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The proof of dirac's theorem for hamiltonian graphs and hints for solving problem 3.7 and 3.8. It covers the concept of hamiltonian graphs, where a graph can be traversed once without repeating vertices, and eulerian graphs, where a graph can be traversed using all its edges exactly once. A proof of dirac's theorem, which is a necessary condition for a graph to be hamiltonian, and hints for solving problems related to finding hamiltonian and eulerian paths.
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Lecture 5 Copyright ©c Sue Geller 2006
This week’s topic is Hamiltonian graphs in which we want to hit every vertex once without repeating a vertex, but it doesn’t matter what edges we use. Indeed, in most graphs we won’t use all the edges. As is in the reading, Alexander Hamilton started the study of Hamiltonian graphs by creating a traveling salesmen game.
Since we are skipping Exercise 3.7, I include the proof of Dirac’s Theorem here so that you can use it in your solutions to the assigned Problems.
Proof: Suppose that there are n vertices. After adding edges, we may assume that there is a path of the form (v 1 , v 2 ,... , vn), where v 1 and vn are not adjacent. I claim that the degree condition implies that, if we look at all the vertices adjacent to vn, there must be one, say vk, whose successor is adjacent to v 1. For v 1 is connected to at least n/2 vertices and vn is connected to at least n/2 vertices but v 1 is not connected to vn. Therefore they both must be connected to at least one vertex, vk. Then a Hamiltonian cycle is (v 1 ,... , vk, vn, vn− 1 ,... , vk+1, v 1 ).
Problem 3.7 hint: Change the problem into one for a graph constructed from the information given.
On Problem 3.8 be sure to prove your characterization, i.e., a necessary and sufficient condition that the graph have a path that is both Eulerian and Hamiltonian.