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Calculations and results for the performance analysis of an induction machine under negative sequence excitation. It includes system and machine parameters, calculations for system and machine impedances, and determination of slip, power factors, and power losses.
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Symmetrical Components with Neg. Seq.
s 2 =1.
System Parameters: (^) ωe 377.
rad sec
:= ⋅ Vll := 480 V⋅ Vs1 := V 1 p := 4 Prot :=2950 W⋅
Machine Parameters:^ Vs2^ :=V^2
rs := 0.1 ohm⋅ xls := 0.205 ohm⋅ xlr :=0.186 ohm⋅
Vs1 = 277.1295 V xm := 7.15 ohm⋅ rr :=0.079 ohm⋅ Vs2 =13.8456 V
Calculations: (^) ωsyn
ωe
p 2
:= ωsyn 188.5 rad sec
− 1 = ⋅
ωrm := (^) ( 1 −s 1 ) ⋅ωsyn ωrm 182.
rad sec
Performance of an Induction Machine given a Slip with Negative Sequence Excitation Present
Unbalanced Phase Voltages:
j := − 1
Va 290.98 e
j 0⋅ := ⋅ ⋅V Vb 270.47 e
− j⋅ 122.54⋅deg := ⋅ ⋅V Vc 270.47 e
j 122.54⋅ ⋅deg := ⋅ ⋅V
a e
j
2 ⋅π 3
⋅ := A
a
2
a
a
a
2
− 1
Va
Vb
Vc
V 0 = 0.0049 V arg V( 0 ) =0 deg
V 1 = 277.1295 V arg V( 1 ) =0 deg
V 2 = 13.8456 V arg V( 2 ) =0 deg
− 5 = ×
Slip: (^) s 1 := 0.0333 s 2 := 2 −s 1
Symmetrical Components with Neg. Seq.
Z (^) in2 =0.4104 ohm arg Z( (^) in2) =70.33 deg
Z (^) in2 :=Z (^) f2 + rs+j x⋅ ls Z (^) in2 =0.1382 + 0.3865iohm
Z (^) in1 =2.3822 ohm arg Z( (^) in1) =26.0478 deg
Z (^) in1 :=Z (^) f1 + rs+j x⋅ ls Z (^) in1 =2.1402 + 1.0461iohm
R (^) f2 :=Re Z( (^) f2) R (^) f2 =0.0382 ohm
Z (^) f2 =0.1855 ohm arg Z( (^) f2) =78.1272 deg
Z (^) f2 Z (^) f2 =0.0382 + 0.1815iohm
j x⋅ (^) m
rr
s 2
+j x⋅lr
rr
s (^2)
+j ⋅(x (^) lr +xm)
R (^) f1 :=Re Z( (^) f1) R (^) f1 =2.0402 ohm
Z (^) f1 =2.2068 ohm arg Z( (^) f1) =22.4035 deg
Z (^) f1 Z (^) f1 =2.0402 + 0.8411iohm
j x⋅ (^) m
rr
s 1
+j x⋅lr
rr
s (^1)
+j ⋅(x (^) lr +xm)
z (^) r
z (^) r
z (^) r2 =0.1903 ohm arg z( (^) r2) =77.8135 deg
z (^) r2 z (^) r2 =0.0402 + 0.186iohm
rr
2 − s 1
:= +j x⋅lr
z (^) r1 =2.3797 ohm arg z( (^) r1) =4.483 deg
z (^) r1 z (^) r1 =2.3724 + 0.186iohm
rr
s (^1)
:= +j x⋅ lr
Symmetrical Components with Neg. Seq.
η η =0.
Pout
Pin
τ (^) out τ (^) out =422.5609 N m⋅
Pout
ωrm
Pout :=Pem −Prot Pout =77.0003 kW
τ (^) em =438.7498 N m⋅
τ (^) em :=τ (^) em1 +τ (^) em
τem
τem
τ (^) em2 τ (^) em2 =−0.691 N m⋅
( 1 −s 2 ) ⋅Pgap
( 1 −s 1 ) ⋅ωsyn
τ (^) em1 τ (^) em1 =439.4408 N m⋅
Pgap
ωsyn
Pem :=Pem1 +Pem
Pem2 :=( 1 −s 2 ) ⋅Pgap2 Pem2 =−0.1259 kW
Plossr2 :=s 2 ⋅Pgap2 Plossr2 =0.2562 kW
Pgap2 3 ( Is2) Pgap2 =0.1303 kW
2 := ⋅ ⋅R (^) f
Pem1 :=( 1 −s 1 ) ⋅Pgap1 Pem1 =80.0762 kW
Plossr1 :=s 1 ⋅Pgap1 Plossr1 =2.7584 kW
Pgap1 3 ( Is1) Pgap1 =82.8346 kW
2 := ⋅ ⋅R (^) f
Pin :=Pin1 +Pin2 Pin =87.3663 kW
Plosss :=Plosss1 +Plosss2 Plosss =4.4014 kW
Plosss
Plosss