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Solutions to various integration problems involving dirac delta functions in one and three dimensions, as well as computations of gradient and divergence of a vector field. It also includes an optional exercise on the general rule for integrating delta functions.
Typology: Exercises
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5
− 2
δ(x)f (x)dx
5
− 1
δ(x − 3)f (x)dx
4
− 1
δ(2x − 3)f (x)dx
3
− 2
δ(x
2 − 1)f (x)dx
1
− 5
δ(x
2 − 4)f (x)dx
2
− 2
dx
1
− 3
dy
5
0
dzδ(~x − (ˆx + 2ˆz))f (x, y, z)
2
− 2
dx
1
− 3
dy
5
0
dzδ(~x − (ˆx + 2ˆy + 2ˆz))f (x, y, z)
2
− 2
dx
3
− 3
dy
5
0
dzδ(~x − (ˆx + ˆy + 2ˆz))f (x, y, z)
F = 3xxˆ + (2x + z)ˆy + 3yzˆ
3.1) Compute
3.2) Compute
3.3) Can you split
F into
1
2
such that
1
0 and
2
3.4) Find a scalar V such that
1
3.5) Find a vector
A such that
2
dimension) one can write down
x 2
x 1
δ(g(x))dx =
i
x 2
x 1
δ(x − xi)
|g
′ (x i
dx
where the sum above is over all the points where g(x) is zero in the interval [x 1 , x 2 ] i.e.
g(x i
) = 0 ∀i.
4.1) Split the integral over a sum over the zeros of the function g(x)
x 2
x 1
δ(g(x))dx =
i
xi+
xi−
δ(g(x))dx
In the above you are only integrating over small intervals. Why can you discard the rest?
Can you give an idea on what size the intervals should be so as not to run into trouble?
4.2) In the region around each x i
you can write g(x) ≈ (x − x i
)g
′ (x i
). Why? You thus have
x 2
x 1
δ(g(x)) =
i
xi+
xi−
δ(xg
′
(x i
) − g
′
(x i
)x i
)dx
4.3) Prove that
x 2
x 1
δ(ax−x i
)dx =
1
|a|
1
|a|
x 2
1
|a|
x 1
δ(x−
xi
|a|
)dx. Why is the absolute value important?
This completes the proof.
4.4) Show that this general rule is consistent with the rule for δ(x
2
− α)