Hyperbolas - Calculus - Exercise, Exercises of Calculus

These are the notes of Exercise of Calculus. Key important points are: Hyperbolas, Vertices and Foci, Equation, Graph the Hyperbola, Standard Form, Hyperbola that Satisfies, Given Conditions, Asymptotes, Transverse Axis, Focus

Typology: Exercises

2012/2013

Uploaded on 02/11/2013

somitra-dave
somitra-dave 🇮🇳

4.7

(3)

55 documents

1 / 7

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Hyperbolas
Findtheverticesandfociofthehyperbola.
1) x2
4-y2
60 =1
A) Vertices:(0,±8);Foci:(0,±2) B) Vertices: 2
,
0);Foci:8
,
0)
C) Vertices:(0,±2);Foci:(0,±8) D) Vertices: 8
,
0);Foci:2
,
0)
2) (x-5)2
144 -(y-4)2
81 =1
A) Vertices:(14
,
4),(-4
,
4);Foci:(-4
,
4),(14
,
4) B) Vertices:(4
,
17),(4
,
-7);Foci:(4
,
-10),(4
,
20)
C) Vertices:(4
,
14),(4
,
-4);Foci:(4
,
-4),(4
,
14) D) Vertices:(17
,
4),(-7
,
4);Foci:(-10
,
4),(20
,
4)
3) (y+4)2
64 -(x+2)2
36 =1
A) Vertices:(2
,
-2),(-10
,
-2);Foci:(-10
,
-2),(2
,
-2) B) Vertices:(-2
,
4),(-2
,
-12);Foci:(-2
,
6),(-2
,
-14)
C) Vertices:(4
,
-2),(-12
,
-2);Foci:(6
,
-2),(-14
,
-2) D) Vertices:(-2
,
2),(-2
,
-10);Foci:(-2
,
-10),(-2
,
2)
Matchthegivengraphwithitsequation.
4)
x
-8-6-4-2 2468
y
6
4
2
-2
-4
-6
x
-8-6-4-2 2468
y
6
4
2
-2
-4
-6
A) x2
9-y2
25 =1B)
x2
9+y2
25 =1C)
x2
25 -y2
9=1D)
y2
9-x2
25 =1
pf3
pf4
pf5

Partial preview of the text

Download Hyperbolas - Calculus - Exercise and more Exercises Calculus in PDF only on Docsity!

Hyperbolas

Find the vertices and foci of the hyperbola.

  1. x2 4 - y2 60 = 1

A) Vertices: (0, ± 8); Foci: (0, ± 2) B) Vertices: (± 2, 0); Foci: (± 8, 0) C) Vertices: (0, ± 2); Foci: (0, ±8) D) Vertices: (± 8, 0); Foci: (± 2, 0)

  1. (x^144 -^ 5)2 - (y^ - 81 4)2 = 1

A) Vertices: (14, 4), (-4, 4); Foci: (-4, 4), (14, 4) B) Vertices: (4, 17), (4, - 7); Foci: (4, - 10), (4, 20) C) Vertices: (4, 14), (4, - 4); Foci: (4, - 4), (4, 14) D) Vertices: (17, 4), (-7, 4); Foci: (-10, 4), (20, 4)

  1. (y^ + 64 4)2 - (x^ + 36 2)2 = 1

A) Vertices: (2, - 2), (-10, - 2); Foci: (-10, - 2), (2, - 2) B) Vertices: (-2, 4), (-2, - 12); Foci: (-2, 6), (-2, - 14) C) Vertices: (4, - 2), (-12, - 2); Foci: (6, - 2), (-14, - 2) D) Vertices: (-2, 2), (-2, - 10); Foci: (-2, - 10), (-2, 2)

Match the given graph with its equation.

-8 -6 -4 -2 2 4 6 8 x

y 6 4 2

-8 -6 -4 -2 2 4 6 8 x

y 6 4 2

A) x 9

  • y 25

= 1 B) x 9

  • y 25

= 1 C) x 25

  • y 9

= 1 D) y 9

  • x 25

-8 -6 -4 -2 2 4 6 8 x

y 6 4 2

-8 -6 -4 -2 2 4 6 8 x

y 6 4 2

A) y 9

  • x 25

= 1 B) y 25

  • x 9

= 1 C) x 9

  • y 25

= 1 D) y 9

  • x 25

-8 -6 -4 -2 2 4 6 8 x

y 6 4 2

-8 -6 -4 -2 2 4 6 8 x

y 6 4 2

A) 4y2^ - 25x2^ = 100 B) 25x2^ - 4y2^ = 100 C) 25x2^ + 4y2^ = 100 D) 4x2^ - 25y2^ = 100

-8 -6 -4 -2 2 4 6 8 x

y 2

-8 -6 -4 -2 2 4 6 8 x

y 2

A) (x^ -^ 1) 16

  • (y^ +^ 3) 4

= 1 B) (x^ +^ 3) 16

  • (x^ -^ 1) 4

C) (y^ + 4 3)2- (x^ - 16 1)2 = 1 D) (x^ - 4 1)2 - (y^ + 16 3)2 = 1

  1. (x^ +^ 2) 49
  • (y^ +^ 3) 4

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

  1. (y^ +^ 1) 4
  • (x^ -^ 3) 16

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

  1. 25y2^ - 36x2^ = 900

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

  1. 16x2^ - 9y2^ = 144

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

Find an equation in standard form for the hyperbola that satisfies the given conditions.

  1. Vertices at (±2, 0), foci at (±7, 0)

A) x2 4 - y2 49 = 1 B) x2 49 - y2 4 = 1 C) x2 4 - y2 45 = 1 D) x2 45 - y2 4 = 1

  1. Vertices at (0, ±6), foci at (0, ±9)

A) y 81

  • x 36

= 1 B) y 45

  • x 36

= 1 C) y 36

  • x 81

= 1 D) y 36

  • x 45
  1. Foci at (±8, 0), transverse axis with length 14

A) x 49

  • y 64

= 1 B) x 49

  • y 15

= 1 C) x 64

  • y 49

= 1 D) x 15

  • y 49
  1. Vertices at (0, ±6), asymptotes at y = ± 3 7

x

A) y 36

  • x 196

= 1 B) y 49

  • x 9

= 1 C) y 196

  • x 36

= 1 D) y 36

  • x 49
  1. Foci at (0, ±7), a conjugate axis with length 10

A) y 49

  • x 100

= 1 B) y 24

  • x 25

= 1 C) y 100

  • x 49

= 1 D) y 25

  • x 49
  1. Center (4, - 3), focus (9, - 3), vertex (7, - 3)

A) (x^ - 9 4)2- (y^ + 25 3)2 = 1 B) (x^ - 16 4)2 - (y^ + 9 3)2 = 1

C) (x^ +^ 4) 9

  • (y^ +^ 3) 16

= 1 D) (x^ -^ 4) 9

  • (y^ +^ 3) 16

Answer Key

Testname: 12_HYPERBOLAS

1) B

2) D

3) B

4) A

5) D

6) B

7) C

8) B

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

-10 -5 5 10 x

y 10

5

  1. C
  2. D
  3. B
  4. A
  5. B
  6. D
  7. A
  8. C