Homework 2 with Resolution - Optimization | MATH 5750, Assignments of Optimization Techniques in Engineering

Material Type: Assignment; Class: Optimization; Subject: Mathematics; University: University of Utah; Term: Unknown 1989;

Typology: Assignments

Pre 2010

Uploaded on 08/30/2009

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Homework 2
Section 6.5, 6.4(a): For f(t) = cos(ω0t)and ψ(t)a wavelet symmetric
about 0, verify that W f (u, s) = sˆ
ψ(0) cos(ω0u).
Since ψis symmetric about 0, we have ψ=ψ. Now this verification is a
series of equalities in which we manipulate the variables to obtain the desired
statement with the rationale in brackets preceeding the step:
W f (u, s) = hf, ψu,si=1
sZ
−∞
cos(ω0t)ψtu
sdt
[def of cos] = 1
2sZ
−∞ e0t+e0tψtu
sdt
[y=tu
s] = s
2Z
−∞ e0sye0u+e0sy e0uψ(y)dy
=s
2Z
−∞
ei(0)ye0uψ(y)dy +s
2Z
−∞
ei(0)ye0uψ(y)dy
=s
2e0uZ
−∞
ei(0)yψ(y)dy +s
2e0uZ
−∞
ei(0)yψ(y)dy
[symmetry of ψ] = s
2e0u+e0uZ
−∞
ei(0)yψ(y)dy
=se0u+e0u
2ˆ
ψ(0)
=sˆ
ψ(0) cos(ω0u).
1

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Homework 2

Section 6.5, 6.4(a): For f (t) = cos(ω 0 t) and ψ(t) a wavelet symmetric

about 0, verify that W f (u, s) =

s ψˆ(sω 0 ) cos(ω 0 u).

Since ψ is symmetric about 0, we have ψ

∗ = ψ. Now this verification is a

series of equalities in which we manipulate the variables to obtain the desired

statement with the rationale in brackets preceeding the step:

W f (u, s) = 〈f, ψu,s〉 =

s

−∞

cos(ω 0 t)ψ

t − u

s

dt

[def of cos] =

s

−∞

e

iω 0 t

  • e

−iω 0 t

ψ

t − u

s

dt

[y =

t−u s ]^ =

s

2

−∞

e

iω 0 sy e

iω 0 u

  • e

−iω 0 sy e

−iω 0 u

ψ(y)dy

s

2

−∞

e

i(sω 0 )y e

iω 0 u ψ(y)dy +

s

2

−∞

e

−i(sω 0 )y e

−iω 0 u ψ(y)dy

s

2

e

iω 0 u

−∞

e

i(sω 0 )y ψ(y)dy +

s

2

e

−iω 0 u

−∞

e

−i(sω 0 )y ψ(y)dy

[symmetry of ψ] =

s

2

e

iω 0 u

  • e

−iω 0 u

−∞

e

−i(sω 0 )y ψ(y)dy

s

e

iω 0 u

  • e

−iω 0 u

ψ^ ˆ(sω 0 )

s ψˆ(sω 0 ) cos(ω 0 u).