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A step-by-step solution to solve a system of linear equations using the gaussian elimination method. The augmented coefficient matrix, the row operations, and the calculation of the solution vector.
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1 3 -2 1 5 = Augmented Coefficient Matrix 2 -1 6 2 26 A(1) = 3 2 -5 1 - 2 6 1 -4 1
1 3 -2 1 5 Line same as A(1) m(2,1) 2 0 -7 10 0 16 m(3,1) 3 A(2) = 0 -7 1 -2 - m(4,1) 2 0 0 5 -6 -
1 3 -2 1 5 Line same as A(2) 0 -7 10 0 16 Line same as A(2) m(3,2) 1 A(3) = 0 0 -9 -2 - m(3,4) 0 0 0 5 -6 -
1 3 -2 1 5 Line same as A(3) 0 -7 10 0 16 Line same as A(3) A(4) = 0 0 -9 -2 -35 Line same as A(3) m(4,4) -0.556 0 0 0 -7.11 -28.
Solution: x(1) = 1 x(2) = 2 x(3) = 3 x(4) = 4
(^3)
(^1)
5
(^6)
(^2)
26
(^2)
(^1)
(^6)
(^1)
1
(^1)
(^3)
(^1)
5
m(2,1)
(^) =A4/A
=A4-$D$9*A
=B4-$D$9*B
=C4-$D$9*C
=D4-$D$9*D
=E4-$D$9*E
m(3,1)
(^) =A5/A
A(2) =
=A5-$D$10*A
=B5-$D$10*B
=C5-$D$10*C
=D5-$D$10*D
=E5-$D$10*E
m(4,1)
(^) =A6/A
=A6-$D$11*A
=B6-$D$11*B
=C6-$D$11*C
=D6-$D$11*D
=E6-$D$11*E
(^1)
(^3)
(^1)
5
(^0)
10
(^0)
16
m(3,2)
(^) =H10/H
A(3) =
=G10-$D$16*G
=H10-$D$16*H
=I10-$D$16*I
=J10-$D$16*J
=K10-$D$16*K
m(3,4)
(^) =H11/H
=G11-$D$17*G
=H11-$D$17*H
=I11-$D$17*I
=J11-$D$17*J
=K11-$D$17*K
(^1)
(^3)
(^1)
(^5)
x(1) =
=(K20-(J20N23+I20N22+H20*N21))/G
(^0)
10
(^0)
16
x(2) =
=(K21-J21N23-I21N22)/H
A(4) =
(^0)
(^0)
x(3) =
=(K22-J22*N23)/I
m(4,4)
(^) =I17/I
=G17-$D$23*G
=H17-$D$23*H
=I17-$D$23*I
=J17-$D$23*J
=K17-$D$23*K
x(4) =
=K23/J