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SUBJECT: GEN MATH
NAME: Burce, Mari Ella Rovi A. BRGY BOMBON
STRAND AND BLOCK: 11 STEM D CLUSTER 9
ADVISER: Mrs. Maria Aiza L. Dolar SUBJECT TEACHER: Mr. Melicio
Bayola
Quarter 1 โ Module 11: One-to-One
Functions
DATE: February 09, 2021
General Mathematics Quarter 1 โ Module 11: One-to-One Functions
WHAT I KNOW
1. B
2. A
3. C
4. B
5. A
6. A
7. A
8. A
9. B
10. B
11. C
12. D
13. B
14. D
15. A
WHATโS IN
1. FIGURE 1 FIGURE 2
x y
x y
- In figure number 2, the values of y are increasing, and every value of x
corresponds to a distinct value of y. While in figure 1, the values of y are
repeating.
- In figure no. 1 only the x that has the value of 0 have the same value to its
corresponding y which also has the value of 0. In figure no. 2 none of them have
the same values in terms of x to its corresponding y.
- A one-to-one function.
WHATโS NEW
Name LRN
Lance Marion Bobis 114624090155
Moriah Ballares 111862090008
Svenja Olivie Delfina 114624090356
Kristine Cassandra Hervacio 111877090098
Anbrey Almonte 114624090014
Questions:
- What did you observe from the table? Did you notice any repeated LRN?
- The table shows that each learner has a unique and own reference number.
Therefore, there is no repetition of their LRN.
- What do you think is the reason why learners have their own LRNs?
- Each learner has their own LRNs, it is because it is their identification number it also
makes it easier for teachers in searching for our names when having distinct numbers.
- What kind of function is depicted from the given activity?
- Since each of the domain (which is the member) is paired to exact one range (which is
the LRN) the function clearly shows that it is a one-to-one function.
- When working on the coordinate plane, a function is a one-to-one function when
it will pass the vertical line test (to make it a function) and also a horizontal line
test. (to make it one-to-one).
- Is the Function f:(m,3), (a,2), (t,9), (h,4) represents one-to-one functions? If yes,
why? Yes, it represents a one-to-one function whereas every different value of x
has different values of y or the different inputs have different outputs.
- In the diagram below, set A is the domain of the function and set B is the range
of the function.
- In a one-to-one function, given any y value, there is only one x that can be paired
with the given y. Such functions are also referred to as injective.
B.
Graph A. The reason is that graph A passed both the vertical and horizontal line test
whereas it also satisfied the one-to-one function description. The other graphs like
graph have only passed the vertical line test but did not pass the horizontal line test.
ASSESSMENT
1. A
2. B
3. A
4. C
5. A
6. C
7. B
8. B
9. A
10. D
11. C
12. C
13. C
14. A
15. D
ADDITIONAL ACTIVITIES
- Citizenship
Every person in a state have only one citizenship.
- Fare
Every profit of the fare on a bus depends on the number of passengers.
- Car
A car has a distinct plate number.
- Area of Circle
The area of a circle will depend on the input given which is the radius.
- Soap
In every sachet of soap, there is only one inside of it.
SUBJECT: GEN MATH
NAME: Burce, Mari Ella Rovi A. BRGY BOMBON
STRAND AND BLOCK: 11 STEM D CLUSTER 9
ADVISER: Mrs. Maria Aiza L. Dolar SUBJECT TEACHER: Mr. Melicio
f
โ 1
x
= x โ 2
- g ( x )= 12 x โ 1
x = 12 y โ 1
12 y = x + 1
g
โ 1
( x )=
x + 1
h ( x )=
โ x
x =
โ y
4 x =โ y
y =โ 4 x
h
โ 1
x
=โ 4 x
f ( x )= x
y = x
f
โ 1
x
= x
g ( x )=
3 x + 5
x =
3 y + 5
8 x = 3 y + 5
3 y = 8 x โ 5
- h ( c )=
2 c + 2
c =
2 y + 2
c
2
= 2 y + 2
2 y = c
2
h
โ 1
c
c
2
f ( x )=
x + 10
9 x โ 1
x =
y + 10
9 y โ 1
9 xy โ x = y + 10
y โ 9 xy =โ x โ 10
y ( 1 โ 9 x )=โ x โ 10
f
โ 1
( x )=
x + 10
1 โ 9 x
WHAT I HAVE LEARNED
- An inverse function is a function with domain B and range A given that the original
function has domain A and range B and it is denoted as f
โ 1
Then it is need to be a one-
to-one function.
f
โ 1
is the symbol for inverse function.
- No, not all the functions can be inversed. It needs to be a one-to-one function.
- First, the function should be expressed in the form
y = f ( x ) , next interchange the x and y
variables in the equation and lastly, solve for y in terms of x.
ASSESSMENT
1. D
2. C
3. B
4. B
5. A
6. A
