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Homework 5 Solution Key - Power Electronics - Fall 2008 | ECE 472, Assignments of Electrical and Electronics Engineering

Boise State University (BSU)Electrical and Electronics Engineering
Prof. Said Ahmed-Zaid

Material Type: Assignment; Professor: Ahmed-Zaid; Class: Power Electronics; Subject: Electrical & Computer Engineer; University: Boise State University; Term: Fall 2008;

Typology: Assignments

Pre 2010

Uploaded on 08/18/2009

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Download Homework 5 Solution Key - Power Electronics - Fall 2008 | ECE 472 and more Assignments Electrical and Electronics Engineering in PDF only on Docsity!

ECE472 HOMEWORK #5 ~ SOLUTIONS FALL 2008 Problem 5.1 (Problem D7.18 p. 375) jolt) = Toavg = 20A => Ignms & 20A Pog = Rieoms = Rx20? = 2000W = R = 52 QW, 2(n2/111)Vs 2(na/n1)(100 ’ 2 Voouy = HB = 2ra/a)Vn - 2Ara/n(00) Rloag = 5X20 =< T= = Problem 5.2 (Problem D7.29 p. 377) Using the following approximations, 7 h+T/4 Vinltr + 7/4 Vow = Vn Vne OHM) & Yq Vn (1 BEE) = Tali FEI) ty +T/4 Vipp & Yoh 47/8) S 0.05Vea0g << 0.05Vin b+T/4 ( r) 20F Ac > BAF = oo(4 45 a = = 0.05 IF Gg) PF br ar 5/60 1 > 2 UX 2. ew C2 Fs 0 i 4.17 mF Choosing C = 10 mF yields the following exact calculations: ss Problem D7.29 p. 377 R = 20; Vs = 150; f = 60; T = 1/f; w = 2epixf; ¢ = 0.010; % (a) C = 10 mF tau = R*C; tlold = 0; ti = T/8; while (abs(ti-tlold) >= 0.000001) tiold = t1; ti = asin(exp(-(tilold+T/4)/tau))/w; end ti 4% ti = 0.0034 sec VRpp = Vs-Vs*sin(w*ti) % VRpp = 5.6029 V VRavg = Vs/pi*(cos(w*t1)+tau*w*(1-exp(-(ti+T/4)/tau))) % VRavg = 147.2659 V VRpp/VRavg*100 % Meets the criterion since 3.8046% < 5% TRavg = VRavg/R % (b) Ioavg = 7.3633 A W Problem 5.3 (Problem 8.4 p. 417) Using the attached Simulink model on the next page, we find a = 360°60 x 284.76 & 75.853° by trial and error.