Physics 505 HW IX: Nonlinear Behavior in Oscillators and Pendulum Motion, Assignments of Mechanics

Homework exercises from physics 505, autumn 2005, focusing on nonlinear behavior in oscillators, specifically a pendulum. Students are asked to find the frequency of oscillation to second order in the dimensionless parameter α and determine the maximum amplitude for which the frequency differs by less than 20% from the linear result. Additionally, students are asked to compare the results with the small angle approximation and investigate the phase space trajectories for different initial conditions and with damping.

Typology: Assignments

Pre 2010

Uploaded on 03/11/2009

koofers-user-94z
koofers-user-94z 🇺🇸

5

(1)

10 documents

1 / 3

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Physics 505 HW IX 1 Autumn 2005
Physics 505 - Autumn 2005
HW IX
Due 11/30/05
Overview: Recall that solving physics problems is not (just) about solving
differential equations. Use physical reasoning tohelp solve the following
exercises and be certain to show your work. It is also important that you practice
completely solving these exercises, checking for errors as you go along.
1) We want to look more carefully at nonlinear behavior in oscillators as discussed
in Lecture 12. We have in mind a pendulum and so write the equation of motion
as
2 2
0
1 0,

where, as noted in Lecture 12,
1 6
for the pendulum (i.e., from expanding
sin
). In the lecture we focused on a first order analysis, i.e., keeping only terms
up to first order in
(note that here
is dimensionless). Here we want to see
how much the result changes if we keep terms up to second order. Assume the
following form for the solution
2
1 3 5
cos cos 3 cos 5 ,
t A t A t A t
and find the form of the frequency
(in terms of 0
,
and
1
A
) to second order in
. For the
value appropriate to the pendulum, how large can the amplitude
1
A
be before the frequency
differs by more than 20% from the linear result
0
.
2) Consider the motion of a pendulum of length
l
and (velocity dependent)
viscous damping described by
. The equation of motion is
2 2
0 0
sin 0, .
g
l
pf3

Partial preview of the text

Download Physics 505 HW IX: Nonlinear Behavior in Oscillators and Pendulum Motion and more Assignments Mechanics in PDF only on Docsity!

Physics 505 - Autumn 2005

HW IX

Due 11/30/

Overview: Recall that solving physics problems is not (just) about solving differential equations. Use physical reasoning to help solve the following exercises and be certain to show your work. It is also important that you practice completely solving these exercises, checking for errors as you go along.

  1. We want to look more carefully at nonlinear behavior in oscillators as discussed in Lecture 12. We have in mind a pendulum and so write the equation of motion as

 

2 2

where, as noted in Lecture 12, 1 6 for the pendulum ( i.e ., from expanding

sin ). In the lecture we focused on a first order analysis, i.e., keeping only terms up to first order in  (note that here  is dimensionless). Here we want to see how much the result changes if we keep terms up to second order. Assume the following form for the solution

       2

 t  A 1 cos   t  A 3 cos 3  t  A 5 cos 5  t ,

and find the form of the frequency  (in terms of   0 , and A 1 ) to second order in

. For the  value appropriate to the pendulum, how large can the amplitude A 1

be before the frequency  differs by more than 20% from the linear result  0.

  1. Consider the motion of a pendulum of length l and (velocity dependent) viscous damping described by . The equation of motion is

2 2

0 sin^ 0,^0.

g

l

a) Define a dimensionless time unit by   0 t (really an phase) and rewrite the

equation of motion in terms of this new “time”. What single parameter describes the behavior of the pendulum?

b) Write a fourth-order Runge-Kutta script to solve this equation of motion for

arbitrary initial conditions,  0    0 ,  0  0.

HINT: We can always rewrite a 2nd^ order differential equation as two 1st^ order equations,

y z

y by f y

z bz f y

^ 

^ 

and use the Runge-Kutta technique to solve for the 2-D vector x  y z , 

y z

x F t x

z bz^ f^ y

 ^ ^ 

 ^  

The R-K solution is then given by

5 0 0 1 2 3 4

1 0 0

1 2 0 0

2 3 0 0

4 0 0 3

z t z k k k k O

k F t z

k

k F t z

k

k F t z

k F t z k

     ^ 

 ^ ^ ^ ^ 

c) Ignore the friction term for the moment. Start the pendulum at  0 0.

(  0  0 ) and plot  for the range  0 to  4 . On the same graph

plot the corresponding result for the small angle approximation, sin  , that