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A problem set focused on continuity, integrability, and envelopes of real-valued functions. The problems involve proving the continuity and discontinuity of a specific function, determining riemann and lebesgue integrability, and understanding the relationship between upper semicontinuous functions and step functions.
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April 22, 2009
Submit this homework on Tuesday, April 28.
f (x) =
q if^ x^ =^
p q where^ p^ and^ q^ are coprime integers,^0 ≤^ p^ ≤^ q, 0 if x is irrational or x=0. (a) Prove that f is continuous at every irrational point and at 0, and that f is discontinuous at every rational point of the interval (0, 1];
(b) Is f Riemann integrable? If so, find R
0
f (x) dx.
(c) Is f Lebesgue integrable? If so, find
[0,1]
f.
f (x). Similarly, f is called upper
semicontinuous at the point y if f (y) 6 = +∞ and f (y) ≥ lim x→y f (x). We say that f
is lower (upper) semicontinuous on an interval if it is lower (upper) semicontinuous at each point of the interval. Clearly, f is upper semicontinuos if and only if −f is lower semicontinuous. (a) Let f (y) be finite. Prove that f is upper semicontinuous at y if and only if given > 0, there is a δ > 0 such that f (y) ≥ f (x) − for all x with |x − y| < δ. (b) A function f is continuous (at a point of in an interval) if and only if it is both upper and lower semicontinuous (at a point of in an interval). (c) A step function φ on [a, b] is upper semicontinuous if and only if for a partition a = x 0 < x 1 < · · · < xn = b defining φ and for each i = 0,... , n the value φ(xi) is greater than or equal to the maximal of the two values assumed on (xi− 1 , xi) and (xi, xi+1) (for the endpoints x 0 = a and xn = b, one of the two subintervals is void). (d) A function f on [a, b] is upper semicontinuous if and only if there is a mono- tone decreasing sequence {φn} of upper semicontinuous step functions on [a, b] such that for each x ∈ [a, b], f (x) = lim n φn(x).
inf |x−y|<δ
f (x),
and the upper envelope h of f as
h(y) = inf δ> 0 sup |x−y|<δ
f (x).
(a) For each x ∈ [a, b], g(x) ≤ f (x) ≤ h(x), and h(x) = f (x) if and only if f is upper semicontinuous at x, while g(x) = h(x) if and only if f is continuous at x. 1
2
(b) If f is bounded, the function g is lower semicontinuous on [a, b], while h is upper semicontinuous on [a, b].
envelope. Then R
∫ (^) b a f^ (x)dx^ =^
∫ (^) b a h. Hint: Use the following line of reasoning, and explain the details. If φ ≥ f
is a step function, then φ ≥ h except at a finite number of points, and so
∫ (^) b a h^ ≤
R
∫ (^) b a f^ (x)dx. But there is a sequence^ {φn}^ of step functions such that^ φn^ ↓^ h^ (see Problem 3). By the Bounded Convergence Theorem, we have
∫ (^) b a h^ = lim^
∫ (^) b a φn^ ≥
R
∫ (^) b a f^ (x)dx. (b) Use part (a) to prove the Lebesque theorem: a bounded function f on [a, b] is Riemann integrable if and only if the set of points at which f is discontinuous has measure zero.