Performance Analysis of an Induction Machine with Negative Sequence Excitation, Study notes of Electrical and Electronics Engineering

Calculations and results for the performance analysis of an induction machine under negative sequence excitation. It includes system and machine parameters, calculations for system and machine impedances, and determination of slip, power factors, and power losses.

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Pre 2010

Uploaded on 08/19/2009

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ECE523
Symmetrical Components Induction Machine Performance
with Neg. Seq. Session 24e
s21.9667=
System Parameters: ωe377.0 rad
sec
:= Vll 480 V:= Vs1 V1
:= p4:= Prot 2950 W:=
Vs2 V2
:=
Machine Parameters:
rs0.1 ohm:= xls 0.205 ohm:= xlr 0.186 ohm:=
Vs1 277.1295 V=xm7.15 ohm:= rr0.079 ohm:=
Vs2 13.8456 V=
Calculations: ωsyn ωe
p
2
:= ωsyn 188.5rad sec 1
=
ωrm 1s
1
()
ωsyn
:= ωrm 182.2229 rad
sec
=
Performance of an Induction Machine given a Slip with Negative Sequence Excitation Present
Unbalanced Phase Voltages:
j1:=
Va290.98 ej0
V:= Vb270.47 e j122.54deg
V:= Vc270.47 ej 122.54deg
V:=
ae
j2π
3
:= A
1
1
1
1
a2
a
1
a
a2
:=
V0
V1
V2
A1
Va
Vb
Vc
:=
V00.0049 V=arg V0
()
0 deg=
V1277.1295V=arg V1
()
0 deg=
V213.8456 V=arg V2
()
0 deg=
3 V1
480.00 V=V2
V10.05=V0
V11.7701 10 5
×=
Slip: s10.0333:= s22s
1
:=
NegativeSeq.mcd Page 1 of 4
pf3
pf4

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Symmetrical Components with Neg. Seq.

s 2 =1.

System Parameters: (^) ωe 377.

rad sec

:= ⋅ Vll := 480 V⋅ Vs1 := V 1 p := 4 Prot :=2950 W⋅

Machine Parameters:^ Vs2^ :=V^2

rs := 0.1 ohm⋅ xls := 0.205 ohm⋅ xlr :=0.186 ohm⋅

Vs1 = 277.1295 V xm := 7.15 ohm⋅ rr :=0.079 ohm⋅ Vs2 =13.8456 V

Calculations: (^) ωsyn

ωe

p 2

:= ωsyn 188.5 rad sec

− 1 = ⋅

ωrm := (^) ( 1 −s 1 ) ⋅ωsyn ωrm 182.

rad sec

Performance of an Induction Machine given a Slip with Negative Sequence Excitation Present

Unbalanced Phase Voltages:

j := − 1

Va 290.98 e

j 0⋅ := ⋅ ⋅V Vb 270.47 e

− j⋅ 122.54⋅deg := ⋅ ⋅V Vc 270.47 e

j 122.54⋅ ⋅deg := ⋅ ⋅V

a e

j

2 ⋅π 3

⋅ := A

a

2

a

a

a

2

V 0

V 1

V 2

A

− 1

Va

Vb

Vc

V 0 = 0.0049 V arg V( 0 ) =0 deg

V 1 = 277.1295 V arg V( 1 ) =0 deg

V 2 = 13.8456 V arg V( 2 ) =0 deg

3 V⋅ 1 = 480.00 V

V 2

V 1

V 0

V 1

− 5 = ×

Slip: (^) s 1 := 0.0333 s 2 := 2 −s 1

Symmetrical Components with Neg. Seq.

Z (^) in2 =0.4104 ohm arg Z( (^) in2) =70.33 deg

Z (^) in2 :=Z (^) f2 + rs+j x⋅ ls Z (^) in2 =0.1382 + 0.3865iohm

Z (^) in1 =2.3822 ohm arg Z( (^) in1) =26.0478 deg

Z (^) in1 :=Z (^) f1 + rs+j x⋅ ls Z (^) in1 =2.1402 + 1.0461iohm

R (^) f2 :=Re Z( (^) f2) R (^) f2 =0.0382 ohm

Z (^) f2 =0.1855 ohm arg Z( (^) f2) =78.1272 deg

Z (^) f2 Z (^) f2 =0.0382 + 0.1815iohm

j x⋅ (^) m

rr

s 2

+j x⋅lr

rr

s (^2)

+j ⋅(x (^) lr +xm)

R (^) f1 :=Re Z( (^) f1) R (^) f1 =2.0402 ohm

Z (^) f1 =2.2068 ohm arg Z( (^) f1) =22.4035 deg

Z (^) f1 Z (^) f1 =2.0402 + 0.8411iohm

j x⋅ (^) m

rr

s 1

+j x⋅lr

rr

s (^1)

+j ⋅(x (^) lr +xm)

z (^) r

z (^) r

z (^) r2 =0.1903 ohm arg z( (^) r2) =77.8135 deg

z (^) r2 z (^) r2 =0.0402 + 0.186iohm

rr

2 − s 1

:= +j x⋅lr

z (^) r1 =2.3797 ohm arg z( (^) r1) =4.483 deg

z (^) r1 z (^) r1 =2.3724 + 0.186iohm

rr

s (^1)

:= +j x⋅ lr

Symmetrical Components with Neg. Seq.

η η =0.

Pout

Pin

τ (^) out τ (^) out =422.5609 N m⋅

Pout

ωrm

Pout :=Pem −Prot Pout =77.0003 kW

τ (^) em =438.7498 N m⋅

τ (^) em :=τ (^) em1 +τ (^) em

τem

τem

τ (^) em2 τ (^) em2 =−0.691 N m⋅

( 1 −s 2 ) ⋅Pgap

( 1 −s 1 ) ⋅ωsyn

τ (^) em1 τ (^) em1 =439.4408 N m⋅

Pgap

ωsyn

Pem :=Pem1 +Pem

Pem2 :=( 1 −s 2 ) ⋅Pgap2 Pem2 =−0.1259 kW

Plossr2 :=s 2 ⋅Pgap2 Plossr2 =0.2562 kW

Pgap2 3 ( Is2) Pgap2 =0.1303 kW

2 := ⋅ ⋅R (^) f

Pem1 :=( 1 −s 1 ) ⋅Pgap1 Pem1 =80.0762 kW

Plossr1 :=s 1 ⋅Pgap1 Plossr1 =2.7584 kW

Pgap1 3 ( Is1) Pgap1 =82.8346 kW

2 := ⋅ ⋅R (^) f

Pin :=Pin1 +Pin2 Pin =87.3663 kW

Plosss :=Plosss1 +Plosss2 Plosss =4.4014 kW

Plosss

Plosss