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homework solution chapter7, Exercises of Probability and Statistics

Sungkyunkwan University – Seoul and Suwon City, GyeonggiProbability and Statistics

This is a solution for the international 3rd text of Probability Random Processes course

Typology: Exercises

2015/2016

Uploaded on 11/20/2016

jong_won_park
jong_won_park 🇰🇷

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Z\=£ ix Itc Ks Dl Ely4V4Z |=€ e (y+ ¥+ 2) a) VAR (2) = VAR (% a ly) + acoviy, 2) y+acov\Z \4.9 coy) ; aR (2)+29.c0vC = VAR(W) 4 VARCY) HAR —_ ( \ + \4 9 ( o)+2 a) (G- 3 = VAR OOF VAR (O+VARC b) VAR (X+\4 2) ]J= ZL ELi = Ez YX: = LEX: | E[Sw] = | ee | a H OF cov (Xj, Xe) van (Sn)= 2 VAR (Me) + 2% =) kel. jek 0 . Py 24 ° z r rv é Ik = | po oe po> Oo if u 9 S ‘ 2 = AG +2C0-1) Oe VARS w) =v g ~4 {