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The fifth assignment for mathematics 228, due on february 26, 2007. The assignment covers various exercises on homomorphisms and isomorphisms of rings. Students are required to show that the product of two homomorphic functions is a homomorphism, that the evaluation function is a homomorphism, and to prove properties of the kernel of a homomorphism. The document also includes exercises on composing homomorphic functions and finding the inverse of an isomorphism.
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Mathematics 228 (Q1), Assignment 5 Due : Monday, February 26, 2007
Exercise 1 .(10 marks) Given functions f : T → R and g : T → S, their product f × g : T → R × S is the function defined by (f × g)(t) = (f (t), g(t)), t ∈ T.
Assuming f and g are homomorphisms of rings, show f × g is a homomorphism of rings. Furthermore, show that f × g is injective if both f and g are injective.
Exercise 2 .(10 marks) Let Z[
2] be the ring of exercise 2, assignment 4 and f : Z[
2] the function defined by f (a + b
Show f is an isomorphism of Z[
Exercise 3 .(10 marks) Let R be the ring of all functions f : R → R. Given a ∈ R, the function a : R → R defined by a(f ) = f (a), f ∈ R.
is referred to as evaluation at a. Verify that a is a homomorphism of rings. Is a injective? surjective? Be sure to justify your answers. Exercise 4 .(10 marks) Let f : R → S be a homomorphism of rings. Show that if r ∈ R then for all n ∈ Z
f (nr) = nf (r).
(Hint : Recall definition of multiples and the techniques used to prove their elementary properties.)
Exercise 5 .(10 marks) Given a homomorphism f : R → S of rings, its kernel is the set
ker f = {r ∈ R : f (r) = 0S }.
(a) Verify that ker f is a subring of R. (b) Show that ker f enjoys the following additional property : if k ∈ ker f and r ∈ R then both rk and kr lie in ker f.
Exercise 6 .(10 marks) Recall, if f : R → S and g : S → T are functions then their composite g ◦ f : R → T is the function defined by (g ◦ f )(r) = g(f (r)), r ∈ R.
(a) Assuming f and g are homomorphisms of rings, show g ◦ f is also a homomorphism. (b) If f and g are isomorphisms, show g ◦ f is an isomorphism. Exercise 7 .(10 marks) Let f : R → S be an isomorphism of rings and let g : S → R be the inverse function of f. Show g is an isomorphism of rings.(Hint : To verify g(s 1 + s 2 ) = g(s 1 ) + g(s 2 ), consider its image under the homomorphism f and use the facts that f is a homomorphism and f ◦ g is the identity map.)