Practice Problems Solutions for Final Exam in Vector Calculus, Exams of Calculus

The solutions to practice problems for a final exam in vector calculus. It includes calculations for various vector operations such as gradients, divergence, curl, and line integrals.

Typology: Exams

2012/2013

Uploaded on 02/11/2013

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SOLUTIONS TO PRACTICE PROBLEMS FOR THE FINAL
EXAM
1. (a) (e1)/2. (b) (1.136,1.652). 2. 1/2.
3. (a) 3π/2. (b) π
8ln 5. 4. 1/12; (2/5,1/5,2/5).
5.
(a)Z2
2Z2x2
2x2Z4x2
y2
x2+y2
(x+ 2y+z)dzdydx,
(b)Z2π
0Z2
0Z4r2
r
r(rcos θ+ 2rsin θ+z)dzdrdθ,
(c)Z2π
0Zπ/4
0Z2
0
ρ3(sin ϕcos θ+ 2 sin ϕsin θ+ cos ϕ) sin ϕ dρdϕdθ.
6. (a) (a) 2ma3/3. (b) π/14.
7.
Zπ/2
0Z2
1Z4r2
0
r(z2+r)dzdrdθ.
8.
Z2π
0Z2
0Z16r2+6rsin θ
16r2+6rsin θ
r dzdrdθ
9. (i) π9/2. (ii) 3π/4. The force field is not conservative because
Rc~
F·d~r is not path independnt.
10. 4/5.
11. (a) 2π,~
Fis not conservative. (b) curl ~
F= 0. This does not contradict
Green’s Theorem because the partial derivatives of ~
Fare not continuous at
the origin.
12. (a) 10. (b) 17.
13. No, since div(curl ~
G) must be 0 but div(2x~
i+ 3yz ~
jxz2~
k) = 2 + 3z
2xz 6= 0.
14. (a) (2a/π, 2a/π). (b) (3a/8,3a/8,3a/8). 15. 500,000π.
16. 11π.17. 1/2. 18. 4π.
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SOLUTIONS TO PRACTICE PROBLEMS FOR THE FINAL

EXAM

  1. (a) (e − 1)/2. (b) (1. 136 , 1 .652). 2. 1 /2.
  2. (a) 3π/2. (b)

π

ln 5. 4. 1 /12; (2/ 5 , 1 / 5 , 2 /5).

(a)

2

2

2 −x

2

2 −x

2

4 −x

2 −y

2

x

2 +y

2

(x + 2y + z) dzdydx,

(b)

2 π

0

2

0

4 −r

2

r

r(r cos θ + 2r sin θ + z) dzdrdθ,

(c)

2 π

0

π/ 4

0

2

0

ρ

3 (sin ϕ cos θ + 2 sin ϕ sin θ + cos ϕ) sin ϕ dρdϕdθ.

  1. (a) (a) 2ma

3 /3. (b) π/14.

π/ 2

0

2

1

4 −r

2

0

r(z

2

  • r) dzdrdθ.

2 π

0

2

0

16 −r

2 +6r sin θ

16 −r

2 +6r sin θ

r dzdrdθ

  1. (i) π − 9 /2. (ii) − 3 π/4. The force field is not conservative because

c

F · d~r is not path independnt.

  1. (a) 2π,

F is not conservative. (b) curl

F = 0. This does not contradict

Green’s Theorem because the partial derivatives of

F are not continuous at

the origin.

  1. (a) 10. (b) 17.
  2. No, since div(curl

G) must be 0 but div(2x~i + 3yz ~j − xz

k) = 2 + 3z −

2 xz 6 = 0.

  1. (a) (2a/π, 2 a/π). (b) (3a/ 8 , 3 a/ 8 , 3 a/8). 15. 500 , 000 π.
  2. 11 π. 17. − 1 /2. 18. 4 π.

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