implied

18a

13

40

Accept equivalent fractions or exact decimal

answer (0.325)

Award 1 mark for correct method e.g. writing

each fraction as an equivalent fraction with a

common denominator, converting both

correctly to decimals and correct method to

subtract.

18b

2

9

Award 1 mark for

11

5

×

5

9

seen or implied

Answer must be simplified for the second mark

19a

19b

6.52 × 10

  • 3

19c

3.2 × 10

6

Award 1 mark for a correct method seen or

implied e.g. ( 9. 6 ÷ 3 ) × ( 10

4

÷ 10

− 2

) or

complete method to evaluate 96000 ÷ 0.

20a 𝑦

6

20b 8 𝑧

15

Award 1 mark for either a correct coefficient

or correct power of 𝑧

Award 1 mark for

150 000 −120 000

120 000

seen or

implied

Award 2

nd

mark for a correct method to

express answer as a percentage

Award 1 mark for an arc with radius 3 cm

drawn from C or an angle bisector of BCD

constructed.

Award 2 marks for both constructions

correctly drawn.

Award full marks for correct region shaded.

D

Award 1 mark for a correct method to find 𝑥

seen or implied e.g.

6 +𝑥

2

Award 1 mark for a correct method to find 𝑦

seen or implied e.g.

9 + " 10 " + 𝑦

2

Award full marks for both values correctly

found.

26b

23

68

Award 1 mark for

23

𝑘

where 𝑘 is their 68 from

part a

27a

27b

No, with supporting working

Award 1 mark for 𝑏 = 67 ° seen or implied.

Award 2

nd

mark for correct reason stated i.e.

isosceles triangle should have a pair of equal

angles.

Award 0 marks for “No” with no or insufficient

working.

Award 1 mark for at least four correct entries

1.25 litres/hour

Award 1 mark for a correct method to find the

gradient of the line. e.g.

15 − 5

8 − 0

No, with supporting working

Award 1 mark for a correct method to find the

number of coaches needed i.e. 540 ÷ 60 (= 9 )

Award 1 mark for a correct method to find the

cost of hiring 9 coaches.

Award full mark for a correct conclusion with

workings.

Award 0 marks if no working shown

Arc length:

1

3

of 18 𝜋 = 6 𝜋 cm

Perimeter: 6 𝜋 + 9 + 9

Award 1 mark for a correct method to find the

arc length of the sector e.g.

120

360

× 𝜋 × 18

6.8 kg or 6800 g

Award 1 mark for a correct method to find the

mass i.e. 1.7 × 4000 or 1700 × 4

Award 1 mark for 6800 or 6.8 seen or implied

Award final mark for correct units