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This assignment solution was submitted to Amar Sharma for Finite Element Method course at Aligarh Muslim University. It includes: Cartesian, Global, Coordinates, Corner, Nodes, Quadrilateral, Element, Transformation, Point, Local
Typology: Exercises
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The Cartesian global coordinates of the corner nodes of a quadrilateral element are given by (0,-1), (-2, 3),(2,4) and (5,3). Find the coordinate transformation between the global and local (natural) coordinates. Using this determine the Cartesian coordinates of the point defined by (r, s) = (0.5, 0.5) in the global coordinate system.
SOLUTION
Where (xi, yi ) are the (x ,y) coordinates of node i(1,2,3,4)
Ni =1/4 (1+rri) (1+ssi) ;I =1,2,3,
And (r 1 , s 1 ) = (-1,-1)
(r 2 , s 2 ) = (1,-1) (r 3 ,s 3 )= (1, 1) (r 4 , s 4 )= (-1, 1)
By substituting values of (xi, yi); i= 1,2,3,4 in equation 4.32, we obtain
X=N 1 x 1 +N 2 x 2 +N 3 x 3 +N 4 x 4 = 5N 2 +2N 3 -2N 4
Y=N 1 y 2 +N 2 y 2 +N 3 y 3 +N 4 y 4 =N 1 + 3 N 2 +4N 3 +3N 4
And N 1 =1/4(1-r) (1-s)
N 2 =1/4(1+r) (1-s) N 3 =1/4(1+r) (1+s)
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N 4 =1/4(1-r) (1+s)
By substituting values of N 1 , N 2 , N 3 , N 4 in above relations, we obtained
X= 1/4 [5(1+r) (1-s) +2(1+r) (1+s)-2(1-r) (1+s)]
Y=1/4 [-1(1-r) (1-s) +3(1+r) (1-s) +4(1+r)(1+s)+3(1-r)(1+s)]
This is the coordination transformation between global and natural coordinates.
For global coordinates of point (r, s) = (0.5, 0.5)
Substitute the values of r and s in above relations
X=1/4[5(1.5)(0.5)+2(1.5)(1.5)-2(0.5)(1.5)]
X=1.
Y=1/4[-(0.5)(0.5)+3(1.5)(0.5)+4(1.5)(1.5)+3(0.5)(1.5)]
Y=3.
So global coordinates of point (x, y) = (1.6875,3.3125)
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