Initial Value Problem - Ordinary and Partial Differential Equations - Solved Exam, Exams of Differential Equations

Key points of this exam paper are: Initial Value Problem, Differential Equations, Order, Nonlinear, Solution, Initial Value Problem, Pairs, Functions, Linearly Independent, General Solution

Typology: Exams

2012/2013

Uploaded on 03/21/2013

ambani
ambani 🇮🇳

5

(2)

36 documents

1 / 1

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
MATH 251
Summer 2006
Exam I
June 29, 2006
ANSWERS:
1. (a) Third order, linear; (b) First order, nonlinear; (c) Second order, nonlinear.
2. C
3. C
4. B
5. A
6. (a) y(t) = t2sin t+2
π2t2; (b) (0,).
7. (a) y= 6,5,5; (b) y=5is (asymptotically) stable, y= 5 is unstable, y= 6 is semistable;
(c) lim
t→∞
y(t) = 5; (d) y0= 5.
8. (a) ∂M
∂y =2x+ex+y= N
∂x ; (b) 2x3x2y+ex+y= 4.
9. y(t) = 3e2tcos 3te2tsin 3t
10. y(t) = C1t+C2tln t
11. (a) Q0= 100 1
200Q, Q(0) = 0; (b) Q(t) = 20000 20000e
t
200 ;
(c) t= 200ln 2; (d) lim
t→∞
Q(t) = 20000 g.

Partial preview of the text

Download Initial Value Problem - Ordinary and Partial Differential Equations - Solved Exam and more Exams Differential Equations in PDF only on Docsity!

MATH 251

Summer 2006 Exam I June 29, 2006

ANSWERS:

1. (a) Third order, linear; (b) First order, nonlinear; (c) Second order, nonlinear. 2. C 3. C 4. B 5. A 6. (a) y(t) = t^2 sin t +

π^2

t^2 ; (b) (0, ∞).

7. (a) y = 6, 5 , − 5 ; (b) y = − 5 is (asymptotically) stable, y = 5 is unstable, y = 6 is semistable;

(c) lim t→∞ y(t) = − 5 ; (d) y 0 = 5.

8. (a)

∂M

∂y = − 2 x + ex+y^ =

∂N

∂x ; (b) 2 x^3 − x^2 y + ex+y^ = 4.

9. y(t) = 3e−^2 t^ cos 3t − e−^2 t^ sin 3t 10. y(t) = C 1 t + C 2 t ln t 11. (a) Q′^ = 100 −

Q, Q(0) = 0; (b) Q(t) = 20000 − 20000 e

−t (^200) ;

(c) t = 200 ln 2; (d) lim t→∞ Q(t) = 20000 g.