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A review of various integration techniques, including integration by parts, trigonometric integrals, trigonometric substitution, and partial fractions. It covers formulas, strategies, and examples for each method, as well as guidelines for choosing the appropriate technique for different types of integrals.
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7.1 - 7.5 Review - Integration Techniques
My reviews and review sheets are not meant to be your only form of studying. It is vital to your success on the exams that you carefully go through and understand ALL the homework problems, worksheets and lecture material. Hopefully this review sheet will remind you of some of the key ideas of these sections.
udv = uv −
vdu and
∫ (^) b a udv^ =^ uv|
b a −^
∫ (^) b a vdu
cos^2 (x) + sin^2 (x) = 1 , which we may use as cos^2 (x) = 1 − sin^2 (x) or sin^2 (x) = 1 − cos^2 (x)
Dividing these by cos^2 (x) gives more useful identities:
1 + tan^2 (x) = sec^2 (x) , which we may use as 1 = sec^2 (x) − tan^2 (x) or tan^2 (x) = sec^2 (x) − 1
We will also need the half angle identities:
sin^2 =
cos(2x) , cos^2 (x) =
cos(2x) , and sin(x) cos(x) =
sin(2x)
(c) If neither of the above cases work, you may need to use identites or integration by parts. Also it may be useful to have the following integrals: ∫ tan(x) dx = ln | sec(x)| + C and
sec(x) dx = ln | sec(x) + tan(x)| + C
a^2 − x^2 ,
√ a^2 +^ x^2 , or x^2 − a^2 somewhere in the problem.
(x − 1)(x − 5)
Then we will have a method for breaking this up and integration each part separately by using the first set of integrals below. If we have a quadratic that doesn’t factor, then we will need to complete the square and use what we know about the second integrals below. For example, 1 x^2 + x + 1
x^2 + x + 1/4 + 1/4 + 1
(x + 1/2)^2 + 5/ 4
Then we will use u-substitution along with second and third integrals below.
dx = −
x − b
(x − b)^3
dx = −
x − b
2
And so on. (b) ∫ 1 u^2 + a^2
du =
a
tan−^1
( (^) u a
(c) ∫ x x^2 + a^2
dx =
ln |x^2 + a^2 | + C