Geometry Cheat Sheet: Formulas and Problems with Solutions, Cheat Sheet of Geometry

Basic Geometry formulas, properties and problems with solutions

Typology: Cheat Sheet

2019/2020

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BASIC GEOMETRIC FORMULAS AND PROPERTIES
This handout is intended as a review of basic geometric formulas and properties. For further or more advanced
geometric formulas and properties, consult with a SLAC counselor.
r
Square:
Perimeter:
P = 4s or 2s + 2s
Area: A = s2
s
s
Rectangle: l
w
Perimeter: P = 2w + 2l
Area: A = l ×w
Triangles:
Perimeter: P = a + b + c
a c
h
b
Area:
A = (1/2) × b × h
Types of Triangles:
Isosceles (two equal sides)
Equilateral (all sides equal)
Right (one 90o or right angle)
A
c b
B C
a
Pythagorean Theorem (for right triangles only):
a2 + b 2 = c2
Sum of the Angles (all triangles):
o
A + B + C = 180
iameter:
Circle:
D d = 2r
Circumference: C = 2
π
r =
π
d
Area: A =
π
r2
Rectangular Solid: l
w
h
Volume: V = l × w h
w) + (2
×
Surface Area: S = (2 h × ×
×
l
×
h ) + (2
×
l
×
w)
ight C
R ircular Cylinder:
Volume:
V =
π
r h
2
r
h
Surface Area: S = 2
π
r h + 2
π
r2
mentary
ures
les A
les.
omplementary Angles: C
Two angles are comple
if the sum of their meas
C
A
D
B
is 90o. Angles A and B are
complementary angles. Ang
and C are complementary ang
pf3
pf4
pf5

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BASIC GEOMETRIC FORMULAS AND PROPERTIES

This handout is intended as a review of basic geometric formulas and properties. For further or more advanced geometric formulas and properties, consult with a SLAC counselor.

r

Square:

Perimeter: P = 4s or 2s + 2s

Area: A = s^2

s

s

Rectangle: l

w

Perimeter: P = 2w + 2 l

Area: A = l × w

Triangles:

Perimeter: P = a + b + c

a (^) h c b

Area: A = (1/2) × b × h

Types of Triangles:

Isosceles (two equal sides) Equilateral (all sides equal) Right (one 90o (^) or right angle) A c b B (^) a C

Pythagorean Theorem (for right triangles only):

a^2 + b 2 = c^2

Sum of the Angles (all triangles):o

A + B + C = 180

iameter:

Circle:

D d = 2r

Circumference: C = 2 π r = π d

Area: A = π r^2

Rectangular Solid: l

w h

Volume: V = l × w h

w) + (

×

Surface Area: S = (2 × h× × l × h ) + (2 × l × w)

R ight C ircular Cylinder:

Volume: V = π r h^2

r h

Surface Area: S = 2 π r h + 2 π r^2

mentaryures les A les.

C omplementary Angles:

Two angles are compleif the sum of their meas A C B D

is 90 complementary angles. Ango. Angles A and B are and C are complementary ang

upple

pplementary angles. Angles^ d 2 are ntary angles.

Oppos o lines,

s).

Angles 2 and 3 are congruent. Angles:

re also alternate interior angles. re called alternate

ior nt.

re also alternative exterior angles. nt. (opposite/vertical angles) Angles 4 and 5 are congruent. (alternate interior angles)

Straight lines have degrees measuring B is a straight line,

m 3

S mentary Angles: Two angles are supplementary if the sum of their measures is 180o^. Angles 1 an su 2 and 4 are suppleme m 1 2 1 4 3

m 2 6 5 8 7

ite/Vertical Angles: he intersection of tw m and m , form four

T 1 3 angles. Opposite (vertical) angles are congruent (have equal measure Angles 1 and 4 are congruent.

Alternate Interior and Exterior Lines m 1 and m 2 are parallel. Angles 4 and 5 are called alternate interior angles. Alternate interior angles are congruent. Angles 3 and 6 a Angles 2 and 7 a exterior angles.

Alternate exter angles are congrue Angles 1 and 8 a Note: Angles 1 and 4 are congrue Angles 5 and 8 are congruent. (opposite/vertical angles) Angles 1 and 8 are congruent. (alternate exterior angles) Angles 2 and 6 are congruent. (corresponding angles) Angles 3 and 7 are congruent. (corresponding angles) etc.

Straight Lines: (^180) then angle DCB is 180o. If D to (^) o. D^ C^ B

SOLUTIONS/ANSWERS

  1. P = a + b + c27 = 7 + 13 + c 7 = c (c = 7 centimeters)
  2. (^) A = (1/2)A = (1/2) A = 16 (A = 16)units^2
  3. (^) A = 49A = s^2 A = 7s = 7 2 (s = 7 ft.)

P = 28 (P = 28 ft.)

( l = 9 units)

  1. (^) tells us another angle is 70g h one 90o^ angle o Angles: A + B + C = 180 90 o (^) + 70o (^) + C = 180o o C = 20o^ (C = 20o)
  2. c 2 52 2 = (b = 3 units)
  3. 16

× × b 8 (^) ×× h 4

P = 4(7) A = l × w 36 = l × 4 9 = l Problem^ Right tr^ ian le^ as Sum of

Right Triangles a (^2) + b = 4 + b^2 22 = 16 + b b 2 = 9= 25 b 3 A = π r^2 π (^) = π r^2 π

π π

(^16) = r^2 16 = r^2 (d = 8 units)

d = 2r = 2(4) = 8^ r = 4 C = 2 π 4 C = 2 C = 8 π π (4) ( π =3.14) 25.13 (C = 25.13 units)

  1. V = 240 = 125 = w w (^4) (w = 5 in.)

C = 8(3.14) C = l × w × h × × V = V = π π × r^2 × h V = π ××^242 ×^ × 7 7 V = 28(3.14)V = 87 92. ( π= 3.14) (V = 87.92 unit (^3) )

  1. h 60 gree measure of 180o (Angle 1 = 60o (^) ) Angle 1 0 o^ (above)(alternate exterior of angle 1) ( osite/vertical of angle 8) (Angle 5 = 60o^ )
  2. posite in rior of angle 5 ab

o m)^2 ] OR

repared by: Jefferson Humphries, 1989. Revised by: Ziad Diab, 1994 TUDENT LEARNING ASSISTANCE CENTER (SLAC) evised: Summer 2005 exas State University-San Marcos

Straig t lines have a de 180 o (^) - 120o (^) = o

  1. (^) Angle 8 = 60= 6o Angle 5 = 60o^ opp Angle 4 = 60o^ (op te ove) OR (straihave a degree measure of 180 ght lin s [the diagonal ofe

(opposite vertical with angle 1) (Angle 4 = 60o^ )

P R S T