Interference and Diffraction: A Physics Lab Guide, Schemes and Mind Maps of Physics

Theory. When a monochromatic and coherent light passes through a single or double slit, it creates a diffraction/interference pattern on a screen placed ...

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Brooklyn College 1
Interference and Diffraction
Purpose
a. To study examples of interference in light waves.
b. To understand the interference pattern produced when light passes through a single slit.
c. To understand the interference pattern produced when light passes through a double slit.
Theory
When a monochromatic and coherent light passes through a single or double slit, it creates a
diffraction/interference pattern on a screen placed beyond the slits. The pattern formed is because of
the superposition of the waves coming from the slit (or two slits). The position on the screen
directly opposite the slits
is defined to have
location y = 0. Other
positions on the screen
are characterized by
their distance y away
from this origin.
Alternatively, a position
on the screen is
characterized by an
angle θ formed by the
line from the slits to this
position, relative to the
perpendicular line. Note
that if the distance from
the slits to the screen is
labelled L, then y = L
tan θ.
Double slit Interference
Interference pattern due to a double slit will have dark and bright fringes due to destructive
and constructive interference of the waves coming from the two slits. When two slits separated by a
distance d produces bright spots on the screen centered at positions where the following
constructive interference criterion is satisfied:
d sin θ = n λ, where n is an integer.
For the experiments we will be doing, the angle θ is less than 10 degrees, and sin θ tan θ =
y/L. Substituting y/L for sin θ in the above equation, we get
n
L
y
d=
,
or, rearranging,
d
Ln
y
=
. (1)
d
D
Fig. 1. Geometrical arrangement of slits and screen in experiment.
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Interference and Diffraction

Purpose

a. To study examples of interference in light waves.

b. To understand the interference pattern produced when light passes through a single slit.

c. To understand the interference pattern produced when light passes through a double slit.

Theory

When a monochromatic and coherent light passes through a single or double slit, it creates a

diffraction/interference pattern on a screen placed beyond the slits. The pattern formed is because of

the superposition of the waves coming from the slit (or two slits). The position on the screen

directly opposite the slits

is defined to have

location y = 0. Other

positions on the screen

are characterized by

their distance y away

from this origin.

Alternatively, a position

on the screen is

characterized by an

angle θ formed by the

line from the slits to this

position, relative to the

perpendicular line. Note

that if the distance from

the slits to the screen is

labelled L, then y = L

tan θ.

Double slit Interference

Interference pattern due to a double slit will have dark and bright fringes due to destructive

and constructive interference of the waves coming from the two slits. When two slits separated by a

distance d produces bright spots on the screen centered at positions where the following

constructive interference criterion is satisfied:

d sin θ = n λ , where n is an integer.

For the experiments we will be doing, the angle θ is less than 10 degrees, and sin θ  tan θ =

y/L. Substituting y/L for sin θ in the above equation, we get

nL

y d = ,

or, rearranging,

d

n L y

 =. (1)

d

D

Fig. 1. Geometrical arrangement of slits and screen in experiment.

Single-slit diffraction

Diffraction pattern formed by a single will have a wide and bright pattern at the center with

alternate dark and bright fringes with diminishing intensity on both sides. The pattern is formed is

because of the superposition of the waves coming from all points in the slit. A single slit with slit

width D will produce dark regions on the screen at positions where the following destructive

interference criterion is satisfied.

D sinθ = n λ , where n is a non-zero integer.

Again, for our experiments sin θ  tan θ = y/L. Substituting y/L for sinθ in the above

equation, we get

nL

y D = ,

or, rearranging,

D

n L y

 =. (2)

Since the slits have a finite slit width in double slit experiment, it is thoughtful idea to look

back to double slit interference pattern. Thus, practically, double slit interference pattern will have

single slit effect. This is because each of the individual slits of the double slits act as a single slit

that produces single slit diffraction. As you will observe in this experiment, the real interference

pattern will have interference pattern enveloped in diffraction pattern with evenly-spaced narrower

bright fringes grouped in a few broader bands with decreasing intensity on both sides. The broader

bands are because of the single slit diffraction. We can determine the slit width from the broader

bands.

Apparatus

Various slits in the plastic slits bar of the diffraction assembly; lasers (to be shared and students can

move from station to station when it is time to use a different color laser); mount that holds

laser; black wooden target board; paper; (tape: if needed); meter stick; ruler.

Description of Apparatus

The first three items listed in the apparatus section are shown in the figure 2. You will use

lasers of different colors. Laser gives a monochromatic and coherent light. You will use a plastic

slits bar that you slide in the diffraction assembly to select single slits of different width and then

gently slide the plastic slits bar to select double slit with different slit width and slit separation.

Fig. 2. Experimental set up for interference experiment with a laser and slit(s).

Double slit selection

Single slit selection

Laser Plastic Slit slide bar

Diffraction slits assembly

Part II. Double slit

In this part of the lab, you will perform the same experiment as in Part I but with double

slits.

  1. Gently slide the plastic slits bar so that you select the double slit with slits’ width D = 0.

mm and distance between slits (that is; slits separation), d = 0.25 mm. Turn on the He-Ne

laser. Infront of the screen, place the target wooden board, with a piece of paper securely

taped to it, at a distance, L, of about two meters from the slit assembly. Measure L. You

should see an interference pattern that looks something similar to Fig 4. You can gently

adjust the laser sideways from rear (or front) to get a clear pattern centered on the screen and

paper sheet.

  1. The closely-spaced bright spots represent the double slit interference pattern. The larger-

scale pattern in which a wide central set of spots is bright, after which the spots alternately

fade and recover, represents the interference pattern of the individual slits.

  1. First characterize the double slit pattern. Mark on the paper the location of a central group of

BRIGHT spots, as shown by the black marks at the top of the figure. Stay within the bright

central portion of the pattern, before the spots become difficult to see due to the dark regions

of the single-slit pattern. In your case, for best accuracy, you should make your marks

directly on top of the spots.

  1. Next characterize the single-slit pattern. Mark on the paper the location of the DARK places

in the pattern, as shown by the gray marks at the bottom of the figure. In your case, for best

accuracy, you should make your marks directly on top of the dark spots. Use a different

color pen so that you can clearly distinguish these marks from your marks in step 3.

  1. Remove the paper from the target board.
  2. With your ruler measure the distance  between the furthest-separated marks in your two-slit

interference pattern. Also record n, the number of spaces between these furthest-separated

marks. For example, in the figure above, there are eleven marks, so n is ten.

  1. With your ruler measure the distance  between the second order dark on both sides from

the center. (If you can observe higher order dark, you can use them for better accuracy).

These marks are not evenly spaced: the central-most marks have roughly twice the

separation as other nearest-neighbor separations.

Fig. 4. Photograph of a double slit interference pattern on a screen using a red

laser

  1. Now, gently slide the plastic slits bar to select the double slit with slits’ width D = 0.08 mm

and slits separation, d = 0.25 mm and repeat the previous steps. Record your results in Table

  1. Save this piece of paper with your marks as part of your lab data, to be submitted in your

report.

  1. Obtain the wavelength of your particular laser from your instructor. Write down the slit

width, D and slits’ separation, d that are marked next to the slits that we selected from the

plastic slits’ bar.

Part III. Double slit interference with different color lasers

  1. Repeat double slit interference experiment, Part II, with different color lasers. There are

several different color lasers placed at different stations. You may have go to that particular

station or switch to a new laser in your station. Follow the steps 1-3 only in Part II with

one pattern of the double slit.

Computation

Part I: Single Slit Diffraction. From the data recorded in Table 1 and for the first single slit we

used with slit width, D = 0.04 mm, determine the distance from the center of the pattern to

different order dark from your  values. Since  is the distance between the dark fringes on both

sides from the center, yn = n/2. Determine yn for your pattern. Using these values, your

measured L, and known slit width D, calculate the wavelength of the laser λ from Eq. 2,

D

L

yn n

Use n = 1, 2, 3,…. for first, second, third,…..order dark fringes. Compare this value with

the value of the wavelength given by calculating a percent error.

Repeat this calculation for the results obtained by using Pattern obtained with the second

single slit we used of D = 0.08 mm.

Part II: Double Slit Interference (with inherent single slit diffraction)

(a) Double slit pattern

From the data recorded in Table 2, and for the first double slit we used which had slits

width, D = 0.04 mm and slits separation, d = 0.25 mm, determine the distance between two

neighboring spots in the double slit interference pattern: y = /n. This y is the distance between

the central spot and its neighboring spot, and by setting n = 1 in equation (1) above, we see that

this y should obey

d

L

y

Use this equation, your y from above, your measured L, and your known d (the slit

separation) to calculate the wavelength of the laser light, λ. Compare this value with the

wavelength provided by your instructor and calculate a percent error.

Repeat this calculation for the results obtained by using the second pattern that we

obtained for the second double slit which had slits width, D = 0.08 mm & slits separation d =

0.25 mm.

Data Sheet

Date experiment performed: Name of the group members:

Table 1. Single slit

Distance from the slit to the paper sheet attached to wooden board in front of screen (L) =

Slit

position

 1  2  3 y 1

L

yD

1  =

y 2

L

yD

2

y 3

L

yD

3

Pattern for

single slit

with D =

0.04 mm

Pattern for

single slit

with D=

0.08 mm

Average  =

 error =

Table 2. Double slits

Distance from the slit to the paper sheet attached to wooden board in front of screen (L) =

Double slit pattern Inherent Single-slit pattern

Slit position (^)  (meters) n (^) y = /n

L

yd

(meters)

y2 = /

2

y

L

D

Pattern for

double slit with

D = 0.04 mm &

d = 0.25 mm

Pattern for

double slit with

D = 0.08 mm &

d = 0.25 mm

Average  =  error for D = 0.04 mm:

 error =  error for D = 0.08 mm:

Table 3. Double slits in different colors

Distance between the slits (d) = Slit width (D) = Distance from the slit to the screen (L) =

Color of laser (^)  (meters) n (^) y = /n

L

yd

% error