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Physics 211 Homework Problem Set 1, Syracuse University, Spring 2007, Assignments of Physics

Syracuse UniversityPhysics

Problem set solutions for physics 211, a college-level physics course offered at syracuse university during the spring 2007 semester. The solutions involve calculating average velocity and acceleration based on given data from young & freedman's 'university physics' textbook (12th edition).

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Pre 2010

Uploaded on 08/09/2009

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Physics 211 Spring 2007 Syracuse University Homework Problem Set 1 p.1
Physics 211 Problem Set 1 Due Friday, 01/25/08
Last Name:___________________________________ First Name _______________
Workshop time or section:___________________TA name or Room # ___________
Please submit your homework on this sheet. If you need more space than is available,
please attach additional sheets of paper. Note that the problems in the 12th edition are
NOT the same as in the 11th edition!
1. Solve exercise 2.4a,b in Chapter 2 of Young&Freedman (12th ed., p.62).
(a)
Average velocity:
,avex
x
v
t
∆
=
∆
We need to apply this equation for each segment to find the time traveled in the
segment. The average speed is the ratio between the distance traveled and the time
elapsed.
The distance traveled is 200m+280m = 480 m.
The eastward run takes 200m/(5m/s)=40.s; the westward runs takes
280m/(4m/s)=70s⇒the average speed is 480m/110s= 4.4 m/s
b) the average velocity is
,80
0.73/
110
avex
xm
vms
ts
===−
∆
The average velocity is directed westward.
pf2

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Physics 211 Spring 2007 Syracuse University Homework Problem Set 1 p.

Physics 211 Problem Set 1 Due Friday, 01/25/ Last Name:___________________________________ First Name _______________ Workshop time or section:___________________TA name or Room # ___________

Please submit your homework on this sheet. If you need more space than is available, please attach additional sheets of paper. Note that the problems in the 12th^ edition are NOT the same as in the 11th^ edition!

  1. Solve exercise 2.4a,b in Chapter 2 of Young&Freedman (12th^ ed., p.62).

(a)

Average velocity:

a v e x ,

x v t

We need to apply this equation for each segment to find the time traveled in the segment. The average speed is the ratio between the distance traveled and the time elapsed.

The distance traveled is 200m+280m = 480 m.

The eastward run takes 200m/(5m/s)=40.s; the westward runs takes 280m/(4m/s)=70s⇒the average speed is 480m/110s= 4.4 m/s

b) the average velocity is

,

a v e x 110

x m v m s t s

The average velocity is directed westward.

Physics 211 Spring 2007 Syracuse University Homework Problem Set 1 p.

  1. Solve exercise 2.15a,b,c (Young and Freedman 12th edition p.63).

(a) x= x0 + vx0t + ½ at^2 = 50 cm + 2cm/s t – 0.0625 cm/s^2 t ⇒x(0)= x0 = 50 cm; vx= vx0=2.00 cm/s ax=-0.125 cm/s^2

(b) set vx=0 we get ∆t(xmax)=2.cm/s/[0.125cm/s^2 ]=16s

(c) when vx = 0 (inversion point) we have

xmax=50 cm +2 cm/s*16s -0.0625 *16^2 cm= 66 cm then we can write the equation of motion as: x=66 cm -0.0625 *t^2 cm at x=50 cm, t=16 s⇒ the turtle returns at the starting point after 16 s (to reach xmax) + 16 s (to get back where it started from) = 32 s.