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This document is a brief to the point document on ICSE Physics. This document contains important points on chapters of ICSE Physics that guarantee you good marks in the boards exam. Thank you!
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Created by Rajat Agarwal (I.C.S.E Board Physics Corrector) Trusted by the teachers of many schools! Guaranteed good score in physics!
Q1.Calculate the total moment acting on rod CD in S.I Unit. Given the forces are equal and parallel. C
10 cm 6 cm E
According to Pythagoras theorem: CE = 8cm ∵ The two forces form a couple; Moment of couple = Either Force x Perpendicular distance between the two forces = 50 x 0.08m = 4 Nm - - (1) Note: The perpendicular distance here will be only 8 cm. It cannot be 6 cm as E is considered to be D.
10 cm 6 cm E 8cm
same line. The net effect is : The body will experience both rotational and linear motion.
(Not given in question) Ans- 60cm will be the centre of gravity for the metre ruler(as it balances without any weight being suspended) F 1 =20gf F 2 =50gf (not 50g) F 3
1 =10cm D 2 =50cm D 3 =30cm According to principle of moments in equilibrium; 20cm 50cm 60cm (^) 100cm ? (^) 20gf 50gf Question 2: – A metre ruler of weight 20gf, can be balanced at 60 cm mark, without any weight being suspended. It is pivoted at it’s centre and a mass of 50g is hung from one end. What minimum weight should be placed at 20cm mark to balance it. What is the mass of ruler at 40cm?
near the geometric centre of the body.