integration questions, Exercises of Mathematics

integral calculus questions with solutions

Typology: Exercises

2024/2025

Available from 06/22/2025

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ENTEGRALS
BANPLE
2
Evaluate
Eraluate
the
following
integrals:
LAMPLE
S
Evaluate.
2
1+
cos
2x
dx
BASED
ON
BASIC
CONCEPTS
(BASIC)
DXAMPLE
4
Evaluate:
4+1
1
e
ILLUSTRATIVE
EXAMPLES
2
2
cos
x
Sloge
_p4
loge
x
3
loge
2
loge
x
+C
=
+1
1
3+1
-3+1
-c-2
+c
SOLLTION
We
know
that
eo8e
X=
2
+1
Sloge
x4
loge
X
5
cos
x
-+C
=
2xV2
+C
3
loge
X _2loge X
2
cos
x
2
+C
+C=--
+C
2x2
1
dx
4
x3+1
3+1
dx
()
We
know
that
cos
2x
= 2 cosx-1.
+C=
SOLUTION
(0)
We
know
that
1--cos
2x
=2
sin
x.
Cos
2x
+ 2
sinx
4
SOLUTION
We
know
that
1 +
cos
2x
=2
cos
x
and
1
-
cos
2x
=
2
sinx.
Therefore,
2 2
1+
cos
2x
2
cos
2x
+2
sin
x
dv
INCERT,
CBSE
2018
(1)
cos
+C
(x-1)
u-1)
(G0)
)1-cos
2x
2
dx
=cosec
x dx= -
cot
x
+C
2
sin
x
dx
=sec
x
dx
=
tan
x
+C
cos
x
dx
[Using
formula
(1)]
[Using
formula
(1)]
[Using
formula
()]
[Using
formula
(1)]
2
cos
x-cos
2x
15.3
sin
x
-(l-2sin"
x+2
sin
x
dy=
[
dx
=
see
x
dx
=
tan
x
+C
3
dx
+C
pf3
pf4

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ENTEGRALS

BANPLE 2 Evaluate

Eraluate the followingintegrals:

LAMPLE S Evaluate. 2 1+ cos 2x

dx

BASED ON BASIC CONCEPTS (BASIC)

DXAMPLE 4 Evaluate:

1

e

ILLUSTRATIVE EXAMPLES

2

2 cos x

Sloge _p4loge x

3 loge 2 loge x

+C =

1

3+

-3+

-c-2+c

SOLLTION We^ know^ that^ eo8e^

X=

2

Slogex4loge X

5

cos x

-+C =2xV2 +C

3 loge X_2loge X

2 cos x 2

+C

+C=-- +C

2x

1

dx

4

x3+

3+

dx

() We know that cos 2x = 2cosx-1.

+C=

SOLUTION (0) We know that 1--cos 2x =2 sin x. Cos 2x + 2 sinx

4

SOLUTION We^ know^ that^1 +^ cos^ 2x^ =2^ cos^ x^ and^1 -^ cos^ 2x^ =^2 sinx.^ Therefore, 2 2

1+ cos 2x

2

cos (^) 2x +2 (^) sin x (^) dv INCERT, (^) CBSE (^2018) (1) cos

+C

(x-1) u-1)

(G0) )1-cos 2x

2

dx =cosec x dx= - cot x+C 2 sin x

dx =sec x dx = tan x +C

cos x

dx

[Using formula (1)]

[Using formula (1)]

[Using formula ()]

[Using formula (1)]

2 cos x-cos 2x sin x

-(l-2sin" x+2 sin xdy= [ dx = see xdx = tan x+C

3

dx

+C

( 2 cos^ x-cos^ 2x^

d -f^2

cos-(2 cos

x-1) dx -

Sin 2

SOLUTION (1)^ We^ know^ that^

eloBekk.

-cosec xdx^ =-^ cot^ x^ + C

EXAMPLE5 Ifa>0^ and^ a^ ulevaluate^ the^ following^

integrals:

() feloge^4 dx^

(G) [lo8e dr

BASED ON LOWER^ ORDER^ THINKINGSKILLS^

(LOTS)

(iv) We krnow^ that^ oga Ymylogax

sin x

2

(ae)*

log (ae)

dx = a^ dx^ =

+C

loge 2+ 1

log,2 +

loge a

a+

+C=

+C

+C

loge (2e)

log, (2e)

1

sinx

+C

MATHEMATICS-XI

dx

EXERCISE 151

NTEN

1

I=

) let^ I

= f^

dx.Then,

dx. Then,

I-flt2r.

dx. Then,

-+2x 1/

dx

(vi) Let^ I^ X-

=[-tx-l dy.^ Then,

X-

3/2 5/ 3/2 5/

7 55-c 1

-+C= 2r/2 (^3)

X-

.c-i,N2_222,c

3

-tx+C

INTEGRALS

,2/2 +c