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Math 141 homework #9 with three problems. The first problem asks to sketch the graph of a function and compare it with the calculator's result. The second problem requires writing a clear explanation of the mathematical basis for a senator's proposal based on an article. The third problem deals with the extreme value theorem and proving that the method for finding the global minimum and maximum still works for wild functions. Instructions and hints for each problem.
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Math 141 Homework # Due Tuesday, 10/23/07 Extra Problems
Problem #1 Consider the function
b(x) = x^2 +
ln |x − 2 | 1000
(#1a) Without using a calculator, sketch the graph of b(x) for − 10 ≤ x ≤ 10.
(#1b) Enter b(x) into your calculator and have it draw the graph. The result will probably not look like the graph you drew in part 1 (at least if you are using a TI-83+ or something similar). Who’s right, you or the calculator?
(#1c) Can you resolve this problem by changing the viewing window?
Problem #2 Read this article from the Lawrence Journal-World and write a sentence or two clearly ex- plaining the mathematical basis for Sen. Haley’s proposal.
Problem #3 (Bonus problem; challenging!) The Extreme Value Theorem states that if a function f (x) is continuous on a closed interval I, then f achieves a global maximum and a global minimum on I. In class on Tuesday 10/16, we discussed the possibility that f has infinitely many critical numbers in I. Let’s call a function wild if it exhibits this behavior, and tame otherwise. As we saw in class, an example of a wild function is
f (x) =
x sin
x
if 0 < x ≤ 1 0 if x = 1
on the interval I − [0, 1].
We know that if f is tame, then we can find the global minimum and maximum of f on I by listing all the (finitely many) critical numbers and endpoints, evaluating f at each of them, and comparing the values. We’d like to prove that this method still works even for wild functions.
(#3a) First, explain why the range of f must be an interval. That is, rule out the possibility that the range is something like [− 4 , 0) ∪ (1, 3]
or [− 4 , 0) ∪ (0, 3)
or { 1 , 2 , 3 , 5 , 8 , 13 , 21 }.
The next step is to figure out whether the interval is open, closed or half-and-half, and whether it is finite or infinite.
(#3b) Second, prove the following Lemma. If {x 1 , x 2 , x 3 ,... } is an infinite set of numbers in I, then there is some number a ∈ I that is an “accumulation point” of the xi’s — that is, with the property that any open^1 interval containing a also contains at least one of the xi ’s.
This Lemma is a key tool for the rest of the problem. If you don’t see how to prove the Lemma, that’s okay; you can still do the rest of the problem by assuming that the Lemma is true.
(^1) Or possibly half-open, if a is an endpoint of I, but you can ignore that case if you want to.
(#3c) Now prove that f is bounded on I; that is, there are numbers A and B (for “above” and “below”) such that B ≤ f (x) ≤ A
for every x ∈ I. (Hint: Think about what would have to happen if f is not bounded, and use the Lemma.)
Another way of saying this result is that the range of f is a subset of the interval [B, A], therefore a finite interval. We might as well assume that the interval is one of the following:
[B, A], (B, A], [B, A), (B, A).
(#3d) Rule out the possibility that the range is an open or half-open interval. (Hint: The numbers (A + B)/2, (2A + B)/3, (3A + B)/4,... all lie in the range; use this together with the Lemma.)