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Electric Field: E(r) = (1/4πnn) ∫ ρ(r′) (r − r′)/|r − r′|³ dτ′ E = −∇V Gauss’s Law: n E·da = Q_enc/nn ∇·E = ρ/nn Curl-free: ∇×E = 0 → existence of scalar potential V Poisson/Laplace: ∇²V = −ρ/nn ∇²V = 0 (charge-free regions) Boundary Conditions: E_⊥ above − E_⊥ below = σ/nn E_n continuous Energy: U = (nn/2) ∫ E² dτ
Laplace Solutions: Cartesian: V(x,y,z) = X(x)Y(y)Z(z) X″/X + Y″/Y + Z″/Z = 0 Spherical: V(r,θ) = Σ (A_l r^l + B_l r^{−l−1}) P_l(cosθ) Uniqueness Theorems: Dirichlet: potential fixed on boundary → unique solution. Neumann: normal derivative fixed → unique up to constant. Method of Images:
Replace conductor boundary with “image charge”. Example: point charge q above grounded plane → image −q. Multipole Expansion: 1/|r − r′| = Σ (r′^l / r^{l+1}) P_l(cosγ) Dipole potential: V = (1/4πnn) (p·rn)/r²
Polarization: P = dipole moment per unit volume Bound charge: ρ_b = −∇·P σ_b = P·nn D-field: D = nnE + P Gauss in matter: ∇·D = ρ_free Linear dielectrics: P = χe nn E D = nE with n = nn(1 + χe) Boundary Conditions: D⊥ above − D⊥ below = σ_free E_n continuous Energy: U = (1/2) ∫ E·D dτ
Lorentz Force: F = q(E + v×B)